slice

I have a 18 character string I want characters 2-8 from. In python I can do this: sliceMe = "nnYYYYYYnnnnnnnnnn" print sliceMe[2:8] prints YYYYYY I am looking for a way to do this same thing in groovy, and every explanation is REALLY long. Whats the elegant accepted way to do this in groovy (or java for that matter)? groovy:000> sliceMe = "nnYYYYYYnnnnnnnnnn" ===> nnYYYYYYnnnnnnnnnn groovy:000> sliceMe[2..7] ===> YYYYYY Note the difference in the length being 1 less. BZ. You inherit all the Java methods off String so sliceMe.substring(2,7) should do the trick. For future reference, you can

I'm practicing the array section of JavaScript Koan and I'm not fully understanding why these answers are correct. I added my assumptions below if someone could please clarify/let me know if I'm wrong : it("should slice arrays", function () { var array = ["peanut", "butter", "and", "jelly"]; expect(array.slice(3, 0)).toEqual([]); Why wouldn't it at least slice "jelly" since the slice begins with 3? How does the cut off of 0 make it empty instead? expect(array.slice(3, 100)).toEqual(["jelly"]); If the cut off index goes beyond what currently exists in the array, does this mean that a new array

1.splice() 对数组添加/删除项目，然后返回该数组。注意：该方法会改变原始数组。 arrayObject.splice(index,howmany,item1,.....,itemX)；index：起始位置，使用负数可从数组结尾处规定位置；howmany：要删除的元素个数，可以为0；item1,.....,itemX参数可选； <script type="text/javascript"> var arr = new Array(6) arr[0] = "George" arr[1] = "John" arr[2] = "Thomas" arr[3] = "James" arr[4] = "Adrew" arr[5] = "Martin" arr.splice(2,0,"William");//在arr【1】后面插入数据“William” arr.splice(2,1,"William");//删除arr【1】后面的一个数据“Thomas”，然后在该位置插入数据“William” arr.splice(2,3,"William");//删除arr【1】后面的三个数据“Thomas”、“James”，“Adrew”，然后在该位置插入数据“William” </script> 2.slice（） 从已有的数组中返回选定的元素。注意：不会修改原始数组。 arrayObject

I'm looking for the best most efficient way to match the end of a single string with a value from a predefined list of strings. Something like my_str='QWERTY' my_lst=['QWE','QQQQ','TYE','YTR','TY'] match='TY' or match=['TY'] Under the restrictions len(my_lst) is known but arbitrary thus could be very long, probably around 30 elements in my_lst may have different len so I can't just check a defined last portion of my_str every time for my_str as well as the matching elements in my_lst they can be either strings or lists, whichever is more efficient (see background) len(my_str) is mostly small,

Possible Duplicate: How do you split a list into evenly sized chunks in Python? Hi, I would like to split a list in many list of a length of x elements, like: a = (1, 2, 3, 4, 5) and get : b = ( (1,2), (3,4), (5,) ) if the length is set to 2 or : b = ( (1,2,3), (4,5) ) if the length is equal to 3 ... Is there a nice way to write this ? Otherwise I think the best way is to write it using an iterator ... The itertools module documentation . Read it, learn it, love it. Specifically, from the recipes section: import itertools def grouper(n, iterable, fillvalue=None): "grouper(3, 'ABCDEFG', 'x') --