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I want to resize the page when the keyboard appears on the screen. I was looking for any clue all day but I can't find anything. In my case. I want to have full page TextBox and some buttons under it. <Grid x:Name="RootLayout" > <Grid > <Grid.RowDefinitions> <RowDefinition Height="*"/> <RowDefinition Height="70"/> </Grid.RowDefinitions> <ScrollViewer Margin="0" > <TextBox TextWrapping="Wrap" Text="TextBox" AcceptsReturn="True" VerticalScrollBarVisibility="Auto" Height="698" Width="480"/> </ScrollViewer> <Canvas x:Name="RootMenu" Margin="0,1,0,0" Grid.Row="1" /> </Grid> </Grid> I use to thing

给定一个由 n行数字组成的数字三角形如下图所示。试设计一个算法，计算出从三角形 的顶至底的一条路径(每一步可沿左斜线向下或右斜线向下)，使该路径经过的数字总最大 思路：将三角形存在一个二维数组中，然后从倒数第二层往上，每次寻找下一层到此层的最大值，记录在dp【i】【j】 中，一层一层填表，最后dp[[1][1]就是最大值 代码： #include<iostream> #include<string.h> #include<algorithm> using namespace std; int G[110][110]; int dp[110][110]; int main() { int n; cin>>n; for(int i=1;i<=n;i++) { for(int j=1;j<=i;j++) { cin>>G[i][j]; if(i==n) { dp[i][j] = G[i][j]; } } } for(int j=n-1;j>=1;j--) { for(int i=1;i<=j;i++) { dp[j][i] = max(dp[j+1][i],dp[j+1][i+1]) + G[j][i]; } } cout<<dp[1][1]; } 给定n个整数（可能为负数）组成的序列a[1],a[2],a[3],…,a[n]，求该序列如a[i]+a[i+1]+…+a[j

一、关于自动布局（Autolayout） 在Xcode中，自动布局看似是一个很复杂的系统，在真正使用它之前，我也是这么认为的，不过事实并非如此。 我们知道，一款iOS应用，其主要UI组件是由一个个相对独立的可视单元构成，这些可视单元有的主要负责向用户输出有用的信息，有些则负责信息的输入（交互），交互的过程中往往还伴随有动画的效果，已达到整个信息传递的连贯性以及用户体验的细腻感。可视单元，在实际开发中主要是view、button等，那么这些可视单元的关系由两个基本的关系构成：兄弟关系和父子关系，整个视图单元就是一个树形结构： 对于任何一个UI组件，确定了它的（相对于父view）位置、大小也就确定了它在整个UI视图中的展示效果。 Autolayout（以及iOS8中新增的sizeclass）是为了解决这些UI可视单元或者元素是怎样布局、排列的问题。在过去只有iPhone4的时候，我们可以在代码里将每一个可视单元的位置写死，这样是没问题的，但随着iPhone5、6的发布，屏幕尺寸有了越来越多中可能，未来不排除更多尺寸的iPhone发布出来，这就要求我们的APP的UI元素具有在屏幕尺寸不同的设备上具有一定动态的可调性，已实现较好的UI展示效果。从目前苹果提供的技术来看，有下、中、上三种实现方法： 下策是，代码中判断当前设备的尺寸，对UI元素进行手工的调整，其缺点是显而易见的：代码复杂

Possible Duplicate: determine size of dynamically allocated memory in c newbie questions about malloc and sizeof How can I get the size of an array from a pointer in C? Malloc -> how much memory has been allocated? int **arrofptr; arrofptr = (int **)malloc(sizeof(int *) * 2); arrofptr[0] = (int *)malloc(sizeof(int)*6144); arrofptr[1] = (int *)malloc(sizeof(int)*4800); Now i have to know that how many bytes are allocated in arrofptr,arrofptr[0],arrofptr[1]? is there any way to know the size? if we will print sizeof(arrofptr); sizeof(arrofptr[0]); sizeof(arrofptr[1]); then it will print 4 No,

I simply copied my image and saved it to another temp folder in the current directory, nothing is modified, but the image size is somehow reduced... why? from PIL import Image import os image_path = "/Users/moomoochen/Desktop/XXXXX.jpg" img = Image.open(image_path) pathname, filename = os.path.split(image_path) new_pathname = (pathname + "/temp") if not os.path.exists(new_pathname): os.makedirs(new_pathname) img.save(os.path.join(new_pathname, filename)) The image size is reduced quite a bit, from 3.2 MB down to 350 KB, what did I miss? When PIL/Pillow saves your image as a JPEG, it uses a

please tell me how to get image file size in bytes using javascript. Thanks If javascript engine supports canvas elements you can try to use canvas element and getImageData to fetch the pixel data from your image. Then, depending on type of the image you could create the binary representation of this image. Here is info about canvas element and getImagedata api: http://www.whatwg.org/specs/web-apps/current-work/#dom-context-2d-getimagedata To get the image size, you need to access it on the server. Javascript is a client-side utility, so it can't directly retrieve information from a server.