Do string literals that end with a null-terminator contain an extra null-terminator?
For example: char a[] = "abc\0"; Does standard C say that another byte of value 0 must be appended even if the string already has a zero at the end? So, is sizeof(a) equal to 4 or 5? All string literals have an implicit null-terminator, irrespective of the content of the string. The standard (6.4.5 String Literals) says: A byte or code of value zero is appended to each multibyte character sequence that results from a string literal or literals. So, the string literal "abc\0" contains the implicit null-terminator, in addition to the explicit one. So, the array a contains 5 elements. 来源: https:/