splice

I'm trying to splice an image and then have a transition to next one something like this? Any suggestions on where to start from? Is it possible to splice the images into small tiles and animate them with UIView animations? Here is a sample . EDIT: '#define DESIRED_WIDTH 40 '#define DESIRED_HEIGHT 60 - (void)viewDidLoad { [super viewDidLoad]; UIImage *bigImage = [UIImage imageNamed:@"background_for_Manager_App.png"]; CGRect frame = CGRectMake(0.0, 0.0, DESIRED_WIDTH, DESIRED_HEIGHT); int widthCount = (bigImage.size.width / DESIRED_WIDTH); int heightCount = (bigImage.size.height / DESIRED

Hi I delete an object in an array using two approaches:- splice and filter. splice code here:- (this.myArray).splice((this.myArray).indexOf(myobject), 1); filter code here:- (this.myArray).filter(obj => obj !== myobject); Please tell us differences between both and which one is the best approach? Check this performance test out. It's has not that much to do with Angular, but more with JavaScript. If you're able just go for the fastest method available :) I think that the main difference here is: splice - lets you remove an element from this particular array filter - won't touch the input array

数组的本质 本质是一个对象 length属性：数组的长度，会自动变化，值为最大下标+1 连续下标的取值范围 1~ length-1 , 直接给length赋值可能会截断数组 下标 下标不连续的数组叫做 稀松数组 添加数组项 Array[Array.length] = 数据 数组.push(数据) 数组.unshift():向数组起始位置添加一个数据 数组.splice(下标，0，添加的数据)：从指定下标位置开始，删除0个，然后在该位置插入添加的数据，如果下标超过范围，则按照范围的边界处理 push unshift splice可以处理多个数据 删除数据 delete 数组[下标] ：不会改变下标，会导致稀松数组 数组.pop() ：删除数组的最后一项，该表达式返回最后一项的数据 数组.shift():删除第一项，返回第一项的值 数组.splice(下标，删除的个数):返回被删除的数据 数组.slice(起始位置下标，结束位置下标 )：从起始位置到结束位置之间的数据拿出来，得到一个新的数组，不会改变原来的数组； 结束为止下标取不到 不写结束下标，则直接取到末尾 下标是负数，从数组末尾开始 数组清空： 数组.splice(0,length) 数组.length = 0; 数组.indexOf(数据)：找到第一个下标，返回下标，没有找到则返回 -1 数组.lastIndexOf(数据)

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I did a test with c++ parallel quicksort program as below first with list as container then I moved to a generic container type, but it reported the captioned error. Can help with this? #include <iostream> // std::cout #include <future> // std::packaged_task, std::future #include <chrono> // std::chrono::seconds #include <thread> // std::thread, std::this_thread::sleep_for #include <list> #include <algorithm> #include <type_traits> #include <iterator> template<typename F, typename A> static std::future<typename std::result_of<F(A&&)>::type>

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: If I have an array of objects is there any way possible for the item to splice itself out of the array that contains it? For example: If a bad guy dies he will splice himself out of the array of active enemies. I probably sound crazy but that ability would simplify my code dramatically, so I hope for something cool =) 回答1: The way you would do it is as follows: var game_state = { active_enemies : [] }; function Enemy () { // Various enemy-specific things go here } Enemy . prototype . remove = function () { // NOTE: indexOf is not

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have for example this array (each number is singolar, no one duplicate) called pvalue : 1 2 3 15 20 12 14 18 7 8 (sizeof 10). I need for example to pop the value "15", and after this pvalue should be 1 2 3 20 12 14 18 7 8 (sizeof 9). How can do it? the pop() function take the value at the end of the array. I don't want this :) cheers EDIT for(i=0; i<pvalue.length; i++) { if(pvalue[i]==param) { ind=i; break; } } pvalue.splice(ind, 1); 回答1: You're looking for splice . Example: http://jsbin.com/oteme3 : var a, b; a = [1, 2, 3, 15, 20, 12, 14,

splice-删除 1 var arr = [1, 2, 3, 4, 5, 6]; 2 //删除 3 var delArr = arr.splice(1, 2) 4 console.log(arr); // => (4) [1, 4, 5, 6] 5 console.log(delArr); // => (2) [2, 3] splice-插入 1 var arr = [1, 2, 3, 4, 5, 6]; 2 //插入 3 var insertArr = arr.splice(1, 0, "x", "y") 4 console.log(arr); // => (8) [1, "x", "y", 2, 3, 4, 5, 6] 5 console.log(insertArr); // => [] splice-替换 1 var arr = [1, 2, 3, 4, 5, 6]; 2 // 替换 3 var replaceArr = arr.splice(1, 2, "x", "y", "z") 4 console.log(arr); // => (7) [1, "x", "y", "z", 4, 5, 6] 5 console.log(replaceArr); // => (2) [2, 3] 综合对比： var arr = [1, 2, 3, 4, 5, 6]; //删除 var