set

Fastest way to search a list in python

て烟熏妆下的殇ゞ 提交于 2019-12-27 17:37:12
问题 When you do something like "test" in a where a is a list does python do a sequential search on the list or does it create a hash table representation to optimize the lookup? In the application I need this for I'll be doing a lot of lookups on the list so would it be best to do something like b = set(a) and then "test" in b ? Also note that the list of values I'll have won't have duplicate data and I don't actually care about the order it's in; I just need to be able to check for the existence

How to set and get fields in struct's method

北城以北 提交于 2019-12-27 17:03:52
问题 After creating a struct like this: type Foo struct { name string } func (f Foo) SetName(name string){ f.name=name } func (f Foo) GetName string (){ return f.name } How do I create a new instance of Foo and set and get the name? I tried the following: p:=new(Foo) p.SetName("Abc") name:=p.GetName() fmt.Println(name) Nothing gets printed, because name is empty. So how do I set and get a field inside a struct? 回答1: Commentary (and working) example: package main import "fmt" type Foo struct { name

How to set and get fields in struct's method

折月煮酒 提交于 2019-12-27 17:03:28
问题 After creating a struct like this: type Foo struct { name string } func (f Foo) SetName(name string){ f.name=name } func (f Foo) GetName string (){ return f.name } How do I create a new instance of Foo and set and get the name? I tried the following: p:=new(Foo) p.SetName("Abc") name:=p.GetName() fmt.Println(name) Nothing gets printed, because name is empty. So how do I set and get a field inside a struct? 回答1: Commentary (and working) example: package main import "fmt" type Foo struct { name

std::set with user defined type, how to ensure no duplicates

血红的双手。 提交于 2019-12-27 12:09:55
问题 So I have an std::set which needs to keep specific ordering as well as not allowing duplicates of a user defined (by me) type. Now I can get the order to work correctly by overloading the '<' operator in my type. However, the set does not appropriately detect duplicates, and to be honest I'm not entirely sure how it does this internally. I have overloaded the '==' operator, but somehow im not sure this is what the set is actually using? So the question is how does the set determine duplicates

std::set with user defined type, how to ensure no duplicates

有些话、适合烂在心里 提交于 2019-12-27 11:57:50
问题 So I have an std::set which needs to keep specific ordering as well as not allowing duplicates of a user defined (by me) type. Now I can get the order to work correctly by overloading the '<' operator in my type. However, the set does not appropriately detect duplicates, and to be honest I'm not entirely sure how it does this internally. I have overloaded the '==' operator, but somehow im not sure this is what the set is actually using? So the question is how does the set determine duplicates

std::set with user defined type, how to ensure no duplicates

两盒软妹~` 提交于 2019-12-27 11:57:09
问题 So I have an std::set which needs to keep specific ordering as well as not allowing duplicates of a user defined (by me) type. Now I can get the order to work correctly by overloading the '<' operator in my type. However, the set does not appropriately detect duplicates, and to be honest I'm not entirely sure how it does this internally. I have overloaded the '==' operator, but somehow im not sure this is what the set is actually using? So the question is how does the set determine duplicates

Creating Set in F# with elements from 1111 to 6666

风格不统一 提交于 2019-12-25 18:54:27
问题 How do i create a Set in F# with elements from 1111 to 6666 without any values being 0, 7 or higher. E.g. [1111,1112,1113,1114,1115,1116,1121] I'd like to make it a set. Thanks in advance 回答1: You can use a sequence comprehension: let values = seq { for i in 1110 .. 10 .. 6660 do for j in 1 .. 6 do yield i + j } and create a set using Set.ofSeq e.g. let s = Set.ofSeq values 回答2: There must be an easier way than: let values = seq { for a in 1000 .. 1000 .. 6000 do for b in 100 .. 100 .. 600 do

Creating Set in F# with elements from 1111 to 6666

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-25 18:54:08
问题 How do i create a Set in F# with elements from 1111 to 6666 without any values being 0, 7 or higher. E.g. [1111,1112,1113,1114,1115,1116,1121] I'd like to make it a set. Thanks in advance 回答1: You can use a sequence comprehension: let values = seq { for i in 1110 .. 10 .. 6660 do for j in 1 .. 6 do yield i + j } and create a set using Set.ofSeq e.g. let s = Set.ofSeq values 回答2: There must be an easier way than: let values = seq { for a in 1000 .. 1000 .. 6000 do for b in 100 .. 100 .. 600 do

how get a value from xml tag to hand over to a variable and to compare the value in a for-each loop

二次信任 提交于 2019-12-25 18:44:34
问题 i would like to get a value from certain xml tag and hand over to a variable for compare the same value in for-each loop. I make a screenshot for the xsl code understanding: And i make a screenshot for the xml code understanding: Here is my xsltransform code example. Here my XML Code: <?xml version="1.0" encoding="UTF-8"?> <unidatenbank> <studenten> <student> <daten> <matrikelnummer>2354444</matrikelnummer> <vorname>Horst</vorname> <nachname>Wallenstein</nachname> <geburtsdatum>09.09.1999<

I want to perform a multi-set intersection using C++

爷,独闯天下 提交于 2019-12-25 18:34:55
问题 I am using std::set<int> and multi-set classes std::multiset<int> to perform some set operations - union, intersection etc. The problem is that I have to perform intersection between two multi-sets such that I also get the duplicate values. The intersection works fine when I use it with simple sets (not multi-sets) e.g. Set1={1,2,3,4,5,6} Set2={4,5,6,7,8,9} then the std::set_intersection give me a correct result which is {4,5,6} However, if I have a multiset multi-set1{1,1,2,2,3,3,4,4,5,5,6,6