simpledateformat

Getting the Date format in Java [duplicate]

由 前提是你 提交于 2019-12-12 02:23:31
问题 This question already has answers here : Java string to date conversion (13 answers) Closed 6 years ago . I am have this String from a Date object: Mon Mar 25 00:00:00 IST 2013 What is the String representation of the date format? 回答1: The code below should work fine. public static void main(String[] args) throws Exception { String target = "Mon Mar 25 00:00:00 IST 2013"; DateFormat df = new SimpleDateFormat("EEE MMM dd kk:mm:ss z yyyy", Locale.ENGLISH); Date result = df.parse(target); System

SimpleDateFormat ignores TimeZone

由 [亡魂溺海] 提交于 2019-12-12 02:22:25
问题 I have read a bunch of posts on this, but, I am obviously missing something. I have date string, and a time zone. I am trying to instantiate a date object as follows: final SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); sdf.setTimeZone(TimeZone.getTimeZone("UTC")); java.util.Date dateObj = sdf.parse("2013-10-06 13:30:00"); System.out.println(dateObj); What is printed is: Sun Oct 06 09:30:00 EDT 2013 What I want is a date object in UTC format. Not one converted to EDT.

Java SimpleDatetime parse

由 你说的曾经没有我的故事 提交于 2019-12-12 02:07:02
问题 Maybe i'm just missing the obvious, but I can't get SimpleDateTime s parse() method to work: I want to parse dates like June 19, 2011 . So, according to the documentation: http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html for my needs it should be: M : Month in year. If the number of pattern letters is 3 or more, the month is interpreted as text; --> MMM d : Day in month. For parsing, the number of pattern letters is ignored unless it's needed to separate two adjacent

Java SimpleDateFormat and 19700101 conversion problem

由 孤街醉人 提交于 2019-12-11 23:28:20
问题 i have a little problem with date conversion in java. When i put 19700101 to SimpleDateFormat and then call getTime i got -3600000. I write test: SimpleDateFormat dateFormat = new SimpleDateFormat("yyyyMMdd"); Date date = dateFormat.parse("19700101"); System.out.println(date.getTime()); System.out.println(dateFormat.format(new Date(0))); System.out.println((new Date(0)).getTime()); Result should be: 0 19700101 0 but i got -3600000 19700101 0 My question is why SimpleDateFormat return -3600000

convert String to Date

由 送分小仙女□ 提交于 2019-12-11 20:00:53
问题 I want to convert the following string into Date type this way Date dateToFormat = null; DateFormat formatter = new SimpleDateFormat("E MMM d HH:mm:ss zzzz yyyy"); String databaseDateAsString = "Wed May 11 16:30:00 Asia/Calcutta 2011"; try { dateToFormat = formatter.parse(databaseDateAsString); } catch (Exception e) { System.out.println("Cannot Parse Date:" + e); } But it is giving the following error:- Cannot Parse Date:java.text.ParseException: Unparseable date: "Wed May 11 16:30:00 Asia

Date format issue in android

由 ＊爱你＆永不变心＊ 提交于 2019-12-11 19:17:04
问题 In android am getting date in (date = "04-01-2013") this format but i want to show same date in en.US format like (date="Friday,January 04,2013") 回答1: use SimpleDateFormat. set input pattern matching input date string: "04-01-2013" -> "dd-MM-yyyy" . And output pattern like output: "Friday, January 04, 2013" -> "EEEE, MMMM dd, yyyy" public String formatDate(String input){ SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy"); Date d = sdf.parse(input); sdf.applyPattern("EEEE, MMMM dd, yyyy

how to format a date?

由 ☆樱花仙子☆ 提交于 2019-12-11 17:53:06
问题 Hello I have been trying to format this date but it keeps giving me in unparsable date error? I am trying to get a time stamp like 2011-06-24T19:55:37Z to be June 24, 2011. here is the code I am using. Also on a side note is contraction (like the 1st, 2nd, 3rd) possible? SimpleDateFormat sdf = new SimpleDateFormat("MM d, yyyy", Locale.US); Date dt = sdf.parse("2011-03-01T17:55:15Z"); time.setText("Time: " + dt.toString()); 回答1: The problem is that the format provided to SimpleDateFormat's

How to format Oracle date and timestamp type values in Java?

由 眉间皱痕 提交于 2019-12-11 16:46:35
问题 I have date and timestamp type fields in oracle db, I need to retrieve these values and map them to my object field. Though I format the values I do not get the expected result. Here is the my code snippet. import java.util.Date; public class Operation{ private Date created; private Date valueDate; public Date getValueDate() { return this.valueDate; } public void setValueDate(Date valueDate) { this.valueDate = valueDate; } public Date getCreated() { return this.valueDate; } public void

JAVA处理日期时间常用方法：

由 无人久伴 提交于 2019-12-11 16:18:08
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> JAVA处理日期时间常用方法： 1.java.util.Calendar Calendar 类是一个抽象类，它为特定瞬间与一组诸如 YEAR、MONTH、DAY_OF_MONTH、HOUR 等 日历字段之间的转换提供了一些方法，并为操作日历字段（例如获得下星期的日期）提供了一些方法。瞬间可用毫秒值来表示，它是距历元（即格林威治标准时间 1970 年 1 月 1 日的 00:00:00.000，格里高利历）的偏移量。 例: Java代码 1. Calendar cal = Calendar.getInstance();//使用默认时区和语言环境获得一个日历。 2. cal.add(Calendar.DAY_OF_MONTH, -1);//取当前日期的前一天. 3. 4. cal.add(Calendar.DAY_OF_MONTH, +1);//取当前日期的后一天. 5. 6. //通过格式化输出日期 7. java.text.SimpleDateFormat format = new java.text.SimpleDateFormat("yyyy-MM-dd"); 8. 9. System.out.println("Today is:"+format.format(Calendar.getInstance()

How to parse date with only month and year with SimpleDateFormat

由 微笑、不失礼 提交于 2019-12-11 16:11:22
问题 I am working with expiration date of card. I have a API where I will get expiration date in " yyMM " format as " String ". Here I am trying to use SimpleDateFormat with TimeZone.getTimeZone("UTC") So my code is like String a= "2011"; SimpleDateFormat formatter = new SimpleDateFormat("yyMM"); formatter.setTimeZone(TimeZone.getTimeZone("UTC")); Date date = formatter.parse(a); System.out.println(date); Now problem is, when I am passing 2011 the out it gives is Sat Oct 31 17:00:00 PDT 2020 Here
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