stop-words

Get rid of stopwords and punctuation

冷暖自知 提交于 2019-11-29 01:10:21
问题 I'm struggling with NLTK stopword. Here's my bit of code.. Could someone tell me what's wrong? from nltk.corpus import stopwords def removeStopwords( palabras ): return [ word for word in palabras if word not in stopwords.words('spanish') ] palabras = ''' my text is here ''' 回答1: Your problem is that the iterator for a string returns each character not each word. For example: >>> palabras = "Buenos dias" >>> [c for c in palabras] ['B', 'u', 'e', 'n', 'a', 's', ' ', 'd', 'i', 'a', 's'] You

NLTK and Stopwords Fail #lookuperror

╄→гoц情女王★ 提交于 2019-11-28 18:18:43
问题 I am trying to start a project of sentiment analysis and I will use the stop words method. I made some research and I found that nltk have stopwords but when I execute the command there is an error. What I do is the following, in order to know which are the words that nltk use (like what you may found here http://www.nltk.org/book/ch02.html in section4.1): from nltk.corpus import stopwords stopwords.words('english') But when I press enter I obtain ---------------------------------------------

How to remove list of words from a list of strings

人走茶凉 提交于 2019-11-28 18:02:47
Sorry if the question is bit confusing. This is similar to this question I think this the above question is close to what I want, but in Clojure. There is another question I need something like this but instead of '[br]' in that question, there is a list of strings that need to be searched and removed. Hope I made myself clear. I think that this is due to the fact that strings in python are immutable. I have a list of noise words that need to be removed from a list of strings. If I use the list comprehension, I end up searching the same string again and again. So, only "of" gets removed and

Tokenizer, Stop Word Removal, Stemming in Java

时间秒杀一切 提交于 2019-11-28 17:05:20
I am looking for a class or method that takes a long string of many 100s of words and tokenizes, removes the stop words and stems for use in an IR system. For example: "The big fat cat, said 'your funniest guy i know' to the kangaroo..." the tokenizer would remove the punctuation and return an ArrayList of words the stop word remover would remove words like "the", "to", etc the stemmer would reduce each word the their 'root', for example 'funniest' would become funny Many thanks in advance. jitter AFAIK Lucene can do what you want. With StandardAnalyzer and StopAnalyzer you can to the stop

Removing stop words from single string

↘锁芯ラ 提交于 2019-11-28 12:35:46
My query is string = 'Alligator in water' where in is a stop word. How can I remove it so that I get stop_remove = 'Alligator water' as output. I have tried it with ismember but it returns integer value for matching word, I want to get the remaining words as output. in is just an example, I'd like to remove all possible stop words. Use this for removing all stop-words. Code % Source of stopwords- http://norm.al/2009/04/14/list-of-english-stop-words/ stopwords_cellstring={'a', 'about', 'above', 'above', 'across', 'after', ... 'afterwards', 'again', 'against', 'all', 'almost', 'alone', 'along',

ignoring mysql fulltext stopwords in query

霸气de小男生 提交于 2019-11-28 11:08:34
I'm building a search for a site, which utilizes a fulltext search. The search itself works great, that's not my problem. I string together user provided keywords (MATCH... AGAINST...) with AND's so that multiple words further narrow the results. Now, I know that certain stop words aren't indexed, and that's fine with me I don't really want to use them as selection criteria. But, if a stopword is provided in the keyword set (by the user), it kills all the results (as expected) even if the word actually is in a certain text block. My question: is there any way to check to see if a certain word

Full text search does not work if stop word is included even though stop word list is empty

北城余情 提交于 2019-11-28 06:59:05
I would like to be able to search every word so I have cleared the stop word list. Than I have rebuilt the index. But unfortunately if I type in a search expression with stop word in it it still returns no row. If I leave out just the stop word I do get the results. E.g. "double wear stay in place" - no result, "double wear stay place" - I get the results that actually contain "in" as well. Does anyone know why this can be? I am using SQL Server 2012 Express. Thanks a lot! Meanwhile I have managed to solve the issue. The problem was that I had my own stop list which was indeed empty but my

SQL 2008: Turn off Stop Words for Full Text Search Query

假装没事ソ 提交于 2019-11-28 06:49:21
I'm having quite a bit of difficulty finding a good solution for this: Let's say I have a table of "Company", with a column called "Name". I have a full-text catalog on this column. If a user searched for "Very Good Company", my query would be: SELECT * FROM Company WHERE CONTAINS(Name, '"Very" AND "Good" AND "Company"') The problem is in this example, the word "Very" shows up in the standard list of stopwords: SELECT ssw.* FROM sys.fulltext_system_stopwords ssw WHERE ssw.language_id = 1033; Resulting in the query returning with no rows, even though there is a row with the name "Very Good

Adding words to scikit-learn's CountVectorizer's stop list

…衆ロ難τιáo~ 提交于 2019-11-28 05:52:00
Scikit-learn's CountVectorizer class lets you pass a string 'english' to the argument stop_words. I want to add some things to this predefined list. Can anyone tell me how to do this? According to the source code for sklearn.feature_extraction.text , the full list (actually a frozenset , from stop_words ) of ENGLISH_STOP_WORDS is exposed through __all__ . Therefore if you want to use that list plus some more items, you could do something like: from sklearn.feature_extraction import text stop_words = text.ENGLISH_STOP_WORDS.union(my_additional_stop_words) (where my_additional_stop_words is any

“Stop words” list for English? [closed]

孤人 提交于 2019-11-28 03:43:04
I'm generating some statistics for some English-language text and I would like to skip uninteresting words such as "a" and "the". Where can I find some lists of these uninteresting words? Is a list of these words the same as a list of the most frequently used words in English? update: these are apparently called "stop words" and not "skip words". The magic word to put into Google is "stop words". This turns up a reasonable-looking list . MySQL also has a built-in list of stop words , but this is far too comprehensive to my tastes. For example, at our university library we had problems because