shortest-path

I have been searching for weeks for a way to compute shortest paths in JavaScript. I have been playing with the book Data Structures and Algorithms by Groner (aptly named) at https://github.com/loiane/javascript-datastructures-algorithms/tree/master/chapter09 . The trouble I keep on finding is that the code is so customized that it is almost impossible to rewrite to produce the desired results. I would like to be able to get the shortest path from any given vertex to any other, rather than, as Groner codes it, just the list of everything from A. I would like to be able to get, for example, the

Some days ago, Someone ask me, If we have some agents in our environment, and they want go from their sources to their destinations, how we can find the total shortest path for all of them such that they shouldn't have conflict during their walk. The point of problem is all agents simultaneously walking in environment (which can be modeled by undirected weighted graph), and we shouldn't have any collision. I thought about this but I couldn't find optimum path for all of them. But sure there are too many heuristic ideas for this problem. Assume input is graph G(V,E), m agents which are in: S 1

I'm studying graph theory and I have a question about the connection between minimum spanning trees and shortest path trees. Let G be an undirected, connected graph where all edges are weighted with different costs . Let T be an MST of G and let T s be a shortest-path tree for some node s . Are T and T s guaranteed to share at least one edge? I believe this is not always true, but I can't find a counterexample. Does anyone have a suggestion on how to find a counterexample? I think that this statement is actually true , so I doubt you can find a counterexample. Here's a hint - take any node in

I have a directed, positive weighted graph. Each edge have a cost of use. I have only A money, i want to calculate shortest paths with dijkstra algorithm, but sum of edges costs on route must be less or equal to A. I want to do this with most smallest Dijstra modification (if I can do it with small modification of Dijkstra). I must do this in O(n*log(n)) if I can, but i think i can. Anyone can help me with this? IVlad https://www.spoj.pl/problems/ROADS/ The problem was given at CEOI '98 and its official solution can be found here . You don't really need to modify Dijkstra's algorithm to do