range

问题 I need to select range of integer in MySQL. Something like this SELECT RANGE(10,20) AS range; returns 10, 11, 12, 13, 14, ..., 20 Why? I would like to select random phone number from range which is not yet registered. This is idea. SELECT RANGE(100000,999999) AS range FROM phone WHERE phoneNum <> range LIMIT FLOOR(100000 + RAND()*(899999); 回答1: Problems with your query: You can't use range in the WHERE clause. It is an alias and will only be defined after the WHERE clause is performed. Even

问题 Let's say you have a set of ranges: 0 - 100: 'a' 0 - 75: 'b' 95 - 150: 'c' 120 - 130: 'd' Obviously, these ranges overlap at certain points. How would you dissect these ranges to produce a list of non-overlapping ranges, while retaining information associated with their original range (in this case, the letter after the range)? For example, the results of the above after running the algorithm would be: 0 - 75: 'a', 'b' 76 - 94: 'a' 95 - 100: 'a', 'c' 101 - 119: 'c' 120 - 130: 'c', 'd' 131 -

问题 Recently I've resumed Fortran and probably there's something I'm missing but this behaviour looks very odd When I run the following code (compiled with ifort), that just declares an array and sets one of his elements PROGRAM sol_kernel2 IMPLICIT NONE INTEGER, PARAMETER :: jpi=5,jpj=5 REAL, DIMENSION(jpi,jpj) :: sshn PRINT *,jpi,jpj sshn(10,10) = 150.0 PRINT *,sshn(10,10) END PROGRAM sol_kernel2 I expect to get an ERROR Statement, such as SEGMENTATION FAULT, since I'm trying to set the sshn

问题 Recently I've resumed Fortran and probably there's something I'm missing but this behaviour looks very odd When I run the following code (compiled with ifort), that just declares an array and sets one of his elements PROGRAM sol_kernel2 IMPLICIT NONE INTEGER, PARAMETER :: jpi=5,jpj=5 REAL, DIMENSION(jpi,jpj) :: sshn PRINT *,jpi,jpj sshn(10,10) = 150.0 PRINT *,sshn(10,10) END PROGRAM sol_kernel2 I expect to get an ERROR Statement, such as SEGMENTATION FAULT, since I'm trying to set the sshn

问题 Recently I've resumed Fortran and probably there's something I'm missing but this behaviour looks very odd When I run the following code (compiled with ifort), that just declares an array and sets one of his elements PROGRAM sol_kernel2 IMPLICIT NONE INTEGER, PARAMETER :: jpi=5,jpj=5 REAL, DIMENSION(jpi,jpj) :: sshn PRINT *,jpi,jpj sshn(10,10) = 150.0 PRINT *,sshn(10,10) END PROGRAM sol_kernel2 I expect to get an ERROR Statement, such as SEGMENTATION FAULT, since I'm trying to set the sshn

问题 This question already has answers here : Efficient way to filter one data frame by ranges in another (3 answers) Closed 2 years ago . I want to get a list of values that fall in between multiple ranges. library(data.table) values <- data.table(value = c(1:100)) range <- data.table(start = c(6, 29, 87), end = c(10, 35, 92)) I need the results to include only the values that fall in between those ranges: results <- c(6, 7, 8, 9, 10, 29, 30, 31, 32, 33, 34, 35, 87, 88, 89, 90, 91, 92) I am

问题 This question already has answers here : Efficient way to filter one data frame by ranges in another (3 answers) Closed 2 years ago . I want to get a list of values that fall in between multiple ranges. library(data.table) values <- data.table(value = c(1:100)) range <- data.table(start = c(6, 29, 87), end = c(10, 35, 92)) I need the results to include only the values that fall in between those ranges: results <- c(6, 7, 8, 9, 10, 29, 30, 31, 32, 33, 34, 35, 87, 88, 89, 90, 91, 92) I am

问题 In Python 2.7.1, I import the random module. when I call randint() however, I get the error: ValueError: empty range for randrange() (1,1, 0) This error is caused by an error in the random.py module itself. I don't know how to fix it, not does reinstalling python help. I can't change versions. can someone please give me code for a working module or tell me what to do? 回答1: You called randint like this: randint(1,0) That tells randint to return a value starting as 1 and ending at 0. The range

问题 Playing with the NumPy concatenation and range building object r_ I stumbled over the following behavior: apparently, a complex step no matter whether real, imaginary or proper complex has its absolute value taken as the number of steps in a linspace like way. >>> import numpy as np >>> >>> np.r_[0:12:4] # start : stop : step array([0, 4, 8]) # that's expected >>> np.r_[0:12:4j] # start : stop : imaginary step array([ 0., 4., 8., 12.]) # that's in the docs >>> np.r_[0:12:4+0j] # real step of

问题 I want to apply goal seek across several rows when there is a change to any cell in the work sheet. I want to apply this from row 7 to row 11. The first problem I have is that excel is crashing each time I run this. I am just starting to learn VBA so any help is much apreciated. Thank you! My code is below: Option Explicit Private Sub Worksheet_Calculate() CheckGoalSeek End Sub Private Sub CheckGoalSeek() Range("T7").GoalSeek Goal:=0, ChangingCell:=Range("V7") End Sub 回答1: You appear to be