seq

I can make a sequence of numbers like this: s = seq(from=1, to=10, by=1) How do I make a sequence of characters from A-Z? This doesn't work: seq(from=1, to=10) Use LETTERS and letters (for uppercase and lowercase respectively). Use the code you have with letters and/or LETTERS : > LETTERS[seq( from = 1, to = 10 )] [1] "A" "B" "C" "D" "E" "F" "G" "H" "I" "J" > letters[seq( from = 1, to = 10 )] [1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j" Just use the predefined variables letters and LETTERS . And for completeness, here it something using seq : R> rawToChar(as.raw(seq(as.numeric(charToRaw('a')),

Bash allows me to write the statement, $ for i in {h..k} ; do echo $i ; done but zsh only allows number list expansion such as {8..13} . What's the best workaround? Something like seq for characters... As this is still a top google result, an updated answer: The current release supports bash style {c1..c2} where c1 and c2 are characters: An expression of the form ‘ {c1..c2} ’, where c1 and c2 are single characters (which may be multibyte characters), is expanded to every character in the range from c1 to c2 in whatever character sequence is used internally. For characters with code points

What are good examples of when seq_along will work, but seq will produce unintended results? From the documentation of ?seq we have: Note that it dispatches on the class of the first argument irrespective of argument names. This can have unintended consequences if it is called with just one argument intending this to be taken as along.with : it is much better to use seq_along in that case. This should make the difference clear. Basically, seq() acts like seq_along() except when passed a vector of length 1, in which case it acts like seq_len() . If this ever once bites you, you'll never use seq

I have a dataset that looks like this: ID created_at MUM-0001 2014-04-16 MUM-0002 2014-01-14 MUM-0003 2014-04-17 MUM-0004 2014-04-12 MUM-0005 2014-04-18 MUM-0006 2014-04-17 I am trying to introduce new column that would be all dates between start date and defined last day (say, 12th-july-2015). I used seq function in dplyr but getting an error. data1 <- data1 %>% arrange(ID) %>% group_by(ID) %>% mutate(date = seq(as.Date(created_at), as.Date('2015-07-12'), by= 1)) the error which I am getting is: Error: incompatible size (453), expecting 1 (the group size) or 1 Can you please suggest some

I want to produce such file (cartesian product of [1-3]X[1-5] ) : 1 1 1 2 1 3 1 4 1 5 2 1 2 2 2 3 2 4 2 5 3 1 3 2 3 3 3 4 3 5 I can do this using nested loop like: for i in $(seq 3) do for j in $(seq 5) do echo $i $j done done is there any solution without loops? Combine two brace expansions ! $ printf "%s\n" {1..3}" "{1..5} 1 1 1 2 1 3 1 4 1 5 2 1 2 2 2 3 2 4 2 5 3 1 3 2 3 3 3 4 3 5 This works by using a single brace expansion: $ echo {1..5} 1 2 3 4 5 and then combining with another one: $ echo {1..5}+{a,b,c} 1+a 1+b 1+c 2+a 2+b 2+c 3+a 3+b 3+c 4+a 4+b 4+c 5+a 5+b 5+c A shorter (but hacky)

I need to implement a method that return a Scala Seq , in Java. But I encounter this error: java.util.ArrayList cannot be cast to scala.collection.Seq Here is my code so far: @Override public Seq<String> columnNames() { List<String> a = new ArrayList<String>(); a.add("john"); a.add("mary"); Seq<String> b = (scala.collection.Seq<String>) a; return b; } But scala.collection.JavaConverters doesn't seem to offer the possibility to convert as a Seq . JavaConverters is what I needed to solve this. import scala.collection.JavaConverters; public Seq<String> convertListToSeq(List<String> inputList) {