signed

Is the conversion from '(signed) -1' to 'unsigned long' standardized? [duplicate]

大兔子大兔子 提交于 2019-12-10 19:48:58
问题 This question already has answers here : What happens if I assign a negative value to an unsigned variable? (5 answers) Closed last year . In this answer, you can find this comment: Strictly speaking the bit representations of the two numbers before conversion being the same doesn't matter. Even with 1's complement or signed magnitude representations, the conversion of (signed) -1 to unsigned long will always result in ULONG_MAX . (The bit pattern will be the same after conversion of course).

conversion of unicode string in python

心已入冬 提交于 2019-12-10 16:56:42
问题 I need to convert unicode strings in Python to other types such as unsigned and signed int 8 bits,unsigned and signed int 16 bits,unsigned and signed int 32 bits,unsigned and signed int 64 bits,double,float,string,unsigned and signed 8 bit,unsigned and signed 16 bit, unsigned and signed 32 bit,unsigned and signed 64 bit. I need help from u people. 回答1: use int() to convert the string to an integer. Python doesn't have different fixed-width integers so you'll just get one type of thing out.

Is it a best practice to use unsigned data types to enforce non-negative and/or valid values?

一世执手 提交于 2019-12-10 16:24:31
问题 Recently, during a refactoring session, I was looking over some code I wrote and noticed several things: I had functions that used unsigned char to enforce values in the interval [0-255]. Other functions used int or long data types with if statements inside the functions to silently clamp the values to valid ranges. Values contained in classes and/or declared as arguments to functions that had an unknown upper bound but a known and definite non-negative lower bound were declared as an

Calculating the maximum size of a signed integer

江枫思渺然 提交于 2019-12-10 09:46:26
问题 I wanted to know what the maximum value my time_t can hold was, so I wrote a little program helping me. It needs one argument: the amount of bytes (1 byte = 8 bits). So I wrote it and tested it. It goes well by all values from 1 untill 4, but at 5 and higher it also edits the "signed"-bit (I don't know how it's called). Can someone explain: #include <stdio.h> int main(int argc, const char **argv) { if(argc != 2) { fprintf(stderr, "Usage: %s bits/8\n", argv[0]); return -1; } unsigned int bytes

Invalid conversion from unsigned char* to char*

醉酒当歌 提交于 2019-12-10 01:36:44
问题 Here is a code - 1 int main(int argc, char *argv[]) 2 { 3 signed char S, *psc; 4 unsigned char U, *pusc; 5 char C, *pc; 6 7 C = S; 8 C = U; 9 10 pc = psc; 11 pc = pusc; 12 13 return 0; 14 } $ gcc test.cpp -o a test.cpp: In function ‘int main(int, char**)’: test.cpp:10:7: error: invalid conversion from ‘signed char*’ to ‘char*’ [-fpermissive] test.cpp:11:7: error: invalid conversion from ‘unsigned char*’ to ‘char*’ [-fpermissive] This is compiled on gcc version 4.6.3 on Ubuntu 12.10 on an

Why stores 255 in a char variable give its value -1 in C?

允我心安 提交于 2019-12-09 01:52:32
问题 I am reading a C book, and there is a text the author mentioned: " if ch (a char variable) is a signed type, then storing 255 in the ch variable gives it the value -1 ". Can anyone elaborate on that? 回答1: Assuming 8-bit char s, that is actually implementation-defined behaviour. The value 255 cannot be represented as a signed 8-bit integer. However, most implementations simply store the bit-pattern, which for 255 is 0xFF . With a two's-complement interpretation, as a signed 8-bit integer, that

would doing arithmetic operation on a pair of signed and unsigned numbers be legal?

◇◆丶佛笑我妖孽 提交于 2019-12-09 00:19:25
问题 I'm more than half way through learning assembly and I'm familiar with the concept of how signed and unsigned integers are presented in bits, I know that it might seem a weird question of which the answer would be pretty obvious, but I'm wondering if using an arithmetic operation like addition makes sense for a pair of numbers that one of them is considered signed and the other one unsigned, I've thought of multiple examples like below that will yield a correct result: 10000001 (1-byte

Convert Raw 14 bit Two's Complement to Signed 16 bit Integer

为君一笑 提交于 2019-12-08 15:38:39
问题 I am doing some work in embedded C with an accelerometer that returns data as a 14 bit 2's complement number. I am storing this result directly into a uint16_t . Later in my code I am trying to convert this "raw" form of the data into a signed integer to represent / work with in the rest of my code. I am having trouble getting the compiler to understand what I am trying to do. In the following code I'm checking if the 14th bit is set (meaning the number is negative) and then I want to invert

getting error while build signed apk ExternalSystemException: String index out of range: -97

夙愿已清 提交于 2019-12-08 07:33:13
问题 i m build signed apk and i have android studio 2.1.2 my build.gradle file as below apply plugin: 'com.android.application' android { compileSdkVersion 22 buildToolsVersion "22.0.1" defaultConfig { applicationId "com.my.pkg" minSdkVersion 15 targetSdkVersion 22 versionCode 1 versionName "1.0" multiDexEnabled true } buildTypes { release { minifyEnabled false proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro' } } dexOptions { preDexLibraries = false

Generated signed Apk successfully but when I try to Run my project, I get an error

核能气质少年 提交于 2019-12-08 04:52:25
问题 To release my application, I generated Signed APK ( Im using Android Studio). Signed APK was generated successfully. For key store path, I just created a folder in c>user>folder>name.keystore . I added an alias and password and successfully generated Signed APK. However, when I try to run my application on the emulator, I get the following error: app-release-unsigned.apk is not signed. Please configure the signing information for the selected flavor using the Project Structure dialog. Is