sql-order-by

I have table create table big_table ( id serial primary key, -- other columns here vote int ); This table is very big, approximately 70 million rows, I need to query: SELECT * FROM big_table ORDER BY vote [ASC|DESC], id [ASC|DESC] OFFSET x LIMIT n -- I need this for pagination As you may know, when x is a large number, queries like this are very slow. For performance optimization I added indexes: create index vote_order_asc on big_table (vote asc, id asc); and create index vote_order_desc on big_table (vote desc, id desc); EXPLAIN shows that the above SELECT query uses these indexes, but it's

I was always of the impression that a query with no specified 'Order by' rule, would order this by the results by what was specified within your where clause. For instance, my where clause states: WHERE RESULTS_I_AM_SEARCHING_FOR IN ITEM 1 ITEM 2 ITEM 3 I would have imagined that the results returned for items 1, 2 and 3 would be in the order specified in the where, however this is not the case. Does anyone know what order it sorts them in when not specified? Thanks and sorry for the really basic question! Damon marc_s If you don't specify an ORDER BY , then there is NO ORDER defined. The

After executing the following statement: SELECT Category FROM MonitoringJob ORDER BY CreationDate DESC I am getting the following values from the database: test3 test3 bildung test4 test3 test2 test1 but I want the duplicates removed, like this: bildung test4 test3 test2 test1 I tried to use DISTINCT but it doesn't work with ORDER BY in one statement. Please help. Important: I tried it with: SELECT DISTINCT Category FROM MonitoringJob ORDER BY CreationDate DESC it doesn't work. Order by CreationDate is very important. The problem is that the columns used in the ORDER BY aren't specified in the