scientific-notation

This question already has an answer here: Format double value in scientific notation 4 answers I'm writing a program that deals with planets' mass and diameter; These quantities are expressed in scientific notation. My question is NOT, mind you, NOT how does one print large numbers the right way (That's using printf(), duh), its how I would... "type" these numbers, I guess you could say. For example, the mass of mercury is expressed: 3.30 x 10ˆ23 And in my array of planet masses, an element would look: 33.0 * Math.pow(10, 23) However, I don't quite think this is the right way - it looks like

I need help converting a string that contains a number in scientific notation to a double. Example strings: "1.8281e-009" "2.3562e-007" "0.911348" I was thinking about just breaking the number into the number on the left and the exponent and than just do the math to generate the number; but is there a better/standard way to do this? PHP is typeless dynamically typed, meaning it has to parse values to determine their types (recent versions of PHP have type declarations ). In your case, you may simply perform a numerical operation to force PHP to consider the values as numbers (and it

I've read here ( How to prevent numbers being changed to exponential form in Python matplotlib figure ) and here ( Matplotlib: disable powers of ten in log plot ) and tried their solutions to no avail. How can I convert my y-axis to display normal decimal numbers instead of scientific notation? Note this is Python 3.5.2. Here's my code: #Imports: import matplotlib.pyplot as plt possible_chars = 94 max_length = 8 pw_possibilities = [] for num_chars in range(1, max_length+1): pw_possibilities.append(possible_chars**num_chars) x = range(1, max_length+1) y = pw_possibilities #plot plt.figure() plt

I've got a database filled up with doubles like the following one: 1.60000000000000000000000000000000000e+01 Does anybody know how to convert a number like that to a double in C++? Is there a "standard" way to do this type of things? Or do I have to roll my own function? Right now I'm doing sth like this: #include <string> #include <sstream> int main() { std::string s("1.60000000000000000000000000000000000e+01"); std::istringstream iss(s); double d; iss >> d; d += 10.303030; std::cout << d << std::endl; } Thanks! Something like this? This would be the "C++" way of doing it... #include <sstream

I have a some items that I want to partition in to a number of buckets, such that each bucket is some fraction larger than the last. items = 500 chunks = 5 increment = 0.20 {- find the proportions -} sizes = take chunks (iterate (+increment) 1) base = sum sizes / items buckets = map (base *) sizes main = print buckets I'm sure there is a mathematically more elegant way to do this, but that's not my question. The end step is always printing out in scientific notation. How do I get plain decimal output? I've looked at the Numeric package but I'm getting nowhere fast. Claudiu Try printf . e.g.: >