scheduling

问题 Say I want to schedule a collection of events in the period 00:00–00:59. I schedule them on full minutes (00:01, never 00:01:30). I want to space them out as far apart as possible within that period, but I don't know in advance how many events I will have total within that hour. I may schedule one event today, then two more tomorrow. I have the obvious algorithm in my head, and I can think of brute-force ways to implement it, but I'm sure someone knows a nicer way. I'd prefer Ruby or

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed last year . I have a long BigQuery script that I want to execute from file in Google App Script service. I can save it in BigQuery, in Google Docs, BigQuery view or anywhere which allows me to run it from App Script. The goal is to schedule its running in Google App script, manually copy pasting it like in BigQuery

问题 I want to use the process_flag(priority, Level) to set the priority of a process. I am a little confused as to where it should go in my code and can't seem to find an example. The two options that I can see are: (1) Set the flag before spawning the process: process_flag(priority, max), register(myprocess, spawn(fun() -> myprocess() end)), (2) Set the flag within the function after it has been spawned: myprocess() -> process_flag(priority, max), %do stuff Also, if option 1 is correct, do I

问题 What is the best way to schedule an event? I was thinking about the new Calendar API, but it requires an internet connection at least to create a new calendar. Is there any API for creating a schedule which doesn't require internet connection? 回答1: Check out the FAQ You are more likely to keep getting help if you go back to your previous questions and accept answers that were helpful to you. Also see How does accepting an answer work? for more info. AlarmManager will let you do that. If you

问题 Cannot make it works ... In my config/schedule.rb I have : set :output, '../log/development.log' every 5.minutes do runner "UserWatchedRepo.update" end Note the log setted, but nothing happen. In my Rails 3.0.10 model file app/models/user_watched_repo.rb I get : class UserWatchedRepo include Mongoid::Document def update conn = FaradayStack.build 'https://api.github.com' User.all.map do |user| nickname = user.nickname resp = conn.get "/users/#{nickname}/watched" resp.body.each do |repo| user

问题 I have a function that I want to call, say, 10 times per second. I start out with code like this: while True: the_operation() time.sleep(1.0/TIMES_PER_SECOND) This works ok but the_operation is called slightly less often than desired, because of the time to do the operation itself. We can make the code look like this instead: while True: t = time.time() the_operation() time_to_sleep = 1.0/TIMES_PER_SECOND - (time.time() - t) if time_to_sleep > 0: time.sleep(time_to_sleep) This is better, but

问题 There are a couple of other similar questions on SO, but none of them have satisfactory/relevant answers. I have a single threaded C++ program which does something essentially like this: while(true) { //do things which are cpu bound } The problem is that when I run this program it is usually the only process on my whole computer that is doing active work. With nothing else to schedule, the OS naturally schedules this program heavily and my CPU usage shoots through the roof, which I do not

问题 After hours of braining I've finally crashed and have come to result that I have no clue how to implement round robin into java. I've tried different approaches and the closest I've got.. well i explain with an example.. AT = Arrival Time BT = Burst Time (Execution Time) At first i have this row of numbers (0,5;6,9;6,5;15,10) where elements in position 0-2-4 represent arrival times and elements in position 1-3-5 represent burst times. My code is so far that this input is turned into a class,

问题 Can there be more than two scheduling policies working at the same time in Linux Kernel ? Can FIFO and Round Robin be working on the same machine ? 回答1: Yes, Linux supports no less then 4 different scheduling methods for tasks: SCHED_BATCH, SCHED_FAIR, SCHED_FIFO and SCHED_RR. Regardless of scheduling method, all tasks also have a fixed hard priority (which is 0 for batch and fair and from 1- 99 for the RT schedulign methods of FIFO and RR). Tasks are first and foremost picked by priority -

问题 Just to head off any comments to the effect of "why do you need to know this??": This is just a puzzle I was curious about, not something I need to do for any practical reason. Given a typical POSIX system[1], how would you design an experiment to determine the scheduling quantum[2] of a CPU-bound process? [1]: but NOT one that lets you query for this information through a syscall or /proc interface [2]: "Scheduling quantum" is defined as the amount of time a process will run on the CPU