React Native Open settings through Linking.openURL in IOS
问题 I want to open ios setting app from my app. the settings destination is [ settings => notification => myapp ]. to turn on & turn off push notification. There are some documents about how to link to settings, but I don't know how to open deep link. (notification => myapp). How can I do this? 回答1: You can deep-link referencing the settings's index like so: Linking.openURL('app-settings:') Above method only for IOS 回答2: Since React Native 0.60 to open App settings use: Linking.openSettings() 回答3