raw-input

I'm using Zed Shaw's Learn Python the Hard Way . In exercise 11, the code produces an EOF error on line 2. Here is the code: 1 print "How old are you?", 2 age = raw_input() 3 print "How tall are you?", 4 height = raw_input() 5 print "How much do you weigh?", 6 weight = raw_input() 7 print "So, you're %r old, %r tall and %r heavy." % ( age, height, weight) I have searched StackOverflow, Google, and Hacker News forum. I could not find any answer that (a) solved this problem and (b) I could understand. I am using the python compiler on ideone.com (have also tried two other on-line compilers and

I was wondering if anyone has suggestions for writing a backwards-compatible input() call for retrieving a filepath? In Python 2.x, raw_input worked fine for input like /path/to/file. Using input works fine in this case for 3.x, but complains in 2.x because of the eval behavior. One solution is to check the version of Python and, based on the version, map either input or raw_input to a new function: if sys.version_info[0] >= 3: get_input = input else: get_input = raw_input I'm sure there is a better way to do this though. Anyone have any suggestions? Since the Python 2.x version of input() is

I wanted to understand the behaviour of raw_input in the below code. I know num will be string. Irrespective of whatever number i enter it always enter the elif part i.e. if num is 5, which should go to if num<check: part or if num is 10 which should go to else part. Every single time it is going to elif . I thought comparing STRING and INT might throw exception( I dont think so) but just in case, so I had included try except but as expected it did not throw any exception. But what puzzles me is why it is ALWAYS hitting elif even when the input given was 10, atleast in that case i was