range

Is it possible to show me a sample http session with range requests. I mean what would be the request and response headers? The following exchange is between Chrome and a static web server, retrieving an MP4 video. Initial request - for the video. Note the Accept-Ranges response header to indicate the server has range header support: GET /BigBuckBunny_320x180.mp4 Cache-Control: max-age=0 Connection: keep-alive Accept-Language: en-GB,en-US,en Host: localhost:8080 Range: Accept: text/html,application/xhtml+xml,application/xml,*/* User-Agent: Mozilla/5.0 (Windows NT 5.1) AppleWebKit/535.7 ...

Is there a range() equivalent for floats in Python? >>> range(0.5,5,1.5) [0, 1, 2, 3, 4] >>> range(0.5,5,0.5) Traceback (most recent call last): File "<pyshell#10>", line 1, in <module> range(0.5,5,0.5) ValueError: range() step argument must not be zero kichik I don't know a built-in function, but writing one like this shouldn't be too complicated. def frange(x, y, jump): while x < y: yield x x += jump As the comments mention, this could produce unpredictable results like: >>> list(frange(0, 100, 0.1))[-1] 99.9999999999986 To get the expected result, you can use one of the other answers in

Given two inclusive integer ranges [x1:x2] and [y1:y2], where x1 ≤ x2 and y1 ≤ y2, what is the most efficient way to test whether there is any overlap of the two ranges? A simple implementation is as follows: bool testOverlap(int x1, int x2, int y1, int y2) { return (x1 >= y1 && x1 <= y2) || (x2 >= y1 && x2 <= y2) || (y1 >= x1 && y1 <= x2) || (y2 >= x1 && y2 <= x2); } But I expect there are more efficient ways to compute this. What method would be the most efficient in terms of fewest operations. What does it mean for the ranges to overlap? It means there exists some number C which is in both

How can I set the y axis range of the second subplot to e.g. [0,1000] ? The FFT plot of my data (a column in a text file) results in a (inf.?) spike so that the actual data is not visible. pylab.ylim([0,1000]) has no effect, unfortunately. This is the whole script: # based on http://www.swharden.com/blog/2009-01-21-signal-filtering-with-python/ import numpy, scipy, pylab, random xs = [] rawsignal = [] with open("test.dat", 'r') as f: for line in f: if line[0] != '#' and len(line) > 0: xs.append( int( line.split()[0] ) ) rawsignal.append( int( line.split()[1] ) ) h, w = 3, 1 pylab.figure

As the title suggests, I am trying to figure out a way of generating random numbers using the new C++11 <random> library. I have tried it with this code: std::default_random_engine generator; std::uniform_real_distribution<double> uniform_distance(1, 10.001); The problem with the code I have is that every time I compile and run it, it always generates the same numbers. So my question is what other functions in the random library can accomplish this while being truly random? For my particular use case, I was trying to get a value within the range [1, 10] Bill Lynch Stephan T. Lavavej (stl) from

Suppose I have a std::vector (let's call it myVec ) of size N . What's the simplest way to construct a new vector consisting of a copy of elements X through Y, where 0 <= X <= Y <= N-1? For example, myVec [100000] through myVec [100999] in a vector of size 150000 . If this cannot be done efficiently with a vector, is there another STL datatype that I should use instead? vector<T>::const_iterator first = myVec.begin() + 100000; vector<T>::const_iterator last = myVec.begin() + 101000; vector<T> newVec(first, last); It's an O(N) operation to construct the new vector, but there isn't really a