scheduling

I found when using select on multiple non buffered channels like select { case <- chana: case <- chanb: } Even when both channels have data, but when processing this select, the call that falls in case chana and case chanb is not balanced. package main import ( "fmt" _ "net/http/pprof" "sync" "time" ) func main() { chana := make(chan int) chanb := make(chan int) go func() { for i := 0; i < 1000; i++ { chana <- 100 * i } }() go func() { for i := 0; i < 1000; i++ { chanb <- i } }() time.Sleep(time.Microsecond * 300) acount := 0 bcount := 0 wg := sync.WaitGroup{} wg.Add(1) go func() { for {

I thought about which factors would influence the static scheduling overhead in OpenMP. In my opinion it is influenced by: CPU performance specific implementation of the OpenMP run-time library the number of threads But am I missing further factors? Maybe the size of the tasks, ...? And furthermore: Is the overhead linearly dependent on the number of iterations? In this case I would expect that having static scheduling and 4 cores, the overhead increases linearly with 4*i iterations. Correct so far? EDIT: I am only interested in the static (!) scheduling overhead itself. I am not talking about

I'm working on an exercise on the textbook "Operating System Concepts 7th Edition", and I'm a bit confused about how does fork() work. From my understanding, fork() creates a child process which runs concurrently with its parent. But then, how do we know exactly which process runs first? I meant the order of execution. Problem Write a C program using fork() system call that generates the Fibonacci sequence in the child process. The number of sequence will be provided in the command line. This is my solution: #include <sys/types.h> #include <stdlib.h> #include <stdio.h> #include <unistd.h> void