strftime

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I used : utctime = datetime.datetime(1601,1,1) + datetime.timedelta(microseconds = tup[5]) last_visit_time = "Last visit time:"+ utctime.strftime('%Y-%m-%d %H:%M:%S') But I have the time of 1601, so the error show: ValueError: year=1601 is before 1900; the datetime strftime() methods require year >= 1900 I used python2.7, how can I make it? Thanks a lot! 回答1: You can do the following: >>> utctime.isoformat() '1601-01-01T00:00:00.000050' Now if you want to have exactly the same format as above: iso = utctime.isoformat() tokens = iso.strip()

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a huge dataframe more than 100 mln rows. In that I have a date columns, unfortunately have improper formatted (mixed) date strings. Now I did convert it to datetime by: df['TRX_DATE'] = pd.to_datetime(df['TRX_DATE'],coerce=True) # without any error # Now i want to calculate week day from that date columns df['day_type'] = [x.strftime('%A') for x in d['TRX_DATE']] ###ValueError: month out of range If it would a single field I can manage with dateutil parser. But in this case I am getting out of idea, how to handle that. Just intersted,

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Could you please help me how to format a struct timeval instance to human readable format like "2010-01-01 15:35:10.0001"? 回答1: Convert the tv_sec using localtime , and strftime , then append tv_usec part. 回答2: You need to manually append the microseconds part, since it's not in the struct tm that strftime () deals with. Here's a snippet: struct timeval tv; time_t nowtime; struct tm *nowtm; char tmbuf[64], buf[64]; gettimeofday(&tv, NULL); nowtime = tv.tv_sec; nowtm = localtime(&nowtime); strftime(tmbuf, sizeof tmbuf, "%Y-%m-%d %H:%M:%S",

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Recently i changed my database from sqlite3 to mysql.When i ran my project i am getting this error in one of the file which is using this query. date = Date.today + 1 @employees = Employee.where("status = ? AND strftime('%d/%m', date_of_birth) = ?", "Active" , date.strftime('%d/%m') ActionView::Template::Error (Mysql2::Error: FUNCTION hrms_development.strftime does not exist: SELECT COUNT(*) FROM `employees` WHERE (status = 'Active' AND strftime('%d/%m', date_of_birth) = '28/03')): 210: 211: 212: 213: 214: 215: 216: app/views/home/_group

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have a large project about static source code analysis, and everything compiles successfully, except for one thing. I have provided the error message in the title. The point that confuses me is that it gives an error message saying unsafe. I thought it should be just warning, not an error. By the way, I'm using Visual Studio 2012. Here is the part of the code where I get the error, in ctime. If someone can help me overcome this error, I would be glad. void CppCheckExecutor :: reportProgress ( const std :: string & filename ,

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I store some time values in sqlite in %H:%M string format (for example "15:43"), but I would like to get them out formatted in 12 hour format with AM/PM indicators (for example "3:43 PM"). Is this possible with sqlite (and if so, how), or do I need to do this in my application code? 回答1: Unless you extend sqlite with your own custom function , you'll have to do this is code. sqlite's strftime date formatting function only supports a small subset of its C counterpart, insufficient for your problem. sqlite also lacks a selection construct like

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Here is my code... from datetime import datetime def userLogin() : Name = input("Please type your Username ") if Name == "User1" : print ("Welcome User1! " + timeIs()) if Name == "User2" : print ("Welcome User2! The time is " + datetime.strftime(datetime.now(), '%H:%M')) if Name == "User3" : print ("Welcome User3! The time is " + datetime.strftime(datetime.now(), '%H:%M')) def timeIs() : print ("The time is " + datetime.strftime(datetime.now(), '%H:%M')) print (userLogin()) As you can see, for User2 and User3 I have set out the full

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Here is my code... from datetime import datetime def userLogin() : Name = input("Please type your Username ") if Name == "User1" : print ("Welcome User1! " + timeIs()) if Name == "User2" : print ("Welcome User2! The time is " + datetime.strftime(datetime.now(), '%H:%M')) if Name == "User3" : print ("Welcome User3! The time is " + datetime.strftime(datetime.now(), '%H:%M')) def timeIs() : print ("The time is " + datetime.strftime(datetime.now(), '%H:%M')) print (userLogin()) As you can see, for User2 and User3 I have set out the full