routing

问题 Android devices has back button on menu toolbar. I want to disable the possibility when i login to my app and click on that back button to route on login page. I want if user click on back button after login then i close the app. Here is my initial code for routing below. if (token) { this.router.navigate(['/main-tabs/tabs/dashboard']) } else { this.router.navigate(['/login']).then(); } 回答1: I've tried many other answers but none of them really works for me. But this one works : To disallow

问题 How should I define route in my global.asax to be able use nullable parameters and coma as separator? I'm trying to implement routing rule for my search users page like "{Controller}/{Action},{name},{page},{status}" Full entry from the Global.asax: routes.MapRoute( "Search", "{controller}/{action},{name},{page},{status}", new { controller = "User", action = "Find", name = UrlParameter.Optional, page = UrlParameter.Optional, status = UrlParameter.Optional } ); Routine defined like above works

问题 Explain me please, how these two techniques differs. I assume, based on my experience described below and this article, that when routing is applied, PageHandlerFactory is not called. I have my own class derived from PageHandlerFactory that should be called whenever a user access a page. When I don't access pages through routes, everything is just fine with this line of code in web.config <httpHandlers> <add verb="*" path="*.aspx" type="MyProject.Web.DependencyInjectionPageHandlerFactory,

问题 I have a weird problem with routing. I have an existing website that I am trying to add this to. It works, but only if .aspx is on the end of the URL. If I remove the .aspx, it gives me an error: "The resource cannot be found." I created a quick test website and copied the code over to it, it works just fine. The code between the 2 are identical. Both are running on the VS 2008 web server. I just don't get it. Any ideas? Thanks, Vincent 回答1: Okay, I found the problem. I don't understand why

问题 Can anyone tell me what is the syntax for retreiving the actual URL for the "Default" Route? I'd like to do something like: string url = RouteTable.Routes["Default"].ToString(); //(even though that code is completely wrong) so that I could have the url value of the route available to work with. So far, I've been trying the .GetVirtualPath() method, but that only returns the route data for the current controller. thanks Dave 回答1: A route can match any number of urls. So a route doesn't have a

问题 I'm trying to have the navigation on my Vue app to have a main menu up top populated by all the root level routes, and a side menu if the route has any children. Like so: The current Design I have has the main navigation with routing links on the top with the router-view below. I have been able to get the side menu working so it it only shows up when I choose Travellers and updates the components/content correctly. However I'm having trouble routing things correctly, when I click on one of

问题 I want handle the requests to my application "http://example.com/whateverpath" by a custom HttpHandler but the return things depending of the value of "whateverpath". So users accessing "http://example.com/path1" will get different response than users accessing "http://example.com/path2", but both request must be handled in the same HttpHandler. The idea is find "whateverpath" in a database and depending of the result, return the response content. I hear about URL routing and I already have a

问题 I try add global parameter Parameter for all routes, and parameter setup in kernel Request Listener. routing mea_crm: resource: @Crm4Bundle/Resources/config/routing.yml prefix: /{_applicationid} defaults: { _applicationid: 0 } requirements: _applicationid: |0|1|2|3|4|5|6 in Listener - { name: kernel.event_listener, event: kernel.request, method: onKernelRequest } I try setup this parameter $request->attributes->add(array( '_applicationid'=>$appCurrentId )); $request->query->add( array( '

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . I have a system with 2 interfaces eth0 , and eth1 . eth0 is 192.168.0.250 and connected to gateway 192.168.0.2 . eth1 is connected to 192.123.123.10 via a swtich. I am trying to route packets from 192.123.123.10 to gateway 192.168.0.2 , which means I need to route 192.123.123.x packets coming into eth1 interface

问题 I am trying to use a broadcast router in Scala, if I'm not mistaken it should look like this: val system = ActorSystem("My beautiful system") val workerRouter = system.actorOf(Props[Agent].withRouter(BroadcastRouter(individualDefinitions.size)), name = "agentRouter") That is what I understand from the tutorial I am following. The workerRouter acts as another actor and I can send messages to this router that will send them to all the Agents (as many as individualDefinitions I have). The