split

问题 I want to remove the rows from the pandas dataframe, that contains the strings from a particular column whose length is greater than the desired length. For example: Input frame: X Y 0 Hi how are you. 1 An apple 2 glass of water 3 I like to watch movie Now, say I want to remove the rows which has the string of words with length greater than or equal to 4 from the dataframe. The desired output frame must be: X Y 1 An apple 2 glass of water Row with value 0,3 in column 'X' is removed as the

问题 Here is some dummy data I have created for my question. I have two questions regarding this: Why is split working by using str in the first part of the query and not in the second part? How come [0] is picking up the first row in part 1 and the first element from each row in part 2? chess_data = pd.DataFrame({"winner": ['A:1','A:2','A:3','A:4','B:1','B:2']}) chess_data.winner.str.split(":")[0] ['A', '1'] chess_data.winner.map(lambda n: n.split(":")[0]) 0 A 1 A 2 A 3 A 4 B 5 B Name: winner,

问题 I have a string that contains 128.82 . I want to split/separate them in 100 and 28.82 . var_dump(substr($kwh,0,3)); die(); It gives me 128 . How can I separate the 100 and 28.82 ? Any help would be highly appreciated Note: I am setting this because I have defined slabs. 1-100 , 101-150 , and so on. So I need to set them according to the slabs. The slabs may differ as it could be 1-50 , 51-100 , 100-150 , and so on. so I have to divide/split 128.82 like 50 for 1-50 , 50 for 51-100 and then 28

问题 I have a string that contains 128.82 . I want to split/separate them in 100 and 28.82 . var_dump(substr($kwh,0,3)); die(); It gives me 128 . How can I separate the 100 and 28.82 ? Any help would be highly appreciated Note: I am setting this because I have defined slabs. 1-100 , 101-150 , and so on. So I need to set them according to the slabs. The slabs may differ as it could be 1-50 , 51-100 , 100-150 , and so on. so I have to divide/split 128.82 like 50 for 1-50 , 50 for 51-100 and then 28

问题 I have the following dataset wherein, I have the person's ID, district and sub-district they live in along with the last date/time on which they uploaded data to the server. The variables "last_down_" contain the last date/time on which a person the uploaded data and are named in such a way that they show the date on which I had downloaded the data on the same. For example, "last_upload_2020-06-12" would mean I downloaded the data from the server on 12th June. For the below dataset, I would

问题 Suppose I have the text file like this: Apple#mango&banana@grapes The data needs to be split on multiple delimiters before performing the word count. How to do that? 回答1: Use split method: scala> "Apple#mango&banana@grapes".split("[#&@]") res0: Array[String] = Array(Apple, mango, banana, grapes) 回答2: If you just want to count words, you don't need to split. Something like this will do: val numWords = """\b\w""".r.findAllIn(string).length This is a regex that matches start of a word ( \b is a

问题 Suppose I have the text file like this: Apple#mango&banana@grapes The data needs to be split on multiple delimiters before performing the word count. How to do that? 回答1: Use split method: scala> "Apple#mango&banana@grapes".split("[#&@]") res0: Array[String] = Array(Apple, mango, banana, grapes) 回答2: If you just want to count words, you don't need to split. Something like this will do: val numWords = """\b\w""".r.findAllIn(string).length This is a regex that matches start of a word ( \b is a

问题 Suppose I have the text file like this: Apple#mango&banana@grapes The data needs to be split on multiple delimiters before performing the word count. How to do that? 回答1: Use split method: scala> "Apple#mango&banana@grapes".split("[#&@]") res0: Array[String] = Array(Apple, mango, banana, grapes) 回答2: If you just want to count words, you don't need to split. Something like this will do: val numWords = """\b\w""".r.findAllIn(string).length This is a regex that matches start of a word ( \b is a

问题 I want to read a file line by line, split each line by comma (,) and store the result in an array. How to do this in a bash shell script? Sample line in my comma separated file 123,2014-07-21 10:01:44,123|8119|769.00||456|S This should be the output after splitting: arr[0]=123 arr[1]=2014-07-21 10:01:44 arr[2]=123|8119|769.00||456|S 回答1: Use read -a to split each line read into array based from IFS. while IFS=, read -ra arr; do ## Do something with ${arr0]}, ${arr[1]} and ${arr[2]} ... done <

问题 I want to read a file line by line, split each line by comma (,) and store the result in an array. How to do this in a bash shell script? Sample line in my comma separated file 123,2014-07-21 10:01:44,123|8119|769.00||456|S This should be the output after splitting: arr[0]=123 arr[1]=2014-07-21 10:01:44 arr[2]=123|8119|769.00||456|S 回答1: Use read -a to split each line read into array based from IFS. while IFS=, read -ra arr; do ## Do something with ${arr0]}, ${arr[1]} and ${arr[2]} ... done <