range

问题 I'm relatively new to BASH and I'm trying to use awk to filter out column 1 data based on the 4th column of a text file. If the 4th column of data matches the range of x, then it'll output column 1 data. "x" is suppose to be a range of numbers 1-10 (1,2,3..10). awk -F: '{ if($4=="x") print $1}' filename.txt filename.txt sample1 0 0 4 sample2 0 0 10 sample3 0 0 15 sample4 0 0 20 Actual use: awk -F: '{ if($4=="1-10") print $1}' sample.txt output = sample1, sample2, sample3, sample4 It should be

问题 I'm relatively new to BASH and I'm trying to use awk to filter out column 1 data based on the 4th column of a text file. If the 4th column of data matches the range of x, then it'll output column 1 data. "x" is suppose to be a range of numbers 1-10 (1,2,3..10). awk -F: '{ if($4=="x") print $1}' filename.txt filename.txt sample1 0 0 4 sample2 0 0 10 sample3 0 0 15 sample4 0 0 20 Actual use: awk -F: '{ if($4=="1-10") print $1}' sample.txt output = sample1, sample2, sample3, sample4 It should be

问题 I'm relatively new to BASH and I'm trying to use awk to filter out column 1 data based on the 4th column of a text file. If the 4th column of data matches the range of x, then it'll output column 1 data. "x" is suppose to be a range of numbers 1-10 (1,2,3..10). awk -F: '{ if($4=="x") print $1}' filename.txt filename.txt sample1 0 0 4 sample2 0 0 10 sample3 0 0 15 sample4 0 0 20 Actual use: awk -F: '{ if($4=="1-10") print $1}' sample.txt output = sample1, sample2, sample3, sample4 It should be

问题 My Problem Consider a set of data with two intervals. For instance, consider a student schedule of classes. Each record has a begin and end date, and each class has a period start time and a period end time. But this schedule is not 'normalized' in the sense that some records overlap. So if you search for records encompassing a given date and period for a student, you might get multiple matches. Here's a contrived example. I represent the dates as integers to simplify the problem: declare

问题 I have a date range like date from=2011-10-14 & date to=2011-10-20 if I have another date ranges like - 2011-10-11 - 2011-10-15 - 2011-10-11 - 2011-10-21 - 2011-10-15 - 2011-10-21 - 2011-10-15 - 2011-10-19 - 2011-10-21 - 2011-10-26 I want sql query which shows only the date range whose dates lies in between above (2011-10-14 & date to=2011-10-20) date range. Here only 2011-10-21 - 2011-10-26 does not lies in date from=2011-10-14 & date to=2011-10-20 Result must show - 2011-10-11 - 2011-10-15

问题 After spending a week checking and fixing my program for memory leaks through FastMM4, I finally test ran my program on a different PC. Now, I am getting "Range Check Error." I have spent hours researching online about this, but none of them seem to give me what I am looking for. My program was complied with the Runtime Error option Range Check. So, I know that's why I am getting the error, but I needed to know exactly why the error is raised. The program was compiled on XP with Delphi 7.0.

问题 Is there a way to generate time range in pandas similar to date_range? something like: pandas.time_range("11:00", "21:30", freq="30min") 回答1: A time range doesn't exist as a standalone index type. Generate using a single date In [1]: pandas.date_range("11:00", "21:30", freq="30min") Out[1]: <class 'pandas.tseries.index.DatetimeIndex'> [2013-07-14 11:00:00, ..., 2013-07-14 21:30:00] Length: 22, Freq: 30T, Timezone: None The time objects In [2]: pandas.date_range("11:00", "21:30", freq="30min")

问题 I am learning python and was looking at this problem: Python - Prime Number exercise Here are my questions: When n=2, the range will be (2,n), in the other words the range is between 2 and 2-1=1. for x in range(2, n): if n % x == 0: print("{} equals {} x {}".format(n, x, n // x)) return False else: print(n, "is a prime number") return True a. Will it be 2%2? b. If the number is even, it will print A equals B x C will the loop break once the condition is true or it will finish the loop? c. is

问题 I'm comparing 2 files with an initial identifier column, start value, and end value. The second file contains corresponding identifiers and another value column. Ex. File 1: A 200 900 A 1000 1200 B 100 700 B 900 1000 File 2: A 103 A 200 A 250 B 50 B 100 B 150 I would like to find all values from the second file that are contained within the ranges found in the first file so that my output would look like: A 200 A 250 B 100 B 150 For now I have created a dictionary from the first file with a

问题 I'm comparing 2 files with an initial identifier column, start value, and end value. The second file contains corresponding identifiers and another value column. Ex. File 1: A 200 900 A 1000 1200 B 100 700 B 900 1000 File 2: A 103 A 200 A 250 B 50 B 100 B 150 I would like to find all values from the second file that are contained within the ranges found in the first file so that my output would look like: A 200 A 250 B 100 B 150 For now I have created a dictionary from the first file with a