set

问题 If you create a local repository by: git init Then how to set a default remote for git push so if you create a new branch and want to git push its commits you don't need to specify the remote destination? Take into account that the local repository is not cloned form a remote and just initialized so it does not have any commits to be pushed nor branches. so far I only managed to set the remote for the master because it is the default name for the first branch but this does not solve the

问题 This question already has answers here : How to convert int[] into List<Integer> in Java? (18 answers) Closed 2 years ago . I have code that looks like this: int[] ho = new int[10]; ho[0]= 1; ho[2]= 1; ho[4]= 5; HashSet<Integer> hs = new HashSet(Arrays.asList(ho)); Integer[] a = hs.toArray(new Integer[hs.size()]); This code makes perfect sense to me, but it throws an ArrayStoreException when I run it. Why is that? The HashSet is a set of Integer s, and so is the output array. 回答1:

问题 Suppose I have some function which returns a struct: (struct layer (points lines areas)) (define (build-new-layer height) ... (layer list-a list-b list-c)) I want to keep track of the last returned result something like: (define top-side (build-new-layer 0)) ; store the first result ... (set! top-side (build-new-layer 0.5)) ; throw away the first result and store the new one However, for that particular code I get the error: set!: assignment disallowed; cannot modify a constant constant: top

问题 I need to sort a Set of String's which holds number. Ex: [15, 13, 14, 11, 12, 3, 2, 1, 10, 7, 6, 5, 4, 9, 8] . I need to sort it to [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15] . But when i use Collections.sort(keyList); where keyList is Set, the reult i obtained is [1, 10, 11, 12, 13, 14, 15, 2, 3, 4, 5, 6, 7, 8, 9] . Please help. 回答1: Write a custom comparator and parse it as argument to Collections.sort(Collection,Comparator) . One solution is parsing your Strings to Integers.

问题 Recently I had an interview and I was asked one question. I have 2 sets with around 1 Million records each. I have to find the common element in 2 sets. My response: I will create a new empty Set. And i gave him below solution but he was not happy with it. He said there are 1 million records so the solution won't be good. public Set<Integer> commonElements(Set<Integer> s1, Set<Integer> s2) { Set<Integer> res = new HashSet<>(); for (Integer temp : s1) { if(s2.contains(temp)) { res.add(temp); }

问题 I'm pretty confused on how to go about this. Say I have two columns in a dataframe. One column a numerical series in order (x), the other specifying some value from the first, or -1 (y). These are results from a matching experiment, where the goal is to see if multiple photos are taken of the same individual. In the example below, there 10 photos, but 6 are unique individuals. In the y column, the corresponding x is reported if there is a match. y is -1 for no match (might as well be NAs). If

问题 I'm having trouble finding the intersection of an Array of Hashed Sets that contain a data Class (where I want to intersect by identifier): class Protein(val id: String, val score: Double, val molw: Double, val spc: Int) I've pulled in some data from a .csv file into this type of structure: ArrayList<HashSet<Protein>> So I have six array lists [1 for each csv], each containing one hashed set that contains thousands of Protein structures. Here's what I've tried so far to get an intersection

问题 So I have this piece of code that is suppose to fetch users from the database and store them in an Array (drivingUsers). I get no errors but when I run the app it crashes. func fetchUser() { FIRDatabase.database().reference().child("user_profiles").observe(.childAdded, with: { (snapshot) in if let dictionary = snapshot.value as? [String: AnyObject] { let user = User() user.setValuesForKeys(dictionary) //Error self.drivingUsers.append(user) DispatchQueue.main.async { self.tableView.reloadData(

问题 I am trying to use a python set as a filter for ids from a mysql table. The python set stores all the ids to filter (about 30 000 right now) this number will grow slowly over time and I am concerned about the maximum capacity of a python set. Is there a limit to the number of elements it can contain? 回答1: Your biggest constraint is the amount of memory on your computer. Try the line: s = set(xrange(10000000)) That creates a set of length 10 million, much larger than the 30,000 you give as an

问题 Suppose I have a set of tuples with people's names. I want to find everyone who shares the same last name, excluding people who don't share their last name with anyone else: # input names = set([('John', 'Lee'), ('Mary', 'Miller'), ('Paul', 'Ryan'), ('Bob', 'Ryan'), ('Tina', 'Lee'), ('Bob', 'Smith')]) # expected output {'Lee': ['Tina', 'John'], 'Ryan': ['Bob', 'Paul']} # or similar This is what I am using def find_family(names): result = {} try: while True: name = names.pop() if name[1] in