slice

数组方法:concat、slice、reverse;只复制出副本,不改变原数组;

会有一股神秘感。 提交于 2019-12-15 08:58:36
数组的一些方法时不会改变原数组的 1. concat,拼接数组 (1)arr.concat();//赋值arr (2)arr.concat(arr1, arr2,arr[n]);//赋值多个数组到副本的后面 (3)arr.concat(arr1, item1, item2,item[n]);//赋值多个数组或项到副本后面 拼接多个数组: 拼接多个数组和项 2. slice:从第几位开始复制到第几位,如果没有指定结束的位置,那么复制到结尾 也是复制出一个副本,不改变原数组 3. reverse:逆序 也是复制一个副本,不过顺序和原数组相反 来源: CSDN 作者: 先去前面探探路 链接: https://blog.csdn.net/zyz00000000/article/details/103461899

字符串截取,方法,slice,substring,substr。

白昼怎懂夜的黑 提交于 2019-12-14 11:03:24
let str = 'abcdef'; // 0 str = str.slice(0);//返回整个字符串 abcdef str = str.substring(0);//返回整个字符串 abcdef str = str.substr(0);//返回整个字符串 abcdef // 使用一个参数 str = str.slice(2);//截取第二个之后所有的字符 cdef str = str.substring(2);//截取第二个之后所有的字符 cdef str = str.substr(2);//截取第二个之后所有的字符 cdef // 使用两个参数 str = str.slice(2,4);//截取第二个到第四个之间的字符 cd str = str.substring(2,4);//截取第二个到第四个之间的字符 cd str = str.substr(2,4);//截取从第3个开始往后数4位之间的字符 cdef // 使用两个负数 str = str.slice(1,-3);//截取第二个到第四个之间的字符 bc str = str.substring(1,-3);//截取第二个到第四个之间的字符 a #负数转换为0 str = str.substr(1,-3);//不能为负数,若强行传递负数,会被当成0处理 ' ' #负数转换为0 console.log(str) —————

How to convert slice of structs to slice of strings in go?

二次信任 提交于 2019-12-14 03:58:07
问题 New go user here. I have a slice of this struct objects: type TagRow struct { Tag1 string Tag2 string Tag3 string } Which yeilds slices like: [{a b c} {d e f} {g h}] I'm wondering how can I convert the resulting slice to a slice of strings like: ["a" "b" "c" "d" "e" "f" "g" "h"] I tried to iterate over like: for _, row := range tagRows { for _, t := range row { fmt.Println("tag is" , t) } } But I get: cannot range over row (type TagRow) So appreciate your help. 回答1: For your specific case I

Java - Slice any array at steps

本小妞迷上赌 提交于 2019-12-14 03:54:57
问题 In python we are able to do the following: array = [0,1,2,3,4,5,6,7,8,9,10] new_array= array[::3] print(new_array) >>>[0,3,6,9] Is there an equivalent to this in Java? I have been looking for this type of array slicing, but I have had no luck. Any help would be great, Thanks! 回答1: If you are using Java 8, then you can make use of streams and do the following: int [] a = new int [] {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; // filter out all indices that evenly divide 3 int [] sliceArr = IntStream

Slicing Pandas Dataframe according to number of lines

纵饮孤独 提交于 2019-12-14 03:48:32
问题 I suppose this is something rather simple, but I can't find how to make this. I've been searching tutorials and stackoverflow. Suppose I have a dataframe df loking like this : Group Id_In_Group SomeQuantity 1 1 10 1 2 20 2 1 7 3 1 16 3 2 22 3 3 5 3 4 12 3 5 28 4 1 1 4 2 18 4 3 14 4 4 7 5 1 36 I would like to select only the lines having at least 4 objects in the group (so there are at least 4 rows having the same "group" number) and for which SomeQuantity for the 4th object, when sorted in

Generate array with with range of integers

。_饼干妹妹 提交于 2019-12-14 03:20:00
问题 I have two values: [3:6] I was trying to play something around in Golang but I can't manage to find a good method to create an array according to those values. This what I would like to achieve: [3,4,5,6] 回答1: You can make use of the for ... range construct to make it more compact and maybe even faster: lo, hi := 3, 6 s := make([]int, hi-lo+1) for i := range s { s[i] = i + lo } As a matter of curiosity, the loop can be implemented without a loop variable, but it will be slower, and the code

Slice syntax to object [duplicate]

给你一囗甜甜゛ 提交于 2019-12-14 02:34:06
问题 This question already has answers here : Passing Python slice syntax around to functions (3 answers) Closed 6 years ago . I have a class holding data (a numpy ndarray) that includes a method storing the data to a mat-file (using scipy.io.savemat). The data can be very large, so I may only want to store a segment of the data. Therefore I pass a slice-object, like this: def write_mat(self, fn, fields=None, sel=None): # (set fields and sel to sensible values if None) scipy.io.savemat(fn, dict

How does comparison of a slice with an array work in Rust?

牧云@^-^@ 提交于 2019-12-13 17:41:02
问题 Why would [1,1] == &[1,1] not even compile (presumably because they're different types), yet the following snippet compiles and runs fine. let a: [i32; 100] = [1; 100]; let b: &[i32] = &a[1..3]; if b == [1, 1] { // comparison with &[1, 1] works as well println!("it works"); // this does get printed } 回答1: Right now, arrays in Rust are somewhat special because Rust lacks type-level integers. You can't write a function fn f<T, N>(array: &[T; N]) . Likewise, you can't implement a trait which is

Preserving corners while stretching border image usging qt stylesheet

冷暖自知 提交于 2019-12-13 17:20:36
问题 I'm using Qt 4.7 and trying to apply Qt stylesheets to my application. As mentioned here with the help of border-image you can stretch image with corners left "as is". Here is a good example of how that should work. Unfortunately I'm unable to get the same result. Instead of preserved corners I'm getting cutted and repeated middle part of the image. Is there any mistakes in my code or its not implemented in Qt? (button added to MainWindow via gui designer). int main(int argc, char *argv[]) {

Javascript: Split array of objects into seperate arrays with dynamic names depending on property value

时光毁灭记忆、已成空白 提交于 2019-12-13 17:14:21
问题 I have an array containing objects. Now I want to slice the array to new arrays containing only those objects matching a certain property value. Ideally the new array names should be created dynamically. The original array looks like this: specificSlotButtonArray = [ {slotStarttime:"06:00:00", slotTimespan:1}, {slotStarttime:"09:00:00", slotTimespan:1}, {slotStarttime:"12:00:00", slotTimespan:2}, {slotStarttime:"15:00:00", slotTimespan:2}, {slotStarttime:"18:00:00", slotTimespan:3} ]; The new