range

问题 PROBLEM let x = (0..<10).splitEvery( 3 ) XCTAssertEqual( x, [(0...2),(3...5),(6...8),(9)], "implementation broken" ) COMMENTS I am running into problems calculating number of elements in the Range, etc... extension Range { func splitEvery( nInEach: Int ) -> [Range] { let n = self.endIndex - self.startIndex // ERROR - cannot invoke '-' with an argument list of type (T,T) } } 回答1: The values in a range are of ForwardIndexType , so you can only advance() them, or compute the distance() , but the

问题 What is the best way in Python to determine what values in two ranges overlap? For example: x = range(1,10) y = range(8,20) (The answer I am looking for would be the integers 8 and 9.) Given a range, x, what is the best way to iterate through another range, y and output all values that are shared by both ranges? Thanks in advance for the help. EDIT: As a follow-up, I realized that I also need to know if x does or does not overlap y. I am looking for a way to iterate through a list of ranges

问题 I am working with the Amazon Mechanical Turk API and it will only allow me to use regular expressions to filter a field of data. I would like to input an integer range to a function, such as 256-311 or 45-1233, and return a regex that would match only that range. A regex matching 256-321 would be: \b((25[6-9])|(2[6-9][0-9])|(3[0-1][0-9])|(32[0-1]))\b That part is fairly easy, but I am having trouble with the loop to create this regex. I am trying to build a function defined like this:

问题 I'm playing around with the HTTP range header (specs). From what I understand I can set byte ranges of files ala 0-199/2000 200-499/2000 500-799/2000 etc Question: Say I only want to access certain ranges of a file, would it be possible to specify these ranges and then work with the "incomplete" data I received? I'm playing around with filtering a large log file, so I'm curious if something like this would work. Thanks for inputs! 回答1: You are right the link which you posted in the comment

问题 My "Chart data range" is ='sheet1'!$A$1:$Z$10 . I'd like to make a VBA macro (or if anybody knows a formula I can use, but I couldn't figure one out) to increase the ending column of the range for chart1 by 1 every time I run the macro. So essentially: chart1.endCol = chart1.endCol + 1 What is the syntax for this using ActiveChart or is there a better way? 回答1: Assuming that you want to expand the range (by adding one extra column) to add one more observation for each series in you diagram

问题 I'm trying to implement a page where there are 4 jQuery-UI sliders, and I want to make it so the combined total of all 4 sliders will never go over 400. I don't mind which way this is implemented, it can be from a 0 start, and as soon as you change 1 slider, the remaining available total decreases or setting a slider past the maximum, decreases the values on the other sliders. P.S. The sliders go in increments of 10. All ideas & suggestions are welcome, and I've set up a jsFiddle if you'd

问题 Random class has a method to generate random int in a given range. For example: Random r = new Random(); int x = r.nextInt(100); This would generate an int number more or equal to 0 and less than 100. I'd like to do exactly the same with long number. long y = magicRandomLongGenerator(100); Random class has only nextLong(), but it doesn't allow to set range. 回答1: Starting from Java 7 (or Android API Level 21 = 5.0+) you could directly use ThreadLocalRandom.current().nextLong(n) (for 0 ≤ x < n)

问题 I need to populate a table that will store the date ranges between 2 given dates: 09/01/11 - 10/10/11 So in this case the table would start from 09/01/11 and store each day till it got to 10/10/11 I was wondering if there was a slick way of doing this in SQL Server - I am currently using SQL Server 2008. Thanks 回答1: Easy on SQL 2005+; easier if you have a numbers or tally table. I faked it below: DECLARE @StartDate DATE = '20110901' , @EndDate DATE = '20111001' SELECT DATEADD(DAY, nbr - 1,

问题 I am having difficulties print the length of the longest string in the list which is kevin07 which should equal to 7. My current solution prints all 3 item lengths. names = ['ron', 'james', 'kevin07'] best = 0 for index in range(len(names)): if len(names[index]) > best: best = len(names[index]) print(best) 回答1: names = ['ron', 'james', 'kevin07'] best = 0 for index in range(len(names)): if len(names[index]) > best: best = len(names[index]) print(best) Output: 7 Explanation: You need to move

问题 I am having difficulties print the length of the longest string in the list which is kevin07 which should equal to 7. My current solution prints all 3 item lengths. names = ['ron', 'james', 'kevin07'] best = 0 for index in range(len(names)): if len(names[index]) > best: best = len(names[index]) print(best) 回答1: names = ['ron', 'james', 'kevin07'] best = 0 for index in range(len(names)): if len(names[index]) > best: best = len(names[index]) print(best) Output: 7 Explanation: You need to move