recompose

Using compose() and connect() together in React JS redux

与世无争的帅哥 提交于 2019-12-18 03:12:53
问题 I am starting to develop a web application using React JS. I bought a theme from theme forest. In the theme, they are using compose like this in the component. ...Other code here Login.propTypes = { classes: PropTypes.shape({}).isRequired, width: PropTypes.string.isRequired }; export default compose(withWidth(), withStyles(themeStyles, { withTheme: true }))(Login); As you can see their code is using the compose at the end when exporting the Component. I cannot modify their built-structure.

losing functions when using recompose component as ref

有些话、适合烂在心里 提交于 2019-12-10 23:36:23
问题 I have this simple component class App extends React.Component { a = () => null b = () => null c = () => null render() { return (<div>hey123</div>) } } and this is my 2nd component with ref to the first one class BApp extends React.Component { setComponentRef = ref => { console.log('ref', ref) this.playerComponentRef = ref } render() { return ( <div> <App ref={this.setComponentRef} /> </div>) } } in this case in the console.log I will receive all App component's functions (a, b, c) but if I

How do you add refs to functional components using withHandlers in Recompose and call ScrollTo on a ScrollView?

淺唱寂寞╮ 提交于 2019-12-09 09:28:32
问题 My specific goal is to use the ScrollTo method of a ScrollView but maintain functional component structure. More generally this requires getting ref to the current component which isn't possible with naked react native. In Dec 2016 recompose added Allows handlers property of withHandlers to be a factory function but I can't quite figure out how to use it correctly. How do you add refs to functional components using withHandlers in Recompose and call ScrollTo on a ScrollView? 回答1: You can try

How do I setState within React's recompose's lifecycle method?

主宰稳场 提交于 2019-12-04 16:33:11
问题 I am using recompose in my React project https://github.com/acdlite/recompose/ It's a great library. I'm using the compose utility as a container component that passes state down as props to the presentational component like so: const enhance = compose( lifecycle({ componentDidMount() { myCall .getResponse([productId]) .then(products => { setIsReady(true); }); }, }), withState('isAvailable', 'setIsAvailable', false), withState('isReady', 'setIsReady', false), mapProps(({ setIsAvailable,

recompose withState how to update on props changes

风流意气都作罢 提交于 2019-12-04 04:50:17
问题 I have a higher order component that I try to modify a bit (I'm not familiar with recompose). So thats my component: <Map mycenter={mycenter} /> I want the map-component to update or to rerendered if the mycenter is updated. I'm trying to modify the code from https://github.com/istarkov/google-map-thousands-markers/blob/master/src/Map.js I made some modifications to the code. First, the map center is set to mycenter. That works. withState('mapParams', 'setMapParams', ({ mycenter }) => ({

Using compose() and connect() together in React JS redux

巧了我就是萌 提交于 2019-11-30 11:51:46
I am starting to develop a web application using React JS. I bought a theme from theme forest. In the theme, they are using compose like this in the component. ...Other code here Login.propTypes = { classes: PropTypes.shape({}).isRequired, width: PropTypes.string.isRequired }; export default compose(withWidth(), withStyles(themeStyles, { withTheme: true }))(Login); As you can see their code is using the compose at the end when exporting the Component. I cannot modify their built-structure. What I like to do now is I like to use connect feature of the react as well. Normally connect is used in

React Recompose Causing Typescript Error On Props

£可爱£侵袭症+ 提交于 2019-11-29 11:57:30
I have a very basic stateful component where I'm using recompose to add multiple HOC to my component (in my example I only use one for simplicity). For some reason typescript is giving me an error regarding my props going into my component. How can I get rid of this error? Here's my code: import * as React from 'react'; import { connect } from 'react-redux'; import { compose } from 'recompose'; interface IStoreState { readonly sessionState: { authUser: { email: string; } } } interface IAccountPageProps { authUser: { email: string } } const AccountPage = ({ authUser }: IAccountPageProps ) =>

React Recompose Causing Typescript Error On Props

谁说我不能喝 提交于 2019-11-28 05:21:21
问题 I have a very basic stateful component where I'm using recompose to add multiple HOC to my component (in my example I only use one for simplicity). For some reason typescript is giving me an error regarding my props going into my component. How can I get rid of this error? Here's my code: import * as React from 'react'; import { connect } from 'react-redux'; import { compose } from 'recompose'; interface IStoreState { readonly sessionState: { authUser: { email: string; } } } interface

Typescript: change function type so that it returns new value

别等时光非礼了梦想. 提交于 2019-11-28 00:29:54
Basically, I want something like this: export type ReturnValueMapper<Func extends (...args: Args[] /* impossible */ ) => any, ReturnValue> = (...args: Args[]) => ReturnValue; I'm almost sure that it's impossible, but I haven't found exact confirmation. The use case is improving types for recompose's withStateHandlers , enabling defining state updaters like this: interface StateUpdaters { update(field: string): void; // I don't want to specify Partial<State> here } Edit Since the original question was answered typescript has improved the possible solution to this problem. With the addition of

Typescript: change function type so that it returns new value

不问归期 提交于 2019-11-26 17:04:41
问题 Basically, I want something like this: export type ReturnValueMapper<Func extends (...args: Args[] /* impossible */ ) => any, ReturnValue> = (...args: Args[]) => ReturnValue; I'm almost sure that it's impossible, but I haven't found exact confirmation. The use case is improving types for recompose's withStateHandlers, enabling defining state updaters like this: interface StateUpdaters { update(field: string): void; // I don't want to specify Partial<State> here } 回答1: Edit Since the original