simpledateformat

How to check if a date is after today java

情到浓时终转凉″ 提交于 2019-12-13 09:45:37
问题 Im trying to check whether a date entered by the user is after todays date. Here is my code: SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/dd"); Date enteredDate = sdf.parse(date); Date currentDate = new Date(); if(enteredDate.after(currentDate)){ Date is a variable with the user date in the format "2016/04/26". After doing some debugging i found that enteredDate and currentDate are null. Any ideas why this is? Thanks 回答1: As mentioned in comments, it's not possible that Date object

parse a date from string gives exception in android

浪尽此生 提交于 2019-12-13 09:43:02
问题 I want to parse a string from string to date ,Date is of format like Tuesday March 19,2015 . I want to parse and format it as yyyy-dd-mm format. The below code gives me exception that "unparceble date". Code : DateFormat df1 = new SimpleDateFormat("yyyy-MM-dd"); try { date1 = df1.parse(currentDate); System.out .println("============my formated date====================" + date1.toString()); Calendar cal = Calendar.getInstance(); cal.setTime(date1); cal.add(Calendar.DATE, 10); // add 10 days

Issue with SimpleDateFormat

风格不统一 提交于 2019-12-13 08:58:26
问题 I am working on date format with SimpleDateFormat . But when I format my date in provide format, year value increment by 1.The condition happen with that value. Why this happen? SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-YYYY"); System.out.println("dob - "+date); // Java date System.out.println("formatted date - "+sdf.format(date)); Output as follows : dob - Sun Dec 28 00:00:00 IST 1975 formatted date - 28-12-1976 Year value increment by 1. Why this happen. 回答1: As per Oracle docs

java.text.ParseException: Unparseable date: “2015-03-26 1624:32:39”

走远了吗. 提交于 2019-12-13 08:17:59
问题 I'm generating a date string using the format yyyy-MM-dd HH24:mm:ss . However, when I attempt to parse the resulting string I get an error: java.text.ParseException: Unparseable date: "2015-03-26 1624:32:39" Full example: SimpleDateFormat dateFormatterAPITS = new SimpleDateFormat("yyyy-MM-dd HH24:mm:ss"); Calendar cal = Calendar.getInstance(); cal.setTime(new Date()); cal.add(Calendar.DATE, 30); // add 30 days Date newExpirationDate = dateFormatterAPITS.parse( dateFormatterAPITS.format(cal

Date time parsing error from string format

▼魔方 西西 提交于 2019-12-13 04:49:04
问题 I am trying to get the date format from a string which is saved in sharedpreferences. As you can see the wrong date in the picture.current date is 19/11/2015 but after parsing it is changed to "Mon Jul 11 ..."something.please find some help for me. Thank you. 回答1: Your dateobg returning from web service is : 11-19-2015. You try to get the date from this string, you should in this case use the correct SimpleDateFormat. SimpleDateFormat format = new SimpleDateFormat("MM-dd-yyyy", Locale

how to Convert PST to GMT(-0800) in java?

夙愿已清 提交于 2019-12-13 04:47:36
问题 Actually in my java program like the following code... String date1=null; String formate="IST"; SimpleDateFormat sourceFormat = new SimpleDateFormat("z"); SimpleDateFormat gmtFormat = new SimpleDateFormat("'GMT('Z')'"); date1 = gmtFormat.format(sourceFormat.parse(formate)); System.out.println(date1);//output GMT(+0530) Hear it is giving Correct Value but the timezone may change like PST---- GMT(-0800) will so. But my code alway show only GMT(+0530) Please help me to convert timezone ACT,,PST

convert String “30-MAR-07” to date object

假装没事ソ 提交于 2019-12-13 03:55:18
问题 SimpleDateFormat formatter = new SimpleDateFormat("mm/dd/yyyy"); dt = formatter.parse(temp[0]); gives me the error java.text.ParseException: Unparseable date: "30-MAR-07" Is there any way that I can format the given String to a Date object without having to write my own string splitting and translating-to-months-in-numerals methods? Thanks 回答1: Use correct format, as follows, SimpleDateFormat formatter = new SimpleDateFormat("dd-MMM-yy"); 回答2: Your SimpleDateFormat pattern is completely

How to get time from SimpleDateFormate() in android?

天大地大妈咪最大 提交于 2019-12-13 03:24:08
问题 I have a String this:- Tue Oct 30 13:22:58 GMT+05:30 2012; I want to divide time & date from SimpleDateFormate:- DateFormat f = new SimpleDateFormat("EEE,MM/dd/yyyy hh:mm:ss); Date d = f.parse(my string); DateFormat date = new SimpleDateFormat("MM/dd/yyyy"); DateFormat time = new SimpleDateFormat("hh:mm:ss a"); System.out.println("Date: " + date.format(d)); System.out.println("Time: " + time.format(d)); I am getting this Error:- java.text.ParseException: Unparseable date: "Tue Oct 30 13:22:58

ParseException when parsing a date

こ雲淡風輕ζ 提交于 2019-12-13 01:43:15
问题 I am running the following code: DateFormat fullDate = new SimpleDateFormat("HHmmdd/MMMyy"); Date date = fullDate.parse("035627/NOV15"); and the following exception is thrown: Exception in thread "main" java.text.ParseException: Unparseable date:"035627/NOV15 Any ideas, why the exception is thrown, while the format is validly stated? 回答1: The likeliest reason is that NOV is not a valid month in your default Locale. This should fix the problem (adjust the Locale to match the language used for

How to Validate Date Against multiple patterns format in Java?

被刻印的时光 ゝ 提交于 2019-12-13 01:32:11
问题 My problem is not "how to do it", my problem is the corner cases involved. Here is my code and test case. package datetest.com; import java.text.ParseException; import java.text.SimpleDateFormat; public class MultipleDateParserFormat { private final static String[] PossibleDateFormat=new String[]{ "MM/dd/yyyy", "MM.dd.yyyy", "MM-dd-yyyy", "yyyy/MM/dd", "yyyy.MM.dd", "yyyy-MM-dd", "dd/MM/yyyy", "dd.MM.yyyy", "dd-MM-yyyy" }; public MultipleDateParserFormat(){}; public void checkParseDate(String