sed

问题 I am trying to extract the To header from an email file using sed on linux. The problem is that the To header could be on multiple lines. e.g: To: name1@mydomain.org, name2@mydomain.org, name3@mydomain.org, name4@mydomain.org, name5@mydomain.org Message-ID: <46608700.369886.1549009227948@domain.org> I tried the following: sed -n -e '/^[Tt]o: / { N; p; }' _message_file_ | awk '{$1=$1;printf("%s ",$0)};NR%2==0{print ""}' The sed command extracts the line starting with To and next line. I pipe

问题 $ cat file aaa bbb ccc ddd eee jjj kkk lll mmm nnn ooo ppp The following AWK command will paste the 'mmm' line at the end of the 'ddd eee' line. Is there a simpler way to do this using AWK or sed? $ awk 'FNR==NR {if (NR==4) foo=$0; next} FNR==2 {print $0" "foo; next} FNR==4 {next} 1' file file aaa bbb ccc ddd eee mmm jjj kkk lll nnn ooo ppp To clarify: I want to paste line 4 at the end of line 2 in this particular file, with a single space between the 'ddd eee' and the 'mmm'. That's the task.

问题 $ cat file aaa bbb ccc ddd eee jjj kkk lll mmm nnn ooo ppp The following AWK command will paste the 'mmm' line at the end of the 'ddd eee' line. Is there a simpler way to do this using AWK or sed? $ awk 'FNR==NR {if (NR==4) foo=$0; next} FNR==2 {print $0" "foo; next} FNR==4 {next} 1' file file aaa bbb ccc ddd eee mmm jjj kkk lll nnn ooo ppp To clarify: I want to paste line 4 at the end of line 2 in this particular file, with a single space between the 'ddd eee' and the 'mmm'. That's the task.

问题 $ cat file aaa bbb ccc ddd eee jjj kkk lll mmm nnn ooo ppp The following AWK command will paste the 'mmm' line at the end of the 'ddd eee' line. Is there a simpler way to do this using AWK or sed? $ awk 'FNR==NR {if (NR==4) foo=$0; next} FNR==2 {print $0" "foo; next} FNR==4 {next} 1' file file aaa bbb ccc ddd eee mmm jjj kkk lll nnn ooo ppp To clarify: I want to paste line 4 at the end of line 2 in this particular file, with a single space between the 'ddd eee' and the 'mmm'. That's the task.

问题 i need to remove all multibyte characters from a file, i dont know what they are so i need to cover the whole range. I can find them using grep like so: grep -P "[\x80-\xFF]" 'myfile' Trying to do a simular thing with sed, but delete them instead. Cheers 回答1: Give this a try: LANG=C sed 's/[\x80-\xFF]//g' filename 回答2: you can use iconv to convert from one encoding to another 来源： https://stackoverflow.com/questions/3521106/removing-multibyte-characters-from-a-file-using-sed

问题 i need to remove all multibyte characters from a file, i dont know what they are so i need to cover the whole range. I can find them using grep like so: grep -P "[\x80-\xFF]" 'myfile' Trying to do a simular thing with sed, but delete them instead. Cheers 回答1: Give this a try: LANG=C sed 's/[\x80-\xFF]//g' filename 回答2: you can use iconv to convert from one encoding to another 来源： https://stackoverflow.com/questions/3521106/removing-multibyte-characters-from-a-file-using-sed

问题 I wrote a BASH file that features multiple embedded loops of the form for P in {'0.10','0.20', [...] '0.90','1.00'}; do for Q in {'0.10','0.20', [...] ,'0.90','1.00'}; do [...] I use these variables both as parameters for a command line application, and to create file names directly in BASH. I would like to create duplicates, say $P_REP=0_10 that replaces the dot by an underscore without writting a explicit switch statement for every case, or some hardcoded equivalent. The (non-elegant way) I

问题 I have a file containing the following lines (3 fields delimited by space): component1 /dev/user/test 12344 component2 master abcefa123 component3 trunk 72812 component4 /branch/user/integration bc89fa component5 trunk 989091 component6 integration/test bc7829ac component7 /branch/dev/user/various eded34512 I need to manipulate the field 2 to cut its long prefix (same as you do in bash with ${string##*}) and to get the following result: component1 test 12344 component2 master abcefa123

问题 I am writing a sed command that should uncomment an entry in crontab. Is there a better way to do this? The first option that comes to mind is sed. Example: crontab -l # 5 * * * 3 bash test.sh The sed command should uncomment this entry. This is what I have now. sed "s#\# 5 * * * 3 bash test.sh#5 * * * 3 bash test.sh#" Obviously this sed command doesn't do the task. ps:the sed command will eventually make its way into a script. 回答1: Sed is great for matching specific regular expressions and

问题 I am writing a sed command that should uncomment an entry in crontab. Is there a better way to do this? The first option that comes to mind is sed. Example: crontab -l # 5 * * * 3 bash test.sh The sed command should uncomment this entry. This is what I have now. sed "s#\# 5 * * * 3 bash test.sh#5 * * * 3 bash test.sh#" Obviously this sed command doesn't do the task. ps:the sed command will eventually make its way into a script. 回答1: Sed is great for matching specific regular expressions and