simpledateformat

Jmeter(十二)_打印时间戳

▼魔方 西西 提交于 2019-12-26 22:46:57
Jmeter中提供了一种函数,可以打印时间戳,如下图   年: yyyy 月:MM 日:dd   时: HH 分: mm 秒:ss 关于时间戳的格式,可以自由组合定义,这里我写成这样 yyyy-MM-dd HH:mm:ss 生成的函数是这样的:${__time(yyyy-MM-dd HH:mm:ss,)} 现在将这个函数写入下一个接口 执行,查看结果树,可以看到结果中,将当前时间打印出来了哦~ 此函数适用于一些需要填写时间参数的接口,用于实时获取当前时间。时间参数如果写死的话,过段时间接口就会报错啦~ 下面说一下时间偏移如何打印。 说到时间偏移,就是说我不光想打印当前时间,我还想打印明天,后台,甚至是明年的时间,那么我们要怎么去处理?这里就需要用到 BeanShell Sampler 在Parameters中传递变量,执行并查看结果树,发现成功打印了跨度为一年的时间戳 附:beanshell打印时间的代码 import java.text.SimpleDateFormat; import java.util.Calendar; import java.util.Date; try{ Date date =new Date(); //获取当前时间 SimpleDateFormat sf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

java Date操作日期相关

余生长醉 提交于 2019-12-26 17:52:34
java Date操作日期相关方法 获取当天日期 获取10分钟/年/月/天/小时后的时间 Date转化为毫秒数 字符串转Date Date转字符串 计算两个日期的毫秒数 比较时间大小 将日期转换为周几 得到二个日期间的间隔天数 1.获取当天日期 Date date = new Date(); DateFormat df1 = DateFormat.getDateInstance();//日期格式,精确到日 System.out.println(df1.format(date)); DateFormat df2 = DateFormat.getDateTimeInstance();//可以精确到时分秒 System.out.println(df2.format(date)); DateFormat df3 = DateFormat.getTimeInstance();//只显示出时分秒 System.out.println(df3.format(date)); DateFormat df4 = DateFormat.getDateTimeInstance(DateFormat.FULL, DateFormat.FULL); //显示日期,周,上下午,时间(精确到秒) System.out.println(df4.format(date)); DateFormat df5 =

Convert 12 hours to 24 hours [closed]

断了今生、忘了曾经 提交于 2019-12-26 09:18:30
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . How to convert 12 hours hh:mm a into HH:mm ? When we converting this we are unable to get into 24 hours format. Here the time format pm to am is not converting when we assigned start time at 10pm and wake up time 7am. Here we are unable to get the total time. It's getting stopped at 12:00am and also we are

Find the difference in time between two time values always gives the “Second” value as 0

时光毁灭记忆、已成空白 提交于 2019-12-25 16:09:14
问题 I'm trying to find the difference between current time value and a future time in HH:MM:SS format. For example: When date1 is "2017-05-11T20:30" and date2 is "2017-05-11T21:40", the output should be 01:10:00. Here's the code I'm trying, wherein I'm trying to find the difference between current time and a future time value: public void updateTimeRemaining() { SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm"); String currentTime = simpleDateFormat.format(new Date())

JAVA AOP(动态代理)

好久不见. 提交于 2019-12-25 14:05:28
什么是AOP? 简单理解:方法增强。 AOP可以增强方法的功能,而不需要修改原业务代码。 深入理解 从编程语言的角度:处理粒度不同 AOP是对OOP的扩展,OOP(即面向对象编程)能处理的最大粒度是对象,对OOP而言,当需要增强方法的功能时,必须修改类的定义。而AOP能处理的粒度可以深入到对象内部,可以是方法或者字段(Spring暂不支持字段增强),所以AOP可以使我们不用重新定义类,而增强原方法。 从设计模式的角度:AOP进一步降低了模块间的耦合度 使得业务代码和功能性代码分离,降低它们之间的耦合度。 功能性代码,如:事务处理、参数校验、日志、监控、负载均衡 从解放程序员生产力的角度:更少的代码 AOP只需要少量的配置或者注解就可以完成 从代码可读性的角度:业务逻辑更清晰 程序员可以更聚焦于业务逻辑。 AOP的核心是什么? 动态代理 AOP主要是做什么?(动态代理做什么?) 对那些被代理对象的那些方法在方法运行到那些时段做什么增强。 JDK动态代理 JDK动态代理不需要重写实现类,也不需要定义一个实现UserService接口的代理类。而是使用Proxy类帮我们动态生成代理类。 package day05 . Agent2 ; import day05 . Agent . UserService ; import java . lang . reflect . Proxy ;

Android JSON time conversion from Unix

白昼怎懂夜的黑 提交于 2019-12-25 08:53:10
问题 I asked this question earlier and got some great feedback, but I still wasn't able to get my program running correctly. The Basics: Its a scheduling app. I am trying to get a field in my JSON feed to be converted into a human readable time/date and display in my ListView adaptor. In the code below I am pulling in a string called "ShowDate" that contains the Unix timestamp. Right now (before I added SimpleDateFormat) the string displays the Unix code. When I added the SimpleDateFormat my

yyyy-mm-dd and hh:mm (PM/AM) convert into long

和自甴很熟 提交于 2019-12-25 08:27:38
问题 I have two strings: String date = "2011-11-11" String time="11:00 PM" i want to merge this date and time and convert them into a long, similar to System.currentTimeMillis(). 回答1: try this it is working fine String inputDate=date+" "+time ;; long parsedDate = HttpDateParser.parse(inputDate);//inputDate should 2011-12-11 11:10:00 PM" formate System.out.println("========================="+parsedDate); Date date=new Date(parsedDate); SimpleDateFormat date1=new SimpleDateFormat("yyyy-mm-dd hh:mm

get date from timestamp

旧街凉风 提交于 2019-12-25 04:45:51
问题 My code is: import java.text.*; import java.util.Date; public class DateEx { public static void main(String[] args) { //String valueFromDB = "2012/06/06 00:00:00"; String valueFromDB = "2012-12-31 00:00:00.0"; Date d = new Date(valueFromDB); SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy"); String dateWithoutTime = sdf.format(d); System.out.println("sdf.format(d) " + dateWithoutTime); } } It works for "2012/06/06 00:00:00" and I need to pass "2012-12-31 00:00:00.0" it is showing

new SimpleDateFormat(“hh:mm a”, Locale.getDefault()).parse(“04:30 PM”) giving Unparseable exception

↘锁芯ラ 提交于 2019-12-25 03:19:09
问题 Strange things happen at most desperate times. I'm experiencing a bit strange thing in this line of code Date time = new SimpleDateFormat("hh:mm a", Locale.getDefault()).parse("04:30 PM"); is giving "Unparseable date: \"04:30 PM\" (at offset 6)" exception in Android 6.0 and Android 6.0.1 devices only, in production app (on Google Play Store). PS: I'm unable to regenerate this bug on Android 6.0 Emulator & HTC Desire 10 Pro Android 6.0.1. Any help to regenerate this bug locally or how to way

Converting calendar to date in dd-MMM-yyyy format

爷,独闯天下 提交于 2019-12-25 03:01:06
问题 I am trying to add 17 days to 10-APR-2014 and convert the date to dd-MMM-yyy y format, but I am getting Sun Apr 27 00:00:00 GMT+05:30 2014 . Here is my code: import java.util.*; import java.text.*; public class HelloWorld{ public static void main(String []args){ SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yyyy"); Calendar c = Calendar.getInstance(); c.setTime(new Date()); c.add(Calendar.DATE, 17); String output = sdf.format(c.getTime()); System.out.println(output); System.out.print