r-markdown

问题 i am stuck with this problem in R code please help me I am trying to create a miodin project and then read a file to dataframe so when i insert the file to the project folder it shows the following error arguments imply differing number of rows: 15, 12 Here is my code library(miodin) mp <- MiodinProject( name = "MyProject", author = "lee", path ="." ) countTable <- read.table(paste0("data/",'seq.txt'), header = TRUE, sep = '\t', stringsAsFactors = FALSE ) sampleTable <- data.frame( SampleName

问题 I want to use kable inside a for loop to generate a lot of tables in a HTML rmarkdown. I was looking for solutions and most of them are solved using the wrapper print around kable code. But when I want to generate html table outputs with kable_styling, this solution didn't work! For example: table <- tibble(a = c(1:10), b = letters[1:10]) for(each in 1:2) { print(table %>% kable()) cat("<br>") } This generate two simple tables. But when I try: table <- tibble(a = c(1:10), b = letters[1:10])

问题 I'm experiencing some behavior where knitr cuts off part of a ggplot2 image when i used coord_fixed(ratio = 1) . mwe.Rmd --- title: "mwe" output: pdf_document --- ```{r} library(ggplot2) data <- list( x1 = 0:6, y1 = 0, x2 = rep(0:6, 2), y2 = rep(c(0, 1), each = 7) * -1, labels = paste("Label", 1:7) ) g <- ggplot() + geom_text(aes(0:6, 0.75), label = data$labels) g_unfixed_1 <- g + geom_raster(aes(data$x1, data$y1)) g_fixed_1 <- g_unfixed_1 + coord_fixed(ratio = 1) g_unfixed_2 <- g + geom

问题 I am trying to add page numbers to my beamer presentation. I am using the following code in Rmarkdown (see below). The problem is that the page numbers are cut off. I have tried using geometry to adjust the dimensions but i keep getting an error message that they are incompatible. Does anyone have any ideas? I have spent hours searching for a solution. --- title: my title author: "me" date: "May 05, 2016" output: beamer_presentation header-includes: - \usepackage{fancyhdr} - \pagestyle{fancy}

问题 I want to use Shiny Action buttons in rmarkdown file. Can you help please to rewrite the following code (from https://shiny.rstudio.com/articles/action-buttons.html) into RMarkdown? # Codes from https://shiny.rstudio.com/articles/action-buttons.html library(shiny) ui <- fluidPage( # Pattern 1 - Command tags$head(tags$script(src = "message-handler.js")), actionButton("do", "Click Me"), hr(), # Pattern 2 - Delay reactions actionButton("go", "Go"), numericInput("n", "n", 50), plotOutput("plot2")

问题 Every time I add align=TRUE the document won't knit. I would like to align each column's coefficients so that their decimals are directly above/below each other. Here is my "chunk code" ```{r, results="asis", echo="FALSE", eval="TRUE"} library(stargazer) stargazer(model1, model2, model3, type = "latex", title = "Country Deaths from Political Violence in 1975", dep.var.labels.include = FALSE, dep.var.caption = "Deaths", digits = 1, header = FALSE, covariate.labels = c("Intercept", "Sanctions",

问题 An answer by Nicholas Hamilton specifies how to use colour text in PDF and HTML output from Markdown using an R expression. If I create an RMarkdown document, I get no joy, Warning message is Error in colFmt("MY RED TEXT", "red") : object 'opts_knit' not found Calls: ... inline_exec -> hook_eval -> withVisible -> eval -> eval -> colFmt Execution halted What am I missing? Copy and paste of RMarkdown below: --- title: "test colour" author: "mbn" output: html_document --- ```{r setup, include

问题 I am creating presentation using R Markdown with PDF (Beamer) as output. I am using library kableExtra for some formatting. The following code gives me the expected result library(knitr) # library(kableExtra) # create data frame df <- data.frame(mean = c(1,2,3), beta = c(5,6,7)) # print data frame to slide knitr::kable(df, col.names = c("mean", "$\\beta_t$")) However, when I use library(kableExtra) as in code below, the printed PDF show $\beta_t$ instead of the Greek letter beta. library

问题 Suppose I print a data frame called summary_table as follows: summary_table = data.frame(a=c(1,2,3), b=c(11,12,13),c=c(21,22,23),d=c(31,32,33),e=c(41,42,43),f=c(51,52,53),g=c(61,62,63),h=c(71,72,73),i=c(81,82,83),j=c(91,92,93),k=c(101,102,103),l=c(111,112,113)) print(xtable(summary_table, align=rep("r",13), caption="A summary of stuff."), table.placement="H") Now suppose summary_table has only three rows, but twelve columns. I'd like to flip (transpose) the table so that the columns become

问题 Suppose I print a data frame called summary_table as follows: summary_table = data.frame(a=c(1,2,3), b=c(11,12,13),c=c(21,22,23),d=c(31,32,33),e=c(41,42,43),f=c(51,52,53),g=c(61,62,63),h=c(71,72,73),i=c(81,82,83),j=c(91,92,93),k=c(101,102,103),l=c(111,112,113)) print(xtable(summary_table, align=rep("r",13), caption="A summary of stuff."), table.placement="H") Now suppose summary_table has only three rows, but twelve columns. I'd like to flip (transpose) the table so that the columns become