rome

java.io.FileNotFoundException for valid URL

两盒软妹~` 提交于 2019-12-01 03:51:39
I use library rome.dev.java.net to fetch RSS. Code is URL feedUrl = new URL("http://planet.rubyonrails.ru/xml/rss"); SyndFeedInput input = new SyndFeedInput(); SyndFeed feed = input.build(new XmlReader(feedUrl)); You can check that http://planet.rubyonrails.ru/xml/rss is valid URL and the page is shown in browser. But I get exception from my application java.io.FileNotFoundException: http://planet.rubyonrails.ru/xml/rss at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1311) at com.sun.syndication.io.XmlReader.<init>(XmlReader.java:237) at com.sun.syndication

数据类型及内置方法1

此生再无相见时 提交于 2019-11-29 10:17:59
零、 可变类型:值改变的情况下,id不变 不可变类型:只改变的情况下,id变化 有序:但凡有索引的数据都是有序的 一、整型 用途 存qq号,手机号,不带字母的身份证号码 定义方式 age = 18 可变or不可变 不可变 进制转换 其他进制转十进制 # 二进制转十进制 10 —— 1 * (2 ** 1) + 0 * (2 ** 0) # 八进制转十进制 235 —— 2 * (8 ** 2) + 3 * (8 ** 1) + 5 * (8 ** 0) # 十六进制转十进制 217 —— 2 * (16 ** 2) + 1 * (16 ** 1) + 5 * (8 ** 0) int 可以传第二个参数,表示第一个参数是什么进制,然后转成十进制 - print(int('1100', 2)) - print(int('14', 8)) - print(int('c', 16)) 十进制转其他进制 - 十进制转二进制 print(bin(12)) # 0b1100 - 十进制转八进制 print(oct(12)) # 0o14 - 十进制转十六进制 print(hex(12)) # 0xc 二、字符串 描述 定义方式 ‘ ’ “ ” ‘’‘ ’‘’ 有序 or 无序 有序 可变 or 不可变 不可变 操作和内置方法 按索引取值 s = 'hello world' print(s[0])

谚语摘录

北城余情 提交于 2019-11-26 14:23:04
谚语摘录 Tempora mutantur nos et mutamur in illis. (时光流转,吾等亦随之而变。) No property, that is, no personality. (无财产,即无人格。) Custom makes all things easy.(有个好习惯,事事皆不难。) Actions speak louder than words.(事实胜于雄辩。) Look before you leap.(摸清情况再行动。) Man proposes, God disposes.(谋事在人,成事在天。) Easy come easy go.(来得易,去得易) When in Rome,do as the Romans do。( 身在罗马,就做罗马人 ) All roads lead to Rome。(条条大路通罗马。) Rome was not built in a day. (罗马不是一日建成的) Every day is not Sunday.(好景不常在) Nothing brave, nothing have. (不入虎穴,焉得虎子。) Hope for the best, but prepare for the worst. (抱最好的愿望,做最坏的打算。) One swallow does not make a summer.(一燕不成夏

How to write an RSS feed with Java?

◇◆丶佛笑我妖孽 提交于 2019-11-26 08:48:38
I'm using Java, and need to generate a simple, standards-compliant RSS feed. How can I go about this? Ben Hoffstein I recommend using Rome : // Feed header SyndFeed feed = new SyndFeedImpl(); feed.setFeedType("rss_2.0"); feed.setTitle("Sample Feed"); feed.setLink("http://example.com/"); // Feed entries List entries = new ArrayList(); feed.setEntries(entries); SyndEntry entry = new SyndEntryImpl(); entry.setTitle("Entry #1"); entry.setLink("http://example.com/post/1"); SyndContent description = new SyndContentImpl(); description.setType("text/plain"); description.setValue("There is text in here

How to write an RSS feed with Java?

老子叫甜甜 提交于 2019-11-26 02:00:59
问题 I\'m using Java, and need to generate a simple, standards-compliant RSS feed. How can I go about this? 回答1: I recommend using Rome: // Feed header SyndFeed feed = new SyndFeedImpl(); feed.setFeedType("rss_2.0"); feed.setTitle("Sample Feed"); feed.setLink("http://example.com/"); // Feed entries List entries = new ArrayList(); feed.setEntries(entries); SyndEntry entry = new SyndEntryImpl(); entry.setTitle("Entry #1"); entry.setLink("http://example.com/post/1"); SyndContent description = new