static

Django media files not showing with Debug = False on production - Django 1.10

由 孤街浪徒 提交于 2021-01-02 05:46:11
问题 I currently have two kind of files static files and media files.The static files contain my css,js and other static content. The media files contain stuff that the user uploads.The static folder is right next to the media folder.Now on my deployed machine. If I set the DEBUG = False my static files are presented just fine however my media content is never displayed. I get a 404 not found error. My quuestion is how do I display media content in production environment when DEBUG = False. With

Flutter Instance member ‘{0}’ can’t be accessed using static access

由 倖福魔咒の 提交于 2020-12-30 06:18:24
问题 I am passing variables from one activity to another in flutter but getting the error "Instance member ‘latitude’ can’t be accessed using static access" I need it converted in that block so I can assign it to a static URL. class Xsecond extends StatefulWidget { final double latitude; final double longitude; Xsecond(this.latitude, this.longitude, {Key key}): super(key: key); @override _Xsecond createState() => _Xsecond(); } class _Xsecond extends State<Xsecond> { static String lat = Xsecond

Flutter Instance member ‘{0}’ can’t be accessed using static access

由 拥有回忆 提交于 2020-12-30 06:18:07
问题 I am passing variables from one activity to another in flutter but getting the error "Instance member ‘latitude’ can’t be accessed using static access" I need it converted in that block so I can assign it to a static URL. class Xsecond extends StatefulWidget { final double latitude; final double longitude; Xsecond(this.latitude, this.longitude, {Key key}): super(key: key); @override _Xsecond createState() => _Xsecond(); } class _Xsecond extends State<Xsecond> { static String lat = Xsecond

How can I assure a class to have a static property by using interface or abstract?

由 a 夏天 提交于 2020-12-30 04:49:23
问题 I have one abstract class -let's say myBase. And I want all the classes derived from myBase to have one static field called public static List<string> MyPArameterNames { get {return _myParameterNames;} } So, every child class can tell what parameter names it uses; I want static because I do not want to create an instance just for this. How can I achieve this? 回答1: You can't do that. Interfaces, abstract, etc. cannot apply to static members. If you want to accomplish this, you will have to

How can I assure a class to have a static property by using interface or abstract?

由 你离开我真会死。 提交于 2020-12-30 04:48:53
问题 I have one abstract class -let's say myBase. And I want all the classes derived from myBase to have one static field called public static List<string> MyPArameterNames { get {return _myParameterNames;} } So, every child class can tell what parameter names it uses; I want static because I do not want to create an instance just for this. How can I achieve this? 回答1: You can't do that. Interfaces, abstract, etc. cannot apply to static members. If you want to accomplish this, you will have to

C++ - How to access private members of a class, from a static function of the same class?

由 时光总嘲笑我的痴心妄想 提交于 2020-12-26 05:01:42
问题 What I have: So I have a class with a private member, and a static function. The function must really be static and I can't change that. What I want: I need to access, from the static function, the private member. Any ideas? :) Please check the code bellow: class Base { private: int m_member; public: Base() : m_member(0) {}; ~Base() {}; static void key_callback(GLFWwindow* window, int key, int scancode, int action, int mode); /* This must really be static because it is coming from C */ };

How does Out variable which is defined static and assigned null in System class can access non-static methods of PrintStream class. [duplicate]

由 杀马特。学长 韩版系。学妹 提交于 2020-12-13 04:20:05
问题 This question already has answers here : System.out is declared as static final and initialized with null? [duplicate] (2 answers) Closed 3 years ago . As to access the methods of PrintStram class an object must be created, so how the out variable is able to access those methods when it is assigned null. public final static PrintStream out = null; This is the declaration in System class. I tried to write the similar code but then it gives NullPointerException. My code is given below. class

“Undefined reference” to declared C++ static member variable [duplicate]

由 青春壹個敷衍的年華 提交于 2020-12-12 06:17:12
问题 This question already has answers here : Undefined reference to static class member (7 answers) Closed 4 years ago . I have started programming with Java, I just achieved which I consider as a "good" level in matter of language knowledge. For fun I decided to start programming using C++, I'm fairly new to this language but I'm a fast learner and I think it's not that far from Java. I've created a test class which has a value and a name as attributes, and an objects counter as a global

静态代码块 非静态代码块 static

由 人盡茶涼 提交于 2020-12-04 14:19:39
静态代码块 非静态代码块 static 先来看看看它们的形式： static{ System.out.println(“静态代码块”)； } ｛ System.out.println(“非静态代码块”)； ｝ 相同点：都是在JVM加载类时且在构造方法执行之前执行，在类中都可以定义多个，一般在代码块中对一些 static变量进行赋值。 不同点：静态代码块在非静态代码块之前执行（ 静态代码块--》非静态代码块--》构造方法 ）。 静态代码块只 在第一次new执行一次 ，之后不在执行，而非静态代码块在 每new一次就执行一次 。非 静态代码块可以在普通方法中定义（个人感觉作用不大）;而静态代码块不行。 静态代码块与静态方法的比较？ 一般情况下,如果有些代码必须 在项目启动的时候就执行 的时候,需要使用静态代码块,这种代码是主动执行的;需要在项目启动的时候就初始化,在 不创建对象的情况下,其他程序来调用的时候, 需要使用静态方法,静态方法在类加载的时候 就已经加载 可以用类名直接调用 比如main方法就必须是静态的 这是程序入口。两者的区别就是:静态代码块是自动执行的; 静态方法是被调用的时候才执行的。 package com.wangjia; class Parent{ static String name = "hello"; { System.out.println("parent

Linking static library with -l flag

由 二次信任 提交于 2020-11-28 03:07:21
问题 How can I have my makefile compile with the -l flag? I have a makefile that looks like myLibrary: gcc -c myLibrary.c -o myLibrary.o ar cr libmyLibrary.a myLibrary.o and then I compile my main program with main: gcc -g -c -o main.o main.c gcc main.o -o main libmyLibrary.a The above makefile works, but if I want to replace libmyLibrary.a with -lmyLibrary I get an error. Shouldn't both be working the same? 回答1: Here is a rudimentary, unrealistic makefile that will make the static library
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