router

hide id or query string while passing through react router

由 送分小仙女□ 提交于 2019-12-07 08:47:41
问题 i am having route where i pass id,but i dont want to show id in url, `<Route path={`${match.url}invite-members/:groupID`} exact component={InviteMembers} />` this gets converted in url https://local..../invite-members/5, but instead of that i want https://local..../invite-members, but the functionality should remain the same as in i get id in invite-members through this.props.match.params.groupID should be as it is,please help using react router "react-router-dom": "^4.2.2", 回答1: If you want

React redux connect with with styles and withrouter

由 不想你离开。 提交于 2019-12-07 08:20:42
问题 I am trying to use connect in redux react as Connect (mapstate.., mapdis..) (withstyles(dashboardstyle)(dashboard) The above works fine but I need to add withRouter as well. Below change gives error Connect (mapstate.., mapdis..) (withstyles(dashboardstyle), withrouter(dashboard)) Whenever I add it gives exception such as cannot use class as a function. Any ideas how this can be fixed 回答1: You will need to install recompose: npm i -s recompose Then in your component: import compose from

Angular 2 - issue with bootstrap nav <li><a href=“#header”></a></li> in routing set up

由 白昼怎懂夜的黑 提交于 2019-12-07 08:10:29
am trying to converting normal bootstrap page into components in Angular 2. am actually facing issues when constructing navigation. initially the tags <li><a href></a></li> is like below <div id="header" class="shadow"> <!-- Navigation --> <nav> <div class="nav nav-wrapper navbar-fixed-top"> <div class="container-fluid"> <!-- Menu Option --> <ul class="nav-justified hide-on-med-and-down"> <li><a href="#header">About</a></li> <li><a href="#prodcutInfo">Prod.Info</a></li> <div id="side-nav"> <div id="nav-header"> <div id="nav-profile" class="center-block"> <!-- Profile Picture [Square] --> <img

How to get Wi-Fi router IP address on iOS?

由 情到浓时终转凉″ 提交于 2019-12-07 04:46:52
问题 Is there any way to get Wi-Fi router IP address on iOS from my application? With help of getifaddrs(struct ifaddrs **) method I can get interface address, subnet mask, broadcast address, but cannot get router address. I have found a lot of solutions for Mac OS, but not for iOS. Any solutions for iOS? 来源： https://stackoverflow.com/questions/24887904/how-to-get-wi-fi-router-ip-address-on-ios

angular2 using router.subscribe to watch url change

由 做~自己de王妃 提交于 2019-12-07 03:16:43
问题 I'm using router.event.subscribe @angular/router to watch the url change to execute an if statement though event.subscribe works fine. But my question is how can I avoid repeating my if statement just to show the title on these urls. It's probably something else than router.subscribe but not sure what to use for this. basically wanted a dynamic title based on the url you are on. this._router.events.subscribe((event) => { console.log('route changed'); if(this.location.path() == '/1'){ this

How is source port for HTTP determined? Is there ever collision in NAT?

由 匆匆过客 提交于 2019-12-06 17:29:14
问题 I know that when a HTTP request is made, packets are sent from a seemingly-random high-numbered port (e.g. 4575) on the client to port 80 on the server. Then the server sends the reply to the same high-numbered port, the router knows to route that to the client computer, and all is complete. My question is: How is the return port (4575 in this example) determined? Is it random? If so, within what range? Are there any constraints on it? What happens, for example, if two computers in a LAN send

emberjs: add routes after app initialize()

由 让人想犯罪 __ 提交于 2019-12-06 10:48:43
i run into the following problem when building a router based app with emberjs. My app is simplified structured as following: var App = Em.Application.create({}); App.ApplicationController = Em.Controller.extend({}); App.ApplicationView = Em.View.extend({ template : Em.Handlebars.compile('APPLICATION TEMPLATE') }); App.RootState = Em.Route.extend({ index : Em.Route.extend({ route : "/" }) }) App.Router = Em.Router.extend({ root : App.RootState }); // initialize the app here App.initialize(); // extend the RootState from anywhere. eg. from a plugged widget App.RootState.reopen({ login : Em

React Router - Stay at the same page after refresh

由 半腔热情 提交于 2019-12-06 08:05:17
问题 I'm learning React. I have page with 4 subpages and i use React Router to go through those pages. Everything works fine except for reloading page. When i go from page "home" to "about" or other it's ok, but when i refresh page then it render again page "about" for a second and then it change page to home (home is default/first page).I want it to stay at that page which is currently rendered, not go back to home after every refresh. There is my code in index.js file where i render whole app

How do I connect to router “panel” using C#

由 两盒软妹~` 提交于 2019-12-06 06:26:48
I'm trying to connect to my router "panel" (192.168.1.1) using a simple C# HTTP Web Request: var userName = "admin"; var passWord = "admin"; var encoding = new ASCIIEncoding(); var postData = "" + userName; postData += (":" + passWord); //I saw (using Wireshark) that the HTTP packet is sending the username & password in this form: "username:password" byte[] data = encoding.GetBytes(postData); var myRequest = (HttpWebRequest)WebRequest.Create("http://192.168.1.1"); myRequest.Method = "POST"; **//Or should I use GET?** myRequest.ContentType = "application/x-www-form-urlencoded"; myRequest

Android TCP communication over the internet(not LAN).

由 喜夏-厌秋 提交于 2019-12-06 04:39:51
I'm creating an app to establish communication between two android mobiles through the internet using TCP sockets. So, I'll primarily be using ip addresses of the two mobiles with my fancy app port no. Is this possible? To create custom TCP ports and communicate over the internet like in a LAN? So far i'm able to successfully communicate between two emulators in a LAN . But it's not possible to do the same thorugh the internet in case of emultors cos usually the host machine is behind a router that allows only data to the port 8080 or 80 i'm not sure. Of course there are port forwarding that
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