Python tkFileDialog.asksaveasfile - get file path
问题 I want to get path of file "exportFile". exportFile = tkFileDialog.asksaveasfile(mode='a') If I write "print exportFile", I get: <open file u'C:/Users/Desktop/Test/aaaa.txt', mode 'a' at 0x02CB6078> But I need only path - "C:/Users/Desktop/Test/aaaa.txt". Is there any solution? Thank you. 回答1: Use tkFileDialog.asksaveasfilename instead of tkFileDialog.asksaveasfile . NOTE tkFileDialog.asksaveasfilename does not take mode parameter. 回答2: Try this: exportFile = tkFileDialog.asksaveasfile(mode=