ranking

Possible Duplicate: Mysql rank function I have the following countryTable country clicks ------- ------ 0 222 66 34 175 1000 45 650 How do I get the ranking of say country 45 which is 2 in this case? Ordered by country ASC : SELECT 1+COUNT(*) AS ranking FROM countryTable WHERE country < 45 ; Ordered by clicks DESC : SELECT 1+COUNT(*) AS ranking FROM countryTable AS t JOIN countryTable AS c ON c.clicks > t.clicks WHERE t.country = 45 ; You can get 2 rank as below it like below: Select * from tabeName order by clicks limit 1,1 For 3 rank: Select * from tabeName order by clicks limit 2,1 SELECT *

I have a table called 'winners' with columns 'id', 'category', 'score', 'rank'. I need to update my table and asign a rank within the subcategories (category_id) which as per the sample is 2 but could be more than that in the future. Most anwers I've found are based around select statements which simply tends to just output the table view but I did find a very good 'Update' answer ( https://stackoverflow.com/a/2727239/4560380 ) specifically the answer update where ties are required to share the same rank. Sample CREATE TABLE winners ( id int, category_id int, score double, rank int ); INSERT

What function do I need to use to rank first four most popular words in list in R program? For example, c("apple", "banana", "apple", "banana", "banana", "desk", "pen", "pen", "pen", "pen") to make it like "pen" "banana" "apple" "desk" Thank you You can sort the tabled values in decreasing order and then take the names to get the output you're looking for. Try this: > x <- c("apple", "banana", "apple", "banana", "banana", "desk", "pen", "pen", "pen", "pen") > names(sort(table(x), decreasing = TRUE)) ## [1] "pen" "banana" "apple" "desk" table is intuitive for base R. Here's a qdap approach:

I have a table that I would like to be able to present "ranked X out of Y" data for. In particular, I'd like to be able to present that data for an individual row in a relatively efficient way (i.e. without selecting every row in the table). The ranking itself is quite simple, it's a straight ORDER BY on a single column in the table. Postgres seems to present some unique challenges in this regard; AFAICT it doesn't have a RANK or ROW_NUMBER or equivalent function (at least in 8.3, which I'm stuck on for the moment). The canonical answer in the mailing list archives seems to be to create a

I am attempting to store the rank of users based on a score, all it one table, and skipping ranks when there is a tie. For example: ID Score Rank 2 23 1 4 17 2 1 17 2 5 10 4 3 2 5 Each time a user's score is updated, The rank for the entire table must also be updated, so after a score update, the following query is run: SET @rank=0; UPDATE users SET rank= @rank:= (@rank+1) ORDER BY score DESC; But this doesn't support ties, or skipping rank numbers after ties, for that matter. I want to achieve this re-ranking in as few queries as possible and with no joins (as they seem rather time consuming)

Imagine we have the Django ORM model Meetup with the following definition: class Meetup(models.Model): language = models.CharField() speaker = models.CharField() date = models.DateField(auto_now=True) I'd like to use a single query to fetch the language, speaker and date for the latest event for each language. >>> Meetup.objects.create(language='python', speaker='mike') <Meetup: Meetup object> >>> Meetup.objects.create(language='python', speaker='ryan') <Meetup: Meetup object> >>> Meetup.objects.create(language='node', speaker='noah') <Meetup: Meetup object> >>> Meetup.objects.create(language=