sizeof

sizeof与strlen的用法

﹥>﹥吖頭↗ 提交于 2019-12-04 18:41:50
解析C/C++语言中的sizeof 一、sizeof的概念   sizeof是C语言的一种单目操作符,如C语言的其他操作符++、--等。它并不是函数。sizeof操作符以字节形式给出了其操作数的存储大小。操作数可以是一个表达式或括在括号内的类型名。操作数的存储大小由操作数的类型决定。 二、sizeof的使用方法   1、用于数据类型   sizeof使用形式:sizeof(type)   数据类型必须用括号括住。如sizeof(int)。   2、用于变量   sizeof使用形式:sizeof(var_name)或sizeof var_name   变量名可以不用括号括住。如sizeof (var_name),sizeof var_name等都是正确形式。带括号的用法更普遍,大多数程序员采用这种形式。   注意:sizeof操作符不能用于函数类型,不完全类型或位字段。不完全类型指具有未知存储大小的数据类型,如未知存储大小的数组类型、未知内容的结构或联合类型、void类型等。   如sizeof(max)若此时变量max定义为int max(),sizeof(char_v) 若此时char_v定义为char char_v [MAX]且MAX未知,sizeof(void)都不是正确形式。 三、sizeof的结果    sizeof 操作符的结果类型是 size_t ,它在头文件中

解析sizeof和strlen的区别

我与影子孤独终老i 提交于 2019-12-04 18:41:39
解析C/C++语言中的sizeof 一、sizeof的概念   sizeof是C语言的一种单目操作符,如C语言的其他操作符++、--等。它并不是函数。sizeof操作符以字节形式给出了其操作数的存储大小。操作数可以是一个表达式或括在括号内的类型名。操作数的存储大小由操作数的类型决定。 二、sizeof的使用方法   1、用于数据类型   sizeof使用形式:sizeof(type)   数据类型必须用括号括住。如sizeof(int)。   2、用于变量   sizeof使用形式:sizeof(var_name)或sizeof var_name   变量名可以不用括号括住。如sizeof (var_name),sizeof var_name等都是正确形式。带括号的用法更普遍,大多数程序员采用这种形式。   注意:sizeof操作符不能用于函数类型,不完全类型或位字段。不完全类型指具有未知存储大小的数据类型,如未知存储大小的数组类型、未知内容的结构或联合类型、void类型等。   如sizeof(max)若此时变量max定义为int max(),sizeof(char_v) 若此时char_v定义为char char_v [MAX]且MAX未知,sizeof(void)都不是正确形式。 三、sizeof的结果    sizeof操作符的结果类型是size_t

golang学习----nil值

风格不统一 提交于 2019-12-04 18:23:08
golang中的空值 两个空值是不能比较的 func main() { fmt.Println(nil==nil) } 运行结果见下图: nil 没有默认类型 func main() { fmt.Printf("%T", nil) print(nil) } 运行结果见下图: 不同类型 nil 的指针是一样的 func main() { var m map[int]string var num *int fmt.Printf("%p\n", m) fmt.Printf("%p", num) } 运行结果见下图: map、slice、pointer、channel、func、interface 的零值是nil func main() { var m map[int]string var ptr *int var c chan int var sl []int var f func() var i interface{} var k struct{ name string age int } fmt.Printf("%#v\n", m) fmt.Printf("%#v\n", ptr) fmt.Printf("%#v\n", c) fmt.Printf("%#v\n", sl) fmt.Printf("%#v\n", f) fmt.Printf("%#v\n", i) fmt

大小端

耗尽温柔 提交于 2019-12-04 18:05:53
#include <stdio.h> int main() { union{ short s; char c[sizeof(short)]; }un; un.s = 0x0102; if (sizeof(short) == 2) { if (un.c[0] == 1 && un.c[1] == 2) printf("big-endian\n"); else if (un.c[0] == 2 && un.c[1] == 1) printf("little-endian\n"); } getchar(); return 0; } 来源: https://www.cnblogs.com/zzyoucan/p/11876733.html

