send

Java Multicast Sending Data, Not Receiving

ぃ、小莉子 提交于 2019-12-01 17:47:51
问题 I am writing a class in Java which is used to greatly simplify the process of multicasting. However, I am having two big problems with it: The class sends data (I can verify this with my net monitor, Wireshark) but the data is not received by any others in the same group. On some machines, the sending packet TTL is exceeded in transit (again, according to Wireshark). Could anyone please help me? I've been trying and searching for answers for hours, and it appears that my code follows all of

Java Multicast Sending Data, Not Receiving

ぐ巨炮叔叔 提交于 2019-12-01 17:25:33
I am writing a class in Java which is used to greatly simplify the process of multicasting. However, I am having two big problems with it: The class sends data (I can verify this with my net monitor, Wireshark) but the data is not received by any others in the same group. On some machines, the sending packet TTL is exceeded in transit (again, according to Wireshark). Could anyone please help me? I've been trying and searching for answers for hours, and it appears that my code follows all of the basic procedures for connecting to, joining, sending, and receiving data from a multicast host. Here

MPI_SEND stops working after MPI_BARRIER

筅森魡賤 提交于 2019-12-01 10:52:05
I'm building a distributed web server in C/MPI and it seems like point-to-point communication completely stops working after the first MPI_BARRIER in my code. Standard C code works after the barrier, so I know that each of the threads makes it through the barrier. Point-to-point communication also works just fine before the barrier. However, when I copy-paste the same code that worked the line before the barrier into the line after the barrier it stops working entirely. The SEND will just wait forever. When I try using an ISEND instead, it makes it through the line, but the message is never

Send sms permission doesn't work

邮差的信 提交于 2019-12-01 10:39:06
I want to send a simple message and i have <uses-permission android:name="android.permission.SEND_SMS"/> in my manifest, but I always get: java.lang.SecurityException: Sending SMS message: uid 10064 does not have android.permission.SEND_SMS. I checked this answer , but it still doesn't work. this is my manifest: <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.roa.sendsms" > <uses-permission android:name="android.permission.SEND_SMS"/> <application android:allowBackup="true" android:icon="@mipmap/ic_launcher" android:label

MPI_SEND stops working after MPI_BARRIER

走远了吗. 提交于 2019-12-01 07:48:55
问题 I'm building a distributed web server in C/MPI and it seems like point-to-point communication completely stops working after the first MPI_BARRIER in my code. Standard C code works after the barrier, so I know that each of the threads makes it through the barrier. Point-to-point communication also works just fine before the barrier. However, when I copy-paste the same code that worked the line before the barrier into the line after the barrier it stops working entirely. The SEND will just

Send sms permission doesn't work

淺唱寂寞╮ 提交于 2019-12-01 07:15:29
问题 I want to send a simple message and i have <uses-permission android:name="android.permission.SEND_SMS"/> in my manifest, but I always get: java.lang.SecurityException: Sending SMS message: uid 10064 does not have android.permission.SEND_SMS. I checked this answer, but it still doesn't work. this is my manifest: <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.roa.sendsms" > <uses-permission android:name="android

How to send a email in VC++?

百般思念 提交于 2019-11-30 23:42:00
I am new to VC++ and programming. I have to write code to send a email in VC++. How do I go about it? Please help!! Here's how I do it with the ATL classes. I think you need one of the paid versions of VC++ to get ATL. You will need the name of your email server. CSMTPConnection smtp; if (!smtp.Connect(m_strEmailServer)) return false; // start generating the email message; remember to call CoInitialize somewhere in the app before this CMimeMessage msg; msg.SetSubject(m_strSubject); msg.SetSender(m_strSender); // repeat the following as necessary msg.AddRecipient(strSingleRecipient); msg

The queue does not exist or you do not have sufficient permissions to perform the operation. exception while sending message via MSMQ

别等时光非礼了梦想. 提交于 2019-11-30 17:34:02
问题 I have created a function to send message via MSMQ but getting exception while executing. below is my function. public void SendMessageToQueue(ChessQueue chessQueue) { MessageQueue queue = null; Message m = null; if (!MessageQueue.Exists(".\\Private$\\" + chessQueue.QueueName)) { queue = new MessageQueue(".\\Private$\\chessqueue"); chessQueue.Messages = new List<MessageObject>(); chessQueue.Messages.Add(chessQueue.Message); queue.Formatter = new BinaryMessageFormatter(); m = new Message(); m

Sending email using Zend Framework and PHP

社会主义新天地 提交于 2019-11-30 14:23:49
I working on a form whereby when the user enter in their email account and click on send, an email will be sent to their email account. I have everything worked out. Just that it doesnt send the email to my account. Anyone have any ideas? Is there a configuration that I left out or something? This is the sample from my controller: public function retrieveemailAction(){ $users = new Users(); $email = $_POST['email']; $view = Zend_Registry::get('view'); if($users->checkEmail($_POST['email'])) { // The Subject $subject = "Email Test"; // The message $message = "this is a test"; // Send email //

十四.生成器

ぐ巨炮叔叔 提交于 2019-11-30 11:25:14
2019-09-24-23:24:24 一.什么时生成器?   1.生成器的实质就是迭代器 二.生成器的获取方式   1.通过生成器函数   2.通过各种推导式获取生成器   3.通过数据转换获取生成器 三..案例 #这个是一个简单函数,怎样变成生成器呢? def func(): print("111") return 222 ret = func() print(ret) #将函数中的return换成yield就是生成器 def func(): print("111") yield 222 ret = func() print(ret) 四.yield和return的区别 def func(): print("111") yield 222 print("333") yield 444 gener = func() ret = gener.__next__() print(ret) ret2 = gener.__next__() print(ret2) ret3 = gener.__next__() # 最后⼀一个yield执行完毕. 再次__next__()程序报错, 也就是说和return⽆关了. print(ret3) yield是通过分段执行函数,执行了yield不会立即停止函数的运行,而执行完return是直接就停止函数的运行了 注意:执行完yield这个函数后