set

Comparing two sets in python

我只是一个虾纸丫 提交于 2019-12-11 16:51:33
问题 Hi guys,i have a doubt regarding comparing two sets >>> x = {"a","b","1","2","3"} >>> y = {"c","d","f","2","3","4"} >>> z=x<y >>> print(z) False >>> z=x>y >>> print(z) False In the above logic,for both z=x<y and z=x>y . I'm getting output as False,whereas one of the expression should return True. Could anyone explain me why? 回答1: The < and > operators are testing for strict subsets. Neither of those sets is a subset of the other. {1, 2} < {1, 2, 3} # True {1, 2} < {1, 3} # False {1, 2} < {1,

How can I remove all instances of a single set item in set A from set B?

旧时模样 提交于 2019-12-11 16:45:18
问题 As you can see below, when I open test.txt and put the words into a set, the difference of the set with the common_words set is returned. However, it is only removing a single instance of the words in the common_words set rather than all occurrences of them. How can I achieve this? I want to remove ALL instances of items in common_words from title_words from string import punctuation from operator import itemgetter N = 10 words = {} linestring = open('test.txt', 'r').read() //set A, want to

which container to use map or set or else?

≡放荡痞女 提交于 2019-12-11 16:21:27
问题 If using std::map<std::string,object> to keep objects ordered by name, the map's value_type ( std::pair<string,object> ) is a convenient class which warrants useful functionality, e.g. typedef std::map<std::string,object> object_map; typedef typename object_map::value_type named_object; void function(named_object const&); // with the following possible use case void foo(std::string const&name, object_map const &omap) { auto obj=omap.find(name); if(obj==omap.end()) throw std::runtime_error(

How to use FIND_IN_SET in MySQL?

爷,独闯天下 提交于 2019-12-11 16:16:15
问题 How to use FIND_IN_SET, The values I have is | Val | | No, 1, Yes,5, O, 4| I tried doing FIND_IN_SET('No', Val) And got the value of 1 and then I tried: FIND_IN_SET('No', Val) as 'No', FIND_IN_SET('Yes', Val) as ''Yes' But got the output | No | Yes | | 1 | 0 | How come it suddenly can't find the 'Yes' in the text? Another format: | Val | | No, 1, Yes,5, O, 4 | Note: This is not on 3 rows, just on one row but using the next line(line breaks) for the other values 回答1: Because the actual value

Converting Hibernate's PersistentSet into CopyOnWriteArraySet

北战南征 提交于 2019-12-11 16:14:29
问题 I am using CopyOnWriteArraySet in the following class because I simply like its thread-safe iterator. public class MyClass{ Set _children = new CopyOnWriteArraySet(); public void setChildren(Set children){ _children = children; } public Set getChildren(){ return _children; } } However, I also use Hibernate for persistency which replaces my CopyOnWriteArraySet with its own PersistentSet (which uses HashSet internally). Unfortunately, HashSet is not thread-safe, so I want my CopyOnWriteArraySet

comparing values in a set

為{幸葍}努か 提交于 2019-12-11 16:14:25
问题 so my code currently generates a set with random integers between 1 and 200. It does this by using a while loop to add values to the set. What I'm having trouble doing is comparing values in a set to see if 2 values are duplicated. If they are, I want to return a bool value or an actual print statement saying they are duplicates. Similarly, I would want to stop generating a set if the duplicate is found within this def abc(c): a = 1 my = set() while a <= c: b = randrange(1, 200) my.add(b) a =

Finding the Intersection of the paired-typed Lists (collection of strings) in Python 3.7?

倖福魔咒の 提交于 2019-12-11 15:44:39
问题 Suppose I am having the following paired-typed lists. I want to calculate the intersection of these lists to generate only the common words not the numbers . The lists are l1 = [('state', 3537), ('t', 2320), ('system', 2086), ('transition', 1882), ('φ', 1703), ('path', 1423), ('ϕ', 1310), ('formula', 1273), ('property', 1194), ('π', 1165), ('α', 1065), ('ctl', 1048), ('action', 1034), ('ψ', 881), ('finite', 845), ('model', 828), ('algorithm', 790), ('process', 734), ('checking', 701), (

MDX DateAdd function over a set of tuples

梦想的初衷 提交于 2019-12-11 15:06:20
问题 I am trying to create a set of dates using DateAdd() function but I am getting errors while trying to pass a set of tuples as parameter. The below code returns a member but I am looking for a set of new dates. WITH Member [EFF INJ DT] AS DATEADD("M",12, [INJURY DATE].CurrentMember) SELECT {[EFF INJ DT]} ON COLUMNS, [INJURY DATE].[DATE].Members ON ROWS FROM [WVWC DATA CUBE FROI SROI] I have the following attempt: WITH Set [EFF INJ DT] AS DATEADD("M",12, [INJURY DATE].CurrentMember) SELECT {

How to update a slice set, in an elegant way?

…衆ロ難τιáo~ 提交于 2019-12-11 14:56:01
问题 First, I want the top 250 users, and update their top = 1 users = MyTable.objects.order_by('-month_length')[0: 250] for u in users: u.top = 1 u.save() But, actually, I hope there is an elegent way, like this: MyTable.objects.all().update(top=1) And more, from this question: Django: Cannot update a query once a slice has been taken Does that mean CAN NOT WRITE UPDATE ... WHERE ... LIMIT 5 ? 回答1: Until the queryset has been evaluated once (at which point it will cache itself), slicing result in

Implicit definition working for Seq but not for Set

元气小坏坏 提交于 2019-12-11 14:49:22
问题 So I've made some utility classes and implicit conversions for them. However, it works fine when converting from a Seq but not from a Set, although the code is the same, and those two traits seem rather similar at first sight. What could be the problem, and how would I fix it? import scala.collection.mutable.HashMap trait Indexed[T] { def index: T } class IndexMap[T, V <: Indexed[T]] extends HashMap[T, V] { override def put(key: T, value: V): Option[V] = { require(key == value.index) super