实验三-并发程序 20175201张驰

♀尐吖头ヾ 提交于 2019-12-04 17:58:15
实验三-实时系统-1 任务详情 学习使用Linux命令wc(1) 基于Linux Socket程序设计实现wc(1)服务器(端口号是你学号的后6位)和客户端 客户端传一个文本文件给服务器 服务器返加文本文件中的单词数 上方提交代码 附件提交测试截图,至少要测试附件中的两个文件 查看wc的功能 在终端中输入man wc查看wc的功能 代码 服务器端server // // main.c // server // // Created by shadow on 2019/11/17. // Copyright © 2019 shadow. All rights reserved. // include<netinet/in.h> // sockaddr_in include<sys/types.h> // socket include<sys/socket.h> // socket include<stdio.h> // printf include<stdlib.h> // exit include<string.h> // bzero define SERVER_PORT 175201 define LENGTH_OF_LISTEN_QUEUE 20 define BUFFER_SIZE 1024 define FILE_NAME_MAX_SIZE 512 int main

In C are malloc(256) and malloc(sizeof(char)*256) equivalent?

旧巷老猫 提交于 2019-12-04 17:39:39
问题 I see that people often write C code such as: char *ptr = malloc(sizeof(char)*256); Is that really necessary? The standard says that sizeof(char)==1 by definition, so doesn't it make sense just to write: char *ptr = malloc(256); 回答1: Yes, C defines sizeof(char) to be 1, always (and C++ does as well). Nonetheless, as a general rule, I'd advise something like: char *ptr = malloc(256 * sizeof(*ptr)); This way, when your boss says something like: "Oh, BTW we just got an order from China so we

Why call sizeof operator with two arguments?

六眼飞鱼酱① 提交于 2019-12-04 17:09:13
问题 I recently came across some code that looked like: if(sizeof(var,2) == 4) { ... } (where var is a type) I was quite surprised to see what appeared to be two arguments to the sizeof operator. A quick scan of the ISO/ANSI C99 standard did not yield any secrets. I couldn't come up with any reading of the grammar that allowed a comma there. Searching Google Code, I was able to find an example of this syntax in some PPC code. Is this some PPC-specific syntax? What does it mean? EDIT: It turns out

Difference between sizeof(char) and sizeof(char *)

孤街醉人 提交于 2019-12-04 14:52:05
I'm wondering if there is a difference between sizeof(char) and sizeof(char *) : char *s; s = malloc(sizeof(char*)*len + 1); char *s; s = malloc(sizeof(char)*len + 1); Is this the same ? char is a character and sizeof(char) is defined to be 1. ( N1570 6.5.3.4 The sizeof and _Alignof operators, paragraph 4) char* is a pointer to a character and sizeof(char*) depends on the environment. It is typically 4 in 32-bit environment and 8 in 64-bit environment. In typical environment where sizeof(char*) > sizeof(char) , malloc(sizeof(char*)*len + 1) will (at least try to) allocate more memory than

Windows 获取windows密码

这一生的挚爱 提交于 2019-12-04 14:26:28
#include <iostream> #define Main main #define COLOR_GREEN system("color 2"); #include <vector> #include <list> #include <string> #include <WinSock2.h> #include <WS2tcpip.h> #include <memory> #include <VersionHelpers.h> #include <LM.h> #include <winnetwk.h> #include "BitMap.h" #include <wlanapi.h> #include "ATBAudioEngine/ATBAudioEngine.h" #include "Package.h" #pragma comment(lib,"Ws2_32.lib") #pragma comment(lib,"Mpr.lib") #pragma comment(lib,"netapi32.lib") #pragma comment(lib,"Wlanapi.lib") #include <Windows.h> class disorderly { int m_buf[10] = { 0 }; public: void initBuf() { srand

What determines the size of integer in C? [duplicate]

丶灬走出姿态 提交于 2019-12-04 14:23:06
This question already has answers here : Closed 6 years ago . Possible Duplicate: size of int, long, etc Does the size of an int depend on the compiler and/or processor? I'm not sure if similar questions have been asked before on SO (Atleast, I couldn't find any while searching, so thought of asking myself). What determines the size of int (and other datatypes) in C . I've read it depends on the machine/operating system/compiler, but haven't come across a clear/detailed enough explanation on things like what overrides the other, etc. Any explanation or pointers will be really helpful.