stack-overflow

Android TableLayout Error

家住魔仙堡 提交于 2020-01-03 00:54:25
问题 I have made TableLayout. In there statically define table row & if i put Button , it throw error.It may be the small error, i spend more time, but could find out the solution... Here this is my code.. <ScrollView android:layout_width="fill_parent" android:scrollbarStyle="outsideInset" android:scrollbarThumbVertical="@drawable/scrollbar_vertical_thumb" android:scrollbarTrackVertical="@drawable/scrollbar_vertical_track" android:scrollbarSize="5dp" android:scrollbarFadeDuration="0" android

Kotlin recursion stack overflow

假如想象 提交于 2020-01-02 12:41:05
问题 I have written this recursive function in Kotlin: fun recursive(target: String, population: Population, debugFun: (String) -> Unit) : Population { if (population.solution(target).toString() == target) { return population } debugFun.invoke(population.solution(target).toString()) return recursive(target, population.evolve(target), debugFun) } It will run an indeterminate amount of times (because I'm using randomness to converge on solution in evolutionary algorithm). I am frequently getting

Does a program stack truly overflow?

眉间皱痕 提交于 2020-01-02 09:29:11
问题 Won't the processor cause a TRAP to the operating system if the stack size limit is reached(thus preventing a stackoverflow :P) 回答1: I believe Windows does have a stack that grows when you reach the end. In the Visual Studio compiler the code responsible for this is in the chkstk.obj module. Since this code is open-source I can post it here: ;*** ;_chkstk - check stack upon procedure entry ; ;Purpose: ; Provide stack checking on procedure entry. Method is to simply probe ; each page of memory

What is the order of magnitude of the maximum number of recursive calls in C++?

吃可爱长大的小学妹 提交于 2020-01-02 07:53:43
问题 I have a recursive function which calls itself a very large number of times given certain inputs - which is exactly what it should do. I know my function isn't infinitely looping - it just gets to a certain number of calls and overflows. I want to know if this is a problem with putting too much memory on the stack, or just a normal restriction in number of calls. Obviously it's very hard to say a specific number of calls which is the maximum, but can anybody give me a rough estimate of the

Haskell foldl and stack overflow?

蹲街弑〆低调 提交于 2020-01-02 06:05:52
问题 I read a posting claims foldl may occur stack overflow easily. And the posting sample code was: maximum [1..1000000] The code doesn't overflown in my machine. However it can vary by environment. I increased number like this: maximum [1..1000000000] it caused hard disk swapping, so I have to stop evaluation. Sample code is not important. Is it really occur stack overflow? Or just an old days story? 回答1: Some points Recursive function take stack space in each call, so deeply nested calls will

Haskell foldl and stack overflow?

五迷三道 提交于 2020-01-02 06:04:20
问题 I read a posting claims foldl may occur stack overflow easily. And the posting sample code was: maximum [1..1000000] The code doesn't overflown in my machine. However it can vary by environment. I increased number like this: maximum [1..1000000000] it caused hard disk swapping, so I have to stop evaluation. Sample code is not important. Is it really occur stack overflow? Or just an old days story? 回答1: Some points Recursive function take stack space in each call, so deeply nested calls will

Haskell foldl and stack overflow?

一世执手 提交于 2020-01-02 06:03:11
问题 I read a posting claims foldl may occur stack overflow easily. And the posting sample code was: maximum [1..1000000] The code doesn't overflown in my machine. However it can vary by environment. I increased number like this: maximum [1..1000000000] it caused hard disk swapping, so I have to stop evaluation. Sample code is not important. Is it really occur stack overflow? Or just an old days story? 回答1: Some points Recursive function take stack space in each call, so deeply nested calls will

java.lang.StackOverflowError in android 4.0 and not in android 3.0

不打扰是莪最后的温柔 提交于 2020-01-01 15:09:25
问题 01-31 12:52:53.020: E/AndroidRuntime(10957): FATAL EXCEPTION: main 01-31 12:52:53.020: E/AndroidRuntime(10957): java.lang.StackOverflowError 01-31 12:52:53.020: E/AndroidRuntime(10957): at android.graphics.Paint.getTextRunAdvances(Paint.java:1711) 01-31 12:52:53.020: E/AndroidRuntime(10957): at android.text.TextLine.handleText(TextLine.java:749) 01-31 12:52:53.020: E/AndroidRuntime(10957): at android.text.TextLine.handleRun(TextLine.java:972) 01-31 12:52:53.020: E/AndroidRuntime(10957): at

How do I avoid changing the Stack Size AND avoid getting a Stack Overflow in C#

点点圈 提交于 2020-01-01 09:33:43
问题 I've been trying to find an answer to this question for a few hours now on the web and on this site, and I'm not quite there. I understand that .NET allocates 1MB to apps, and that it's best to avoid stack overflow by recoding instead of forcing stack size. I'm working on a "shortest path" app that works great up to about 3000 nodes, at which point it overflows. Here's the method that causes problems: public void findShortestPath(int current, int end, int currentCost) { if (!weight

How do I avoid changing the Stack Size AND avoid getting a Stack Overflow in C#

给你一囗甜甜゛ 提交于 2020-01-01 09:33:14
问题 I've been trying to find an answer to this question for a few hours now on the web and on this site, and I'm not quite there. I understand that .NET allocates 1MB to apps, and that it's best to avoid stack overflow by recoding instead of forcing stack size. I'm working on a "shortest path" app that works great up to about 3000 nodes, at which point it overflows. Here's the method that causes problems: public void findShortestPath(int current, int end, int currentCost) { if (!weight