release

Recently I started to get this message randomly: Metadata file '...\Release\project.dll' could not be found in Visual Studio I have a solution with several projects in it. The current build mode is Debug and all projects' configurations are set to Debug. But when I try to run the main project - sometimes it gives me a few errors, all of which are "Metadata file '...\Release\projectX.dll' could not be found" - and, look, it says about RELEASE folder, though current mode is Debug. Why? I tried to search for reference to "Release\projectX.dll" inside all solution files, and I found one in

I want to upload my first APK/app to the Android Market, but I got this error (which did not lead me to the correct link when searched for in stackoverflow, by the way). Market does not accept apks signed with the debug certificate. Create a new certificate that is valid for at least 50 years. Market requires that the certificate used to sign the apk be valid until at least October 22, 2033. Create a new certificate. Though it turns out this question is similar, the guy just says "Oh, you reminded me of how to do it" without actually explaining. I've looked at the website referred to in the

Currently, I package the release builds with Nuget for the official builds to nuget.org, but I package the debug builds with Nuget for the symbol source pushes to symbolsource.org. EDIT: (Jon Skeet, with some bias from Noda Time development) NuGet now supports pushing to both NuGet gallery and symbolsource.org (or similar servers), as documented . Unfortunately, there are two contradictory requirements here: When just using a library without any need for debugging, you really want a release build. That's what release builds are for, after all. When debugging into a library for diagnostic

Using GitHub's Release feature , it is possible to provide a link to download a specific version of the published software. However, every time a release is made, the gh-page also needs to be updated. Is there a way to get a link to a specific file of whatever the latest version of a software is? e.g., this would be a static link: https://github.com/USER/PROJECT/releases/download/v0.0.0/package.zip What I'd like is something like: https://github.com/USER/PROJECT/releases/download/latest/package.zip NOTE: The difference between this question and GitHub latest release is that this question

Spring Cloud Config-Client 无法获取 Config-Server 在 github 上的配置文件的属性值，竟然是因为！！！ 2018年07月23日 16:33:25 一颗很菜的菜 阅读数 5907 版权声明：本文为博主原创文章，遵循 CC 4.0 by-sa 版权协议，转载请附上原文出处链接和本声明。 本文链接： https://blog.csdn.net/true1cc/article/details/81170079 Spring Cloud Config-Server 配置中心 配置文件放在github，配置文件均为bootstrap.yml（bootstrap.yml的优先级级比application.yml高，所以会先去github配置中心获取信息） 运行 Spring Cloud Config-Client 应用程序时，报错信息如下： java.lang.IllegalArgumentException: Could not resolve placeholder 'from' in value "${from}" at org.springframework.util.PropertyPlaceholderHelper.parseStringValue(PropertyPlaceholderHelper.java:172) ~[spring

I use to take always a look at the final binary executable or dll after debugging and creating a file with any IDE. Now I am trying Visual C++ 2010, in the search for the best release, without trash or unnecessary references. So, I created a new solution with two projects: a executable and its dll. VC++ created a lot of intermediary files between the code and the final file. I opened the .exe and the .dll with a hexadecimal editor and saw something that I don't like. Somewhere inside the file there's an absolute path to the .PDB file. Why? How can I remove it from VC++? There must be some pre

from threading import Thread, Lock, RLock import time ''' Rlock锁 也被称之为递归锁 第一个抢到Rlock锁的人,可以连续使用acquire,release 每acquire一次,锁身上计数加1 每release一次,锁身上计数减1 等锁身上的计数为0时,其他人就可以抢锁 ''' # mutexA = Lock() # mutexB = Lock() mutexA = mutexB = RLock() class MyThead(Thread): def run(self): # 创建线程时,会自动执行run方法 self.func1() self.func2() def func1(self): mutexA.acquire() print('%s 抢到了A锁' % self.name) mutexB.acquire() print('%s 抢到了B锁' % self.name) mutexB.release() print('%s 释放了B锁' % self.name) mutexA.release() print('%s 释放了A锁' % self.name) def func2(self): mutexB.acquire() print('%s 抢到了B锁' % self.name) time.sleep(1)

I've learned that in dealloc you do [object release]; but in viewDidUnload (in a UIViewController subclass) you do self.object = nil . What is really the difference because self.object = nil (we're assuming object is a (nonatomic, retain) property) retains nil (which does nothing) and then releases the old value and then the reference count is 0 right? smorgan self.object = nil calls your setter, which will release the old value, set the member to nil , and possibly do other things (it's a method, so it could do anything). The "anything" part of that is potentially dangerous; see this question