rollup

SQL SERVER T-SQL Calculate SubTotal and Total by group

只愿长相守 提交于 2019-12-01 05:55:53
I am trying to add subtotal by group and total to a table. I've recreated the data using the following sample. DECLARE @Sales TABLE( CustomerName VARCHAR(20), LegalID VARCHAR(20), Employee VARCHAR(20), DocDate DATE, DocTotal Int, DueTotal Int ) INSERT INTO @Sales SELECT 'Jhon Titor','12345', 'Employee1','2015-09-01',1000,200 INSERT INTO @Sales SELECT 'Jhon Titor','12345', 'Employee1','2015-08-20',500,100 INSERT INTO @Sales SELECT 'Jhon Titor','12345', 'Employee1','2015-08-18',200,50 INSERT INTO @Sales SELECT 'Deli Armstrong','2345', 'Employee1','2015-09-17',2300,700 INSERT INTO @Sales SELECT

Uncaught TypeError: this.method is not a function - Node js class export [duplicate]

戏子无情 提交于 2019-11-29 10:57:37
This question already has an answer here: How to access the correct `this` inside a callback? 10 answers I am new to node.js and I am trying to require a class. I have used https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Classes as reference. However, when I do this for example: // talker.js class Talker { talk(msg) { console.log(this.say(msg)) var t = setTimeout(this.talk, 5000, 'hello again'); } say(msg) { return msg } } export default Talker // app.js import Talker from './taker.js' const talker = new Talker() talker.talk('hello') I get: talker.js:4 Uncaught TypeError: this

oracle中group by的高级用法

半城伤御伤魂 提交于 2019-11-28 23:20:02
简单的group by用法 select c1,sum(c2) from t1 where t1<>'test' group by c1 having sum(c2)>100; rollup(多列)——上卷汇总,从最后一个汇总字段开始上卷汇总,一直到合计 select c1,c2,sum(c3) from t1 group by rollup(c1,c2) 含义: c1,c2分组合计 c1分组合计 总计 cube(多列)——组合汇总,以汇总字段的子集作为汇总条件汇总,包括合计 select c1,c2,sum(c3) from t1 group by cube(c1,c2) 含义: c1,c2分组合计 c1分组合计 c2分组合计 总计 grouping(单列名)只用于rollup和cube,单列名是rollup和cube中的一个列名,表示此记录的分组条件是否包含此列,1表示否,0表示是。 select decode(grouping(c1),1,'all c1',c1) as first, decode(grouping(c2),1,'all c2',c2) as second,sum(c3) from t1 group by cube(c1,c2) 含义: 使记录含义更清晰,而不是单纯的一个null值。 grouping sets(多列)——分列汇总,按参数中的各列分别汇总。

下一代前端打包工具与tree-shaking

荒凉一梦 提交于 2019-11-28 21:23:50
一、js模块化打包概述   随着js模块化规范AMD、CMD、commonJs的出现,模块打包工具也在不断的出现和演变,依次出现了r.js、browserify和webpack,过去的2015年就是webpack大行其道的一年,又随着reactjs、es6的出现,webpack更是深入人心,因为其人性化的特点和友好性,确实给前端模块打包带来了极大的方便。   不过今天并不是重点讲webpack,而是rollup,要了解webpack,可以看我的另一篇文章: http://ouvens.github.io/frontend-build/2015/04/01/webpack-tool.html ,在讲rollup之前先来看看几种之前的前端打包方案。 二、js模块化打包方案   先区分下几个不同概念:包管理工具(package manager)、模块加载器(module loader),打包工具(bundler),包管理器指管理安装js模块的这类,例如npm、bower、jspm这些,模块加载器指向requirejs、modjs、seajs这些,模块加载器又主要遵循AMD、CMD、Commonjs三种规范,打包工具则指r.js、browserify、webpack这类。 1、r.js   在grunt结合requirejs的年代,r.js作为通用标配的打包工具普世存在

Alias names to with rollup in SQL queries?

