simpledateformat

Fri Mar 30 00:00:00 CET 14 to dd/mm/yyyy

扶醉桌前 提交于 2019-12-20 06:07:20
问题 I try to parse format date Fri Mar 30 00:00:00 CET 14 to dd/mm/yyyy this is my code SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy"); System.out.println(formatter.parse(date_retour.toString())); error java.text.ParseException: Unparseable date: "Fri Mar 30 00:00:00 CET 14" help please it is okay now try { SimpleDateFormat formatter = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z", Locale.ENGLISH); SimpleDateFormat formatter2 = new SimpleDateFormat("dd-MM-yyyy"); Date date; date =

Java SimpleDateFormat: Pattern - ParseException [duplicate]

爷,独闯天下 提交于 2019-12-20 05:39:24
问题 This question already has an answer here : Datetime parsing error (1 answer) Closed last year . I am struggling with a date string, I need to parse into the java ‘Date’ object. Here is what I have got so far: try { String value = "2017‎-‎11‎-‎23T14:00:49.184000000Z"; String pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSSSSSSS'Z'"; SimpleDateFormat parser = new SimpleDateFormat(pattern); Date date = parser.parse(value); } catch (ParseException e) {e.printStackTrace();} It currently throws a

java.text.ParseException: unparsable date: “Mon, 22 Aug 2005 20:21:52 +0200”

自古美人都是妖i 提交于 2019-12-20 04:24:31
问题 I got this error. What is wrong on my code? String line = "Date: Mon, 22 Aug 2005 20:21:52 +0200"; String datestring = line.substring(6); DateFormat dateFormat = new SimpleDateFormat("E, dd MMM yyyy HH:mm:ss ZZZZZ"); Date inputDate = null; try { inputDate = dateFormat.parse(datestring); } catch (ParseException e) { e.printStackTrace(); } My errorlog: java.text.ParseException: Unparseable date: "Mon, 22 Aug 2005 20:21:52 +0200" at java.text.DateFormat.parse(Unknown Source) at netspy.EMail

java.text.ParseException: Unparseable date on some devices only

北城以北 提交于 2019-12-20 04:10:22
问题 I'm facing a very bizarre issue. While parsing this string 2016-09-06 05:18:06.023 PM I get the following exception - java.text.ParseException: Unparseable date: "2016-09-06 05:18:06.023 PM" (at offset 24) Weird part is that the device on which this exception has occurred is a friend's Nexus 5 . However, if I debug this same string on my Nexus 5 / several other emulators , it works fine. Here is the code that I'm using. SimpleDateFormat belongs to java.text package. Date belongs to java.util

Display elapsed time with month an day support in JAVA

…衆ロ難τιáo~ 提交于 2019-12-20 03:42:13
问题 I need to display elapsed time in my application form. I currently do this using this code: AppTimer = new Timer(); AppTimer.scheduleAtFixedRate(new java.util.TimerTask() { SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss"); public void run() { sdf.setTimeZone(java.util.TimeZone.getTimeZone("GMT+0")); lblAppRunTime.setText(""+sdf.format(new Date(AppTimeCounter*1000))); AppTimeCounter++; } },1000, 1000); This Code shows hours,minutes & seconds properly but how can I show DAYS & MONTHS?

Display hours between 2 dates in java

眉间皱痕 提交于 2019-12-20 03:12:13
问题 i have this code, i need show only hours:min:sec, any help? String var = "1429174464829"; (this is time in System.currentTimeMillis() ) String p = "HH:mm:ss"; SimpleDateFormat f = new SimpleDateFormat(p); long t = var - System.currentTimeMillis(); String result = f.format(new Date(t)); in example String var, is 1 hours higher than System.currentTimeMillis() result problem EDIT: i obtain: result = 21:59:00 thanks 回答1: Java 8 Okay, this is a little unpleasant, but will get the job done, this is

Postgresql Date type and java SimpleDateFormat

风格不统一 提交于 2019-12-20 03:04:20
问题 I have a database column of type date with the following value 2014-05-01 I then have the following hibernate mapping: @Temporal(TemporalType.DATE) @Column(name = "end_date", nullable = false, length = 13) public Date getEndDate() { return this.endDate; } public void setEndDate(Date endDate) { this.endDate = endDate; } When I reference this date in a JSF page in the following way <h:outputText value="#{someBean.endDate}"> <f:convertDateTime pattern="d MMM yyyy" /> </h:outputText> It reads as

Problems using SimpleDateFormat

纵然是瞬间 提交于 2019-12-20 02:22:07
问题 Apparently, I'm missing something fundamental. I'm having a problem with formatting the value of a jspinner. I've tried a couple different ways and keep receiving an error, didn't keep track of them, other than it has to do with how I'm trying to grab the value from jspinner. Here is the spinner code: //setup date format for both spinners SimpleDateFormat datePattern = new SimpleDateFormat("MM/dd/yyyy"); JSpinner dateFrom = new JSpinner(new SpinnerDateModel()); dateFrom.setEditor(new JSpinner

getting java.lang.IllegalArgumentException: Illegal pattern character 'o'? while parsing java.text.SimpleDateFormat

∥☆過路亽.° 提交于 2019-12-20 01:57:10
问题 I wanted to convert from string to java.util.Date. for the same purpose I used following code, String timeStamp = "Mon Feb 14 18:15:39 IST 2011"; DateFormat formatter = new SimpleDateFormat("dow mon dd hh:mm:ss zzz yyyy"); Date ts = (Date)formatter.parse(timeStamp); The format given to SimpleDateFormat() is format of java.util.Date. When you convert util's Date to string it comes in this format('dow mon dd hh:mm:ss zzz yyyy'). But when I execute code, It gives me Exception. I Don't know what

How to check if a string contains a date in Java?

我怕爱的太早我们不能终老 提交于 2019-12-20 01:10:50
问题 How do I check if a string contains a date of this form: Sunday, January 15, 2012 at 7:36pm EST The data I'm working with contains a ton of strings. But the type of string I'm looking for contains a 2 or 3 word name and a date. I'm checking for dates to identify these types of strings. I've figured out the simpleDateFormat for this type of date. String string1 = "Rahul Chowdhury Sunday, January 15, 2012 at 7:37pm EST"; String string2 = "Aritra Sinha Nirmal Friday, April 1, 2016 at 10:16pm EDT