ram

How does the internal implementation of memcpy work?

前提是你 提交于 2019-11-30 11:05:16
How does the standard C function 'memcpy' work? It has to copy a (large) chunk of RAM to another area in the RAM. Since I know you cannot move straight from RAM to RAM in assembly (with the mov instruction) so I am guessing it uses a CPU register as the intermediate memory when copying? But how does it copy? By blocks (how would it copy by blocks?), by individual bytes (char) or the largest data type they have (copy in long long double's - which is 12 bytes on my system). EDIT: Ok apparently you can move data from RAM to RAM directly , I am not an assembly expert and all I have learnt about

抽象工厂设计模式

不打扰是莪最后的温柔 提交于 2019-11-30 07:54:27
抽象工厂设计模式最大特点就是解耦。 //业务需求:生产不同内存条搭配Win7系统的电脑 //定义抽象工厂 public interface AbstastFactory { public Ram createRam(); public WinSystem createSys(); } //具体工厂实现 低端电脑配置 public class LowComputer implements AbstastFactory { @Override public Ram createRam() { return new Ram512(); } @Override public WinSystem createSys() { return new SystemWin7(); } } //具体工厂实现 高端电脑配置 public class NiceComputer implements AbstastFactory { @Override public Ram createRam() { return new Ram1G(); } @Override public WinSystem createSys() { return new SystemWin7(); } } //内存条接口 public interface Ram {} //512内存条实现类 public class Ram1G

Why is Pandas Concatenation (pandas.concat) so Memory Inefficient?

 ̄綄美尐妖づ 提交于 2019-11-30 06:24:24
I have about 30 GB of data (in a list of about 900 dataframes) that I am attempting to concatenate together. The machine I am working with is a moderately powerful Linux Box with about 256 GB of ram. However, when I try to concatenate my files I quickly run out of available ram. I have tried all sorts of workarounds to fix this (concatenating in smaller batches with for loops, etc.) but I still cannot get these to concatenate. Two questions spring to mind: Has anyone else dealt with this and found an effective workaround? I cannot use a straight append because I need the 'column merging' (for

Prevent RAM from paging to swap area (mlock)

China☆狼群 提交于 2019-11-30 05:22:07
问题 Is there a way to call the POSIX mlock function from Python? The effect of mlock is to disable swapping out certain objects. I know there are still other issues when it comes to securing cryptographic keys, I just want to know how to contain them in RAM. 回答1: For CPython, there is no good answer for this that doesn't involve writing a Python C extension, since mlock works on pages, not objects. Even if you used ctypes to retrieve the necessary addresses and mlock -ed them all through ctypes

R reading a huge csv

只愿长相守 提交于 2019-11-30 03:23:05
I have a huge csv file. Its size is around 9 gb. I have 16 gb of ram. I followed the advises from the page and implemented them below. If you get the error that R cannot allocate a vector of length x, close out of R and add the following line to the ``Target'' field: --max-vsize=500M Still I am getting the error and warnings below. How should I read the file of 9 gb into my R? I have R 64 bit 3.3.1 and I am running below command in the rstudio 0.99.903. I have windows server 2012 r2 standard, 64 bit os. > memory.limit() [1] 16383 > answer=read.csv("C:/Users/a-vs/results_20160291.csv") Error:

every()和some()用法区别

℡╲_俬逩灬. 提交于 2019-11-30 03:18:23
1.every()意思 总结:一假即假 ,而且只要有一个元素是假,其后面的元素将不再遍历。 2.some()用法 总结:一真即真 3.二者应用场景 var computers = [ { name: "mac", ram: 32 }, { name: "mac", ram: 8 }, { name: "IBM", ram: 16 }, { name: "IBM", ram: 64 } ]; var everyComputerCan; var someComputerCan; //判断每一个元素的ram是否都大于16 var everyBoolan = computers.every(function(item) { return item.ram > 16; }); //判断元素的ram是否都大于16 var someBoolean = computers.some(function(item) { return item.ram > 16; }); console.log(everyBoolan); //结果:false console.log(someBoolean);//结果: true    来源: https://www.cnblogs.com/yxkNotes/p/11550093.html

Read file in chunks - RAM-usage, read Strings from binary files

£可爱£侵袭症+ 提交于 2019-11-30 02:55:05
问题 i'd like to understand the difference in RAM-usage of this methods when reading a large file in python. Version 1, found here on stackoverflow: def read_in_chunks(file_object, chunk_size=1024): while True: data = file_object.read(chunk_size) if not data: break yield data f = open(file, 'rb') for piece in read_in_chunks(f): process_data(piece) f.close() Version 2, i used this before i found the code above: f = open(file, 'rb') while True: piece = f.read(1024) process_data(piece) f.close() The

EOS 数据库RAM使用量的计算

那年仲夏 提交于 2019-11-30 00:52:01
如果你是EOS的合约开发者,相信你很有可能跟我一样对内存(RAM)的使用量感到不解。在使用 multi_index 进行数据存储时,明明只存了一点数据,但区块链浏览器中显示的内存占用量却上升了不少。在这篇文章中,我们就来对内存用量一探究竟,精确计算出存储数据所需要的RAM。我们会首先编写一个简单的合约,用以向 multi_index 内存入数据。部署合约后,每次调用接口前后都查询一下RAM用量,并予以记录。 合约编写 新建合约目录: $ mkdir addrow $ cd addrow $ touch addrow.cpp 这里是一份简单的合约,用户每次调用 add 时,数据库中都会多存一行记录 #include <eosiolib/eosio.hpp> class [[eosio::contract]] addrow : public eosio::contract { public: addrow( eosio::name receiver, eosio::name code, eosio::datastream<const char*> ds ) : eosio::contract(receiver, code, ds), _students(receiver, code.value) {} //添加学生 [[eosio::action]] void add(eosio:

How to reduce Spring memory footprint

烂漫一生 提交于 2019-11-30 00:39:14
I would like to ask you HOW (or IF) is possible to reduce Spring framework's RAM footprint. I created a simple helloworld app for demonstrating the issue. There are only two classes and context.xml file: Main - class with main method Test - class used for simulating some "work" (printig Hello in endless loop) context.xml contains only this: <context:component-scan base-package="mypackage" /> Test class contains only metod called init , called after construction: @Component public class Test{ @PostConstruct public void init() { Thread t = new Thread(new Runnable() { @Override public void run()

0016__FLASH与ROM关系

爷,独闯天下 提交于 2019-11-29 18:32:54
ROM和RAM指的都是 半导体存储器 ,ROM是Read Only Memory的缩写,RAM是Random Access Memory的缩写。ROM在系统停止供电的时候仍然可以保持数据,而RAM通常都是在掉电之后就丢失数据,典型的RAM就是计算机的内存。 FLASH存储器又称闪存,它结合了ROM和RAM的长处,不仅具备电子可擦除可编程(EEPROM)的性能,还不会断电丢失数据同时可以快速读取数据(NVRAM的优势),U盘和MP3里用的就是这种存储器。在过去的20年里,嵌入式系统一直使用ROM(EPROM)作为它们的存储设备,然而近年来Flash全面代替了ROM(EPROM)在嵌入式系统中的地位,用作存储Bootloader以及 操作系统 或者程序代码或者直接当硬盘使用(U盘)。 来源: https://blog.csdn.net/tang935892307/article/details/100881403