socketserver

I have a problem with a Python script on my rpi. If I create a process object, it starts automatically and blocks everything else. I want it to run in the background, and to be able to start it by calling the start() method. network_manager.py: import socketserver class NetworkManagerHandler(socketserver.StreamRequestHandler): def handle(self): print("Got some Data!") class NetworkManagerServer(socketserver.ForkingMixIn, socketserver.TCPServer): pass core.py: import multiprocessing from network_manager import NetworkManagerServer, NetworkManagerHandler HOST, PORT = "100.0.0.1", 11891 network

I've created a simple test app (Python 2.6.1) that runs a ThreadingTCPServer, based on the example here . If the client sends a command "bye" I want to shut down the server and exit cleanly from the application. The exit part works OK, but when I try to re-run the app, I get: socket.error: [Errno 48] Address already in use I tried the solution given here for setting the socket options but that didn't seem to help. I've tried various ways to close the server down, but always get the same error. Any idea what I'm doing wrong? import SocketServer import socket import sys import threading import

I was trying to make an http proxy using BaseHttpServer which is based on SocketServer which got 2 asynchronous Mixins (ThreadingMixIn and ForkingMixIn) the problem with those two that they work on each request (allocate a new thread or fork a new subprocess for each request) is there a Mixin that utilize a pool of let's say 4 subprocesses and 40 threads in each so requests get handled by those already created threads ? because this would be a big performance gain and I guess it would save some resources. You could use a pool from concurrent.futures (in stdlib since Python 3.2): from

I'm trying to create a simple client/server application and thus I am experimenting with sockets in PHP. Now I have a simple client in C# wich connects to the server well, but i can only connect one client at once to this server (I found this code sample online and tweaked it a bit for testing purposes). Funny enough I found the same question, based on the same example here: https://stackoverflow.com/questions/10318023/php-socket-connections-cant-handle-multiple-connection I tried to understand every part of it and I'm close to seeing how it works in detail, but for some reason, when I connect

I'm a newbie in network programming, so please forgive me if this is a dumb question :) I created 1 client and 1 SocketServer.ThreadingMixIn server on Ubuntu 10.04.2 using Python2.7, but it seems like I can only call sock.send() once in client, then I'll get a: Traceback (most recent call last): File "testClient1.py", line 33, in <module> sock.send('c1:{0}'.format(n)) socket.error: [Errno 32] Broken pipe Here's the code I wrote: testClient1.py: #! /usr/bin/python2.7 # -*- coding: UTF-8 -*- import sys,socket,time,threading sock=socket.socket(socket.AF_INET,socket.SOCK_STREAM) try: sock.connect(

i want to execute the following simple server code: import socket s = socket.socket() # Create a socket object host = socket.gethostname() # Get local machine name port = 22331 # Reserve a port s.bind((host, port)) # Bind to the port s.listen(5) # Now wait for client connection. while True: c, addr = s.accept() # Establish connection with client. print('Got connection from', addr) c.send('Thank you for connecting') c.close() gives the following error while executing: OSError: [Errno 99] Cannot assign requested address why the OS cannot bind the specified port with the address? If it works