房东的猫 提交于 2019-11-28 12:03:27
I am using with rollup in my sql query. I am not getting alias name for rollup. My SQL is SELECT [Column1], sum([Column2]) FROM Tablea GROUP BY [Column2] WITH ROLLUP Which returns s 8 t 8 j 8 null 24 How can I replace the NULL in the total row? You can use the GROUPING function in a CASE expression. SELECT CASE WHEN GROUPING([Column1]) = 1 THEN 'Total' ELSE [Column1] END [Column1], sum([Column2]) FROM Tablea GROUP BY [Column1] WITH ROLLUP SQL Fiddle select isnull([column1],'rollup'), sum([column2] ) from tableA group by [column1] WITH ROLLUP Anurag Dwivedi SELECT ifnull([column1],'total'), sum

Sum with SQL server RollUP - but only last summary?

纵然是瞬间 提交于 2019-11-28 07:32:53
I have this query: DECLARE @t TABLE(NAME NVARCHAR(MAX),datee date,val money) insert INTO @t SELECT 'a','2012-01-02',100 insert INTO @t SELECT 'a','2012-01-02',100 insert INTO @t SELECT 'a','2012-01-03',100 insert INTO @t SELECT 'a','2012-01-05',100 insert INTO @t SELECT 'b','2012-01-06',200 insert INTO @t SELECT 'b','2012-01-07',200 insert INTO @t SELECT 'd','2012-01-07',400 insert INTO @t SELECT 'e','2012-01-09',500 insert INTO @t SELECT 'f','2012-01-12',600 SELECT Name,datee,SUM (val) from @t GROUP BY NAME ,datee currently the result is: BUT I need to add sum at the end. So I tried with

What is the difference between cube, rollup and groupBy operators?

依然范特西╮ 提交于 2019-11-28 03:57:57
Question is pretty much in the title. I can't find any detailed documentation regarding the differences. I do notice a difference because when interchanging cube and groupBy function calls, I get different results. I noticed that for the result using 'cube', I got a lot of null values on the expressions I often grouped by. These are not intended to work in the same way. groupBy is simply an equivalent of the GROUP BY clause in standard SQL. In other words table.groupBy($"foo", $"bar") is equivalent to: SELECT foo, bar, [agg-expressions] FROM table GROUP BY foo, bar cube is equivalent to CUBE

Sum with SQL server RollUP - but only last summary?

怎甘沉沦 提交于 2019-11-27 01:51:36
问题 I have this query: DECLARE @t TABLE(NAME NVARCHAR(MAX),datee date,val money) insert INTO @t SELECT 'a','2012-01-02',100 insert INTO @t SELECT 'a','2012-01-02',100 insert INTO @t SELECT 'a','2012-01-03',100 insert INTO @t SELECT 'a','2012-01-05',100 insert INTO @t SELECT 'b','2012-01-06',200 insert INTO @t SELECT 'b','2012-01-07',200 insert INTO @t SELECT 'd','2012-01-07',400 insert INTO @t SELECT 'e','2012-01-09',500 insert INTO @t SELECT 'f','2012-01-12',600 SELECT Name,datee,SUM (val) from

What is the difference between cube, rollup and groupBy operators?

我是研究僧i 提交于 2019-11-27 00:11:02
问题 Question is pretty much in the title. I can't find any detailed documentation regarding the differences. I do notice a difference because when interchanging cube and groupBy function calls, I get different results. I noticed that for the result using 'cube', I got a lot of null values on the expressions I often grouped by. 回答1: These are not intended to work in the same way. groupBy is simply an equivalent of the GROUP BY clause in standard SQL. In other words table.groupBy($"foo", $"bar") is

Uncaught TypeError: this.method is not a function - Node js class export [duplicate]

纵饮孤独 提交于 2019-11-26 23:29:43
问题 This question already has an answer here: How to access the correct `this` inside a callback? 10 answers I am new to node.js and I am trying to require a class. I have used https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Classes as reference. However, when I do this for example: // talker.js class Talker { talk(msg) { console.log(this.say(msg)) var t = setTimeout(this.talk, 5000, 'hello again'); } say(msg) { return msg } } export default Talker // app.js import Talker from '.