static-methods

How do I access an instance variable inside a BindingAdapter when using Android Data Binding?

不羁的心 提交于 2019-11-29 14:20:10
So I'm using this popular data binding code snippet to load in image into imageview of list items by passing in URL: <ImageView android:layout_width="match_parent" android:layout_height="150dp"" app:imageUrl="@{movie.imageUrl}" /> The Binding Adapter: class Movie{ boolean isLoaded; @BindingAdapter({"bind:imageUrl"}) public static void loadImage(final ImageView view, String imageUrl) { Picasso.with(view.getContext()) .load(imageUrl) .into(view, new Callback.EmptyCallback() { @Override public void onSuccess() { //set isLoaded to true for the listview item // but cannot access boolean isLoaded as

I am confused about using static method in Multithreading java?

有些话、适合烂在心里 提交于 2019-11-29 13:38:52
问题 something about static: instances of class share static method the similar questions: Java: when to use static methods What does the 'static' keyword do in a class? I am confusing about: static method just have only one memory block? if i use static method in multithreading, will it block? 回答1: I am confusing about: static method just have only one memory block? if i use static method in multithreading, will it block? The static keyword in Java simply means "without regard or knowledge of any

How can I run a static initializer method in C# before the Main() method?

白昼怎懂夜的黑 提交于 2019-11-29 13:10:12
Given a static class with an initializer method: public static class Foo { // Class members... internal static init() { // Do some initialization... } } How can I ensure the initializer is run before Main() ? The best I can think of is to add this to Foo : private class Initializer { private static bool isDone = false; public Initializer() { if (!isDone) { init(); isDone = true; } } } private static readonly Initializer initializer = new Initializer(); Will this work or are there some unforeseen caveats? And is there any better way of doing this? Simply do the initialization inside a static

ES6: this within static method

眉间皱痕 提交于 2019-11-29 12:09:25
Let's say I have two ES6 classes like this: class Base { static something() { console.log(this); } } class Derived extends Base { } And then I make a call like this: Derived.something(); Note that I am making a call to a static method defined on the super class via sub class. This does not give me errors. It prints [Function: Derived] So accessing this within a static method seems to work here. I need a common static method for all sub-classes of a super class and I need to be able to know what sub-class is calling this method. Now my question is whether using this within a static method is

Struts 2 refactoring code to avoid OGNL static method access

大兔子大兔子 提交于 2019-11-29 11:56:29
Struts 2, 2.3.20 mentioned that Support for accessing static methods from expression will be disabled soon, please consider re-factoring your application to avoid further problems! We have used OGNL static calls in validators: @ExpressionValidator( expression = "@foo.bar@isValidAmount(amount)", key = "validate.amount.is.not.valid"), Also we used it in tags <s:set var="test" value="@foo.bar@sampleMethod(#attr.sampleObject.property1)" /> Well, what is the best way to refactor above two usages ?! In your code you are using a static method call. The best way is to create a method in the action

How to call C++ static method

霸气de小男生 提交于 2019-11-29 11:16:51
问题 Is it possible to return an object from a static method in C++ like there is in Java? I am doing this: class MyMath { public: static MyObject calcSomething(void); private: }; And I want to do this: int main() { MyObject o = MyMath.calcSomething(); // error happens here } There are only static methods in the MyMath class, so there's no point in instantiating it. But I get this compile error: MyMath.cpp:69: error: expected primary-expression before '.' token What am I doing wrong? Do I have to

Pointers to static methods in Python

风流意气都作罢 提交于 2019-11-29 11:03:15
Why is it that in the following code, using a class variable as a method pointer results in unbound method error, while using an ordinary variable works fine: class Cmd: cmd = None @staticmethod def cmdOne(): print 'cmd one' @staticmethod def cmdTwo(): print 'cmd two' def main(): cmd = Cmd.cmdOne cmd() # works fine Cmd.cmd = Cmd.cmdOne Cmd.cmd() # unbound error !! if __name__=="__main__": main() The full error: TypeError: unbound method cmdOne() must be called with Cmd instance as first argument (got nothing instead) glglgl I like to view this behaviour from the "bottom up". A function in

PHP static method call with variable class name and namespaces

断了今生、忘了曾经 提交于 2019-11-29 09:52:39
I'm trying to call a static method for a namespaced class from another class with the same namespace. But the other class' name is contained in a variable : <?php namespace MyApp\Api; use \Eloquent; class Product extends Eloquent { public static function find($id) { //.... } public static function details($id) { $product = self::find($id); if($product) { $type = $product->type; // 'Book' $product = $type::find($product->id); return $product; } } } Here is the Book class : <?php namespace MyApp\Api; use \Eloquent; class Book extends Eloquent { public static function find($id) { //.... } } My

How do I make my scala method static?

こ雲淡風輕ζ 提交于 2019-11-29 06:57:52
I have a class class MyClass { def apply(myRDD: RDD[String]) { val rdd2 = myRDD.map(myString => { // do String manipulation } } } object MyClass { } Since I have a block of code performing one task (the area that says "do String manipulation" ), I thought I should break it out into it's own method. Since the method is not changing the state of the class, I thought I should make it a static method. How do I do that? I thought that you can just pop a method inside the companion object and it would be available as a static class, like this: object MyClass { def doStringManipulation(myString:

Are static methods in Java always resolved at compile time?

本秂侑毒 提交于 2019-11-29 06:51:39
Are static methods in Java always resolved at compile time? Roee Adler Yes, it is thoroughly investigated and explained in this thread on Sun's forums: New To Java - No late binding for static methods Several quotes: When the compiler compiles that class it decides at compile time which exact method is called for each static method call (that's the big difference to non-static method calls: the exact method to be called is only decided at runtime in those cases). Calling static methods only ever depends on the compile-time type on which it is called. Yes, but if the static method has been