reference-parameters

Why can't I retrieve the value for parameters of type out or ref using Type.InvokeMember?

末鹿安然 提交于 2019-12-01 05:12:36
A long title, but I wanted it to be specific. The title is really the question. Even though the method that InvokeMember is calling has an out parameter and is assigning a value to to that parameter I can't grab that value. Here is the code I was initially using: string parameter = ""; int result = Convert.ToInt32(typeof(Ability).InvokeMember(selectedMove, BindingFlags.InvokeMethod | BindingFlags.Public | BindingFlags.Static, null, null, new object[] { parameter })); I changed it this, which now makes it work as intended but I don't know why: object[] args = new object[1]; //necessary to

Why can't I retrieve the value for parameters of type out or ref using Type.InvokeMember?

走远了吗. 提交于 2019-12-01 02:46:43
问题 A long title, but I wanted it to be specific. The title is really the question. Even though the method that InvokeMember is calling has an out parameter and is assigning a value to to that parameter I can't grab that value. Here is the code I was initially using: string parameter = ""; int result = Convert.ToInt32(typeof(Ability).InvokeMember(selectedMove, BindingFlags.InvokeMethod | BindingFlags.Public | BindingFlags.Static, null, null, new object[] { parameter })); I changed it this, which

C# property and ref parameter, why no sugar?

孤人 提交于 2019-11-27 00:59:48
I just ran across this error message while working in C# A property or indexer may not be passed as an out or ref parameter I known what caused this and did the quick solution of creating a local variable of the correct type, calling the function with it as the out / ref parameter and then assigning it back to the property: RefFn(ref obj.prop); turns into { var t = obj.prop; RefFn(ref t); obj.prop = t; } Clearly this would fail if the property doesn't support get and set in the current context. Why doesn't C# just do that for me? The only cases where I can think of where this might cause

How do I use Reference Parameters in C++?

陌路散爱 提交于 2019-11-26 18:16:50
I am trying to understand how to use reference parameters. There are several examples in my text, however they are too complicated for me to understand why and how to use them. How and why would you want to use a reference? What would happen if you didn't make the parameter a reference, but instead left the & off? For example, what's the difference between these functions: int doSomething(int& a, int& b); int doSomething(int a, int b); I understand that reference variables are used in order to change a formal->reference, which then allows a two-way exchange of parameters. However, that is the

C# property and ref parameter, why no sugar?

你。 提交于 2019-11-26 09:32:25
问题 I just ran across this error message while working in C# A property or indexer may not be passed as an out or ref parameter I known what caused this and did the quick solution of creating a local variable of the correct type, calling the function with it as the out / ref parameter and then assigning it back to the property: RefFn(ref obj.prop); turns into { var t = obj.prop; RefFn(ref t); obj.prop = t; } Clearly this would fail if the property doesn\'t support get and set in the current

How do I use Reference Parameters in C++?

China☆狼群 提交于 2019-11-26 06:14:55
问题 I am trying to understand how to use reference parameters. There are several examples in my text, however they are too complicated for me to understand why and how to use them. How and why would you want to use a reference? What would happen if you didn\'t make the parameter a reference, but instead left the & off? For example, what\'s the difference between these functions: int doSomething(int& a, int& b); int doSomething(int a, int b); I understand that reference variables are used in order