sas-macro

问题 I want to find to find extreme values produced by a macro as a function of input parameters: For example purposes here is some data: data Input_data; input X Y; cards; 10 15 20 18 30 27 33 41 ; run; The following is not the actual formula (as the minimum for this is easily found analytically.) and I want computational method. For examples sake I have semi-empirical rule, which takes three parameters in: %macro Function(const1, const2 const3); data output; set input; X_eff1=((X > &const1.)*(X

问题 The dataset looks like this: colx coly colz 0 1 0 0 1 1 0 1 0 Required output: Colname value count colx 0 3 coly 1 3 colz 0 2 colz 1 1 The following code works perfectly... ods output onewayfreqs=outfreq; proc freq data=final; tables colx coly colz / nocum nofreq; run; data freq; retain colname column_value; set outfreq; colname = scan(tables, 2, ' '); column_Value = trim(left(vvaluex(colname))); keep colname column_value frequency percent; run; ... but I believe that's not efficient. Say I

问题 I've used call symputx to create a list of macro variables Item 1 to Item N and now I want to transfer them to an array in another datastep so that spot 1 in the array gets Item1, spot 2 gets Item2, etc. do j=1 to &num_OR; rulesUsed{j}=&&Item&j; end; I read that the double ampersand syntax is the way to reference macro variables like this but I keep getting all sorts of errors. I'm sure there's a simple way around this but I'm new to SAS and no document I've read through that's come up in

问题 just would like to compare cell entries and return values. coustmer_NO id A1 A2 A3 A4 1 5 10 20 45 0 1 13 0 45 2 5 2 4 0 10 7 8 2 3 7 9 55 0 2 10 0 0 0 0 3 4 90 8 14 3 3 10 20 7 4 15 how to count the ID that has (value > 030) for each customer_no then, the min number of values before 030 appears. The expected output would be something like: cosutmer_no , count_ac_num , values 1 2 1 2 1 1 3 1 3 回答1: I would recommend converting to a more vertical structure. Then you can begin trying to apply

问题 So I have this code that works well for one year, but I need to convert it as a loop so it works for years from 1970 to 2015. Here is the code for 1 year that I specify in a %let statement. %let year=1970 rsubmit; data home.historical_returns_&year; set home.crspdata; where (year <= &year - 1) and (year >= &year - 5); returns_count + 1; by id year; if first.id or missing(tot_ret) then returns_count = 1; run; endrsubmit; So far, that code works great for me. Now, I am trying to use a loop so I

问题 Working on a macro function to return the modified date of a file as a SAS date, that will run on Linux (SAS 9.3). I want to avoid using OS commands (e.g. piping the results of an LS command) as code needs to work in an environment with NOXCMD. Below is a first draft (no error handling code, etc), using finfo(). Was disappointed by the format of the date returned by finfo(), e.g."Fri Apr 10 14:54:10 2015". Then was more disappointed by my inability to input() this string without the ugly

问题 OK I'll start with the problem: I have product tables being created every week which are named in the format: products_20130701 products_20130708 . . . I'm trying to automate some campaign analysis so that I don't have to manually change the table name in the code every week to use whichever product table is the first one after the maximum end date of my campaign. e.g %put &max_enddate.; /*20130603*/ my product tables in June are: products_20130602 *products_20130609* products_20130616

问题 The following example is very simple and might be solvable in an easier way. However, I am interested in making it work. The following example is based on the cars-dataset of the sashelp-library. First, I have a macro called fun: proc contents data = sashelp.cars out = mycontents; run; %macro fun(var); proc sql noprint; select count(distinct(&var.)) into :obs from sashelp.cars; quit; %mend; Now I want to call the macro but only to update obs (from the input statement). I use: data work.test;

问题 I have one question regaring %macro. Can I set %macro in another %macro? Short example - "picture" of situation: %macro Tier_1(); %do Iter = 1 to &i; %macro Tier_2() proc sql noprint; select 1*&Iter into :var from work._PRODSAVAIL ;quit; %put &var; %mend; %Tier_2(); %end; %mend; %Tier_1(); 回答1: The answer to your question is "yes, it is possible." But it's poor style. The identical results from above will occur if you simply move the macro definition for %Tier_2 outside of macro Tier_1, but

问题 This question already has an answer here : Prompt or Macro Variables used in calculations (1 answer) Closed last year . I have a data set like this; DATA work.faminc; INPUT famid faminc1-faminc12 ; CARDS; 1 3281 3413 3114 2500 2700 3500 3114 3319 3514 1282 2434 2818 2 4042 3084 3108 3150 3800 3100 1531 2914 3819 4124 4274 4471 3 6015 6123 6113 6100 6100 6200 6186 6132 3123 4231 6039 6215 ; RUN; I can create a variable and do some stuff with it like, %let N=12; DATA faminc1b; SET faminc ;