string-formatting

I am looking for a neat way of converting a cell from Minutes:Seconds.Milliseconds to Seconds.Milliseconds i.e. 11.111 = 11.111 1:11.111 = 71.111 I have something in place at the moment but its a bit hacky and I am sure there must be some nice excel feature to do this for me :P Thanks! Do this: Place values 0:0:11.111 and 0:1:11.111 in cells B3 and B4 respectively. Now format it to account for the milliseconds... Select cells B3 and B4 , right click and choose Format Cells. In Custom, put the following in the text box labeled Type : [h]:mm:ss.000 Now on cell C3 put the following formula: =B3

I need to format a floating point number to x characters (6 in my case including the decimal point). My output also needs to include the sign of the number So given the inputs, here are the expected outputs 1.23456 => +1.2345 -12.34567 => -12.345 -0.123456 => -0.1234 1234.567 => +1234.5 Please assume there is always a decimal place before the last character. I.e. there will be no 12345.6 number input - the input will always be less than or equal to 9999.9 . I'm thinking this has to be done conditionally. Here's a transparent way to do it without format strings (except for "F"): static void

I want to use a statically defined template for URL building. I'm trying to use ES6 string interpolation feature for this var template = "http://example.com/?name=${name}&age=${age}"; var name = "John"; var age = "30"; var url = `${template}`; Expected result: http://example.com/?name=John&age=23 Actual result: http://example.com/?name= ${name}&age=${age} In case this can't be done with string interpolation is there any better method than String.prototype.replace like var url = template.replace(/\${name}/,"John").replace(/\${age}/, 23); pawel The variables are substituted at the moment of

What is the easiest way to pad a string with 0 to the left so that "110" = "00000110" "11110000" = "11110000" I have tried to use the format! macro but it only pads to the right with space: format!("{:08}", string); Shepmaster The fmt module documentation describes all the formatting options: Fill / Alignment The fill character is provided normally in conjunction with the width parameter. This indicates that if the value being formatted is smaller than width some extra characters will be printed around it. The extra characters are specified by fill , and the alignment can be one of the

Is it possible to localize numbers in String.format call the same way as NumberFormat.format does? I've expected it simply to use String.format(locale, "%d", number) but this doesn't return the same result as if using NumberFormat. For example: String.format(Locale.GERMAN, "%d", 1234567890) gives: "1234567890", while NumberFormat.getNumberInstance(Locale.GERMAN).format(1234567890) gives: "1.234.567.890" If it can't be done, what's recommended way for localizing text including numbers? From the documentation , you have to: supply a locale (as you are doing in your example) include the ',' flag

Is there any way to give printf a size_t without either casting it first or generating a compiler warning? (I always compile with -Wall .) printf("%zu", sizeof(whatever)); 来源： https://stackoverflow.com/questions/4150056/printf-for-size-t

I need to format a double value to one decimal place without it rounding. double value = 3.984568438706 string result = ""; What I have tried is: 1) result = value.ToString("##.##", System.Globalization.CultureInfo.InvariantCulture) + "%"; // returns 3.98% 2) result = value.ToString("##.#", System.Globalization.CultureInfo.InvariantCulture) + "%"; // returns 4% 3) result = value.ToString("##.0", System.Globalization.CultureInfo.InvariantCulture) + "%"; // returns 4.0% 4) (Following other suggestions) value = (value / 100); result = String.Format("{0:P1}", Math.Truncate(value * 10000) / 10000);