slice

Can python's slice notation be used outside of brackets?

大憨熊 提交于 2019-12-06 07:52:30
Within brackets, python's slice shorthand auto-generates tuples of slice objects: class Foo(object): def __getitem__(self, key): print key Foo()[1::, 2:20:5] This prints (slice(1, None, None), slice(2, 20, 5)) . As far as I can tell, however, this shorthand doesn't work outside brackets. Is there any way to use slice shorthand in other contexts? I could define a dummy object that simply returns whatever it is passed to __getitem__ -- that would at least give me a way to generate slice tuples using the shorthand syntax. Is there a more pythonic way? NumPy has an s_ object that will do this for

How to show a subsection or “slice” of an SVG graphic?

牧云@^-^@ 提交于 2019-12-06 07:39:09
问题 Is there any way to slice an SVG . I mean any already available lib . I need to implement this slicing component in Java. I mean , I have single SVG file and based rulers/scales i choose graphically , I want to slice the single SVG into different SVG files. Hope I am clear 回答1: Yes, although, you'd think this was classified information - or just simply impossible - based on how hard it is to find this basic fact.... Apparently , all you need to do is reference the viewBox from a URI "fragment

non adjacent slicing of numpy multidimensional array in python

心已入冬 提交于 2019-12-06 07:36:28
I have a multidimensional array a: a = np.random.uniform(1,10,(2,4,2,3,10,10)) For dimensions 4-6, I have 3 lists which contain the indexes for slicing that dimension of array 'a' dim4 = [0,2] dim5 = [3,5,9] dim6 = [1,2,7,8] How do I slice out array 'a' such that i get: b = a[0,:,0,dim4,dim5,dim6] So b should be an array with shape (4,2,3,4), and containing elements from the corresponding dimensions of a. When I try the code above, I get an error saying that different shapes can't be broadcast together for axis 4-6, but if I were to do: b = a[0,:,0:2,0:3,0:4] then it does work, even though the

How do I initialize an array without using a for loop in Go?

家住魔仙堡 提交于 2019-12-06 06:16:01
问题 I have an array A of boolean values, indexed by integers 0 to n , all initially set to true . My current implementation is : for i := 0; i < n; i++ { A[i] = true } 回答1: Using a for loop is the simplest solution. Creating an array or slice will always return you a zeroed value. Which in case of bool means all values will be false (the zero value of type bool ). Note that using a Composite literal you can create and initialize a slice or array, but that won't be any shorter: b1 := []bool{true,

mask-rcnn的解读(三):batch_slice()

折月煮酒 提交于 2019-12-06 05:53:40
我已用随机生产函数取模拟5张图片各有8个box的坐标值,而后验证batch_slice()函数的意义。由于inputs_slice = [x[i] for x in inputs] output_slice = graph_fn(*inputs_slice)代码一时蒙蔽,故而对其深入理解,如下:代码如下: import tensorflow as tfimport randomimport numpy as npsess=tf.Session()input=np.array([random.randint(0,150) for i in range(5*8*4)]).reshape((5,8,4))# print('show input=',input)ax=np.array([random.randint(0,7) for i in range(5*6)]).reshape((5,6))inputs=[input,ax]print('true_inputs=',inputs)def batch_slice(inputs, graph_fn, batch_size, names=None): """Splits inputs into slices and feeds each slice to a copy of the given computation graph and

How do you use a variable as an index when slicing strings in Python?

谁说胖子不能爱 提交于 2019-12-06 04:56:43
问题 I've been trying to slice two characters out of a string using a loop, but instead of grabbing two characters, it only grabs one. I've tried: input[i:i+1] and input[i:(i+1)] but neither seems to work. How do I use a variable for slicing? The full routine: def StringTo2ByteList(input): # converts data string to a byte list, written for ascii input only rlist = [] for i in range(0, len(input), 2): rlist.append(input[i:(i+1)]) return rlist 回答1: The slice values aren't the start and end

X264-libx264编码库

余生长醉 提交于 2019-12-06 04:40:11
X264编码库libx264实现真正的视频编解码,该编解码算法是基于块的混合编码技术,即帧内/帧间预测,然后对预测值变换、量化,最后熵编码所得。 编码帧的类型分为I帧(x264_type_i)、P帧(x264_type_p)、B帧(x264_type_b),在H264中叫做图像片Slice。 X264把整帧图像看作一个Slice,片中有slice_type_i、slice_type_p、slice_type_b之分。 I帧只有slice_type_i,P帧有slice_type_i、slice_type_p,B帧三种片都有。 X264的H264视频编码过程可以分为三个步骤:首先根据规则判定当前帧的编码类型,如果是B帧,要缓冲存放、获取;然后对待编码图像进行帧内预测、帧间预测、整数DCT变换、量化和熵编码;最后把压缩的H264数据进行NAL层打包输出。 X264编码器有关的重要结构体: x264_image_t:实际参与编码的编码帧图像信息。 typedef struct { int i_csp; //图像空间颜色 int i_plane; //图像平面数目 int i_stride[4]; //每个图像平面的跨度,也就是每一行数据的字节数 uint8_t *plane[4]; //每个图像平面存放数据的起始地址,plane[0]是Y平面,plane[1]是U平面,plane[2

Is returning a slice of a local array in a Go function safe?

亡梦爱人 提交于 2019-12-06 04:22:51
问题 What happens if I return a slice of an array that is a local variable of a function or method? Does Go copy the array data into a slice create with make() ? Will the capacity match the slice size or the array size? func foo() []uint64 { var tmp [100]uint64 end := 0 ... for ... { ... tmp[end] = uint64(...) end++ ... } ... return tmp[:end] } 回答1: This is detailed in Spec: Slice expressions. The array will not be copied, but instead the result of the slice expression will be a slice that refers

using references to point to sliding window array in Perl

喜夏-厌秋 提交于 2019-12-06 03:54:00
here is my problem: I have 2 arrays. One is character array and represents a sliding window. Characters gets shifted from the beginning and pushed at the end. I would like to use a second array to store references to array slices that 'follow' the characters as they move along. Example: my @char_array = ('h','e','l','l','o','w','o','r','l','d'); my $char_arr_ref=[@char_array[1..$#char_array]]; print @$char_arr_ref, "\n"; # slice contains 'elloworld'; shift(@char_array); push(@char_array), 'x'; print @$char_arr_ref, "\n"; # slice still contains 'elloworld', not 'lloworldx' as I need; IN other

pandas time series multiple slice

只谈情不闲聊 提交于 2019-12-06 02:56:56
I can see from the pandas documentation that you can go: df.loc[['a','b','c'],:] For time series, why can you not go: x = df.loc[['2005-10-27 14:30':'2005-10-27 15:15', '2006-04-14 14:40':'2006-04-14 15:20', '2008-01-25 14:30':'2008-01-25 15:30'],:] I get a syntax error. Can you not do multiple sliced ranges on a time series? Is there a workaround? While a DataFrame index will accept a list of column indexes, it will not accept a list of row slice objects. This should do what you want, it loops through your desired ranges compiling a new DataFrame. import numpy as np import pandas as pd # let