range

问题 I found a script online that takes the current sheet, copies it to a temporary new spreadsheet, converts it to PDF and emails it. I was able to get it working but trying to set it up so that it only sends a certain range. Tried to play with it a bit but I am not a good coder by any stretch. Alternatively I'd be interested also in figuring out how to get it to fit to 1 page PDF in landscape, convert without gridlines (my online research shows this ins't possible?) or even send as XLS. //

问题 I want to use a switch statement to check a range of numbers I have found a few places saying something like case 1...5 or case (score >= 120) && (score <=125) would work but I just somehow keep on getting errors. What I want is if the number is between 1600-1699 then do something. I can do if statements but figured it's time to start using switch if possible. 回答1: On the JVM level switch statement is fundamentally different from if statements. Switch is about compile time constants that have

问题 I have a list : L = ['a', 'b'] I need to create a new list by concatenating an original list which range goes from 1 to k . Example: k = 4 L1 = ['a1','b1', 'a2','b2','a3','b3','a4','b4'] I try: l1 = L * k print l1 #['a', 'b', 'a', 'b', 'a', 'b', 'a', 'b'] l = [ [x] * 2 for x in range(1, k + 1) ] print l #[[1, 1], [2, 2], [3, 3], [4, 4]] l2 = [item for sublist in l for item in sublist] print l2 #[1, 1, 2, 2, 3, 3, 4, 4] print zip(l1,l2) #[('a', 1), ('b', 1), ('a', 2), ('b', 2), ('a', 3), ('b',

问题 given a Math.random() function which returns a number between [0,1) and min max values to specify the range, how can we generate numbers for the following cases: Case we want integer : A: (min,max) ? B: [min,max) return Math.floor(Math.random() * (max - min)) + min; C: (min,max] ? D: [min,max] return Math.floor(Math.random() * (max - min + 1)) + min; Case we want float : A: (min,max) ? B: [min,max) return Math.random() * (max - min) + min; C: (min,max] ? D: [min,max] ? 回答1: Integers Your

问题 I'm having a serious problem with MySQL (innoDB) 5.0. A very simple SQL query is executed with a very unexpected query plan. The query: SELECT SQL_NO_CACHE mbCategory.* FROM MBCategory mbCategory INNER JOIN ResourcePermission as rp ON rp.primKey = mbCategory.categoryId where mbCategory.groupId = 12345 AND mbCategory.parentCategoryId = 0 limit 20; MBCategory - contains 216583 rows ResourcePermission - contains 3098354 rows. In MBCategory I've multiple indexes (columns order as in index):

问题 I've got this block of code: date_counter = Time.mktime(2011,01,01,00,00,00,"+05:00") @weeks = Array.new (date_counter..Time.now).step(1.week) do |week| logger.debug "WEEK: " + week.inspect @weeks << week end Technically, the code works, outputting: Sat Jan 01 00:00:00 -0500 2011 Sat Jan 08 00:00:00 -0500 2011 Sat Jan 15 00:00:00 -0500 2011 etc. But the execution time is complete rubbish! It takes approximately four seconds to compute each week. Is there some grotesque inefficiency that I'm

问题 In PostgreSQL, how do you combine an exclusion constraint on a range column with a unique constraint on other, scalar columns. Or to put it another way, how do I ensure that the range overlap check is only done in combination with a unique check on some other columns? For example, say I have: CREATE TABLE reservation ( restaurant_id int, time_range tsrange ); I want to make sure that for each restaurant_id , there are no overlapping time_range s. I know that I can create an exclusive range

问题 I have two sets of ranges. Each range is a pair of integers (start and end) representing some sub-range of a single larger range. The two sets of ranges are in a structure similar to this (of course the ...s would be replaced with actual numbers). $a_ranges = { a_1 => { start => ..., end => ..., }, a_2 => { start => ..., end => ..., }, a_3 => { start => ..., end => ..., }, # and so on }; $b_ranges = { b_1 => { start => ..., end => ..., }, b_2 => { start => ..., end => ..., }, b_3 => { start =

问题 I need a regular expression that should validate decimal point as well as range. Totally 3 number should be present including dot and the value must be greater than 0.0. That means the valid range is from 0.1 to 7.0. I used the following regex: ^\\d{1,1}(\\.\\d{1,2})?$ It works fine except for the range validation. What do I need to change? 回答1: Regexes are notoriously bad at validating number ranges. But it's possible. You have to break down the number range into the expected textual

问题 Given an array of integers, what is the simplest way to iterate over it and figure out all the ranges it covers? for example, for an array such as: $numbers = array(1,3,4,5,6,8,11,12,14,15,16); The ranges would be: 1,3-6,8,11-12,14-16 回答1: If the array is sorted in ascending order, then the problem is easy. Define a Range structure or class, which has a beginning and an end. Then go through the array. If the current element is one more than the previous, update Range.end , otherwise